Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 30, Number 2, April 2025
Page(s) 111 - 117
DOI https://doi.org/10.1051/wujns/2025302111
Published online 16 May 2025

© Wuhan University 2025

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

In this article, we study the following system of semilinear parabolic equations

u t = Δ u + u p 1 e q 1 v ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation(1)

v t = Δ v + u p 2 e q 2 v ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation(2)

u ( x , t ) = v ( x , t ) = 0 ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation(3)

u ( x , 0 ) = ρ θ ( x ) ,   u ( x , 0 ) = ρ ϑ ( x ) ,   x Ω   , Mathematical equation(4)

where ΩMathematical equation is a bounded domain in RNMathematical equation with smooth boundary Ω ,p1,p2,q1,q2>0,ρ>0Mathematical equation is a parameter, θ(x),ϑ(x)Mathematical equation are nonnegative continuous functions in Ω¯.Mathematical equation

Denote

M ( θ ) = m a x x Ω ¯ θ ( x ) , M ( ϑ ) = m a x x Ω ¯ ϑ ( x ) , Mathematical equation

We denote by T(ρ)Mathematical equation the maximal existence time of a classical solution (u,v)Mathematical equation of Equations (1)-(4), that is

T ( ρ ) = s u p { T > 0 , s u p ( u ( , t ) + v ( , t ) ) < } , Mathematical equation

and we call T(ρ)Mathematical equation is the life span of (u,v),Mathematical equation if T(ρ)<,Mathematical equation then we have

l i m t T ( ρ ) s u p ( s u p u ( , t ) + v ( , t ) ) = . Mathematical equation

Equations (1)-(4) can be used to describe the processes of diffusion of heat and burning in two component continuous media conductivity, volume energy release, and nucleate blow up.

In recent decades, there are many research achievements on the life span of solutions determined by initial value has been considered, see Refs. [1-9]. Sato[1] studied the following system of semi-linear equations

u t = Δ u + v p ,   ( x , t ) Ω × ( 0 , T ) , v t = Δ v + u q ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation

u ( x , t ) = v ( x , t ) = 0 ,   ( x , t ) Ω × ( 0 , T ) , u ( x , 0 ) = ρ φ ( x ) , u ( x , 0 ) = ρ ψ ( x ) , x Ω   , Mathematical equation

and by using super-subsolution method and Kaplan method, he obtained expression of the span of solution when p,q1Mathematical equation. Xu et al[2] studied the following system of coupled parabolic equations with large initial values

u t = Δ u + u p v q ,   ( x , t ) Ω × ( 0 , T ) , v t = Δ v + u α v β ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation

then by constructing and solving a new ordinary parabolic equation (OPE) system, they had the accurate life span of solutions (blow up time) of the expression determined with the initial value.

Zhou et al[3] and Xiao[4] considered the following nonlinear parabolic system with large initial values

u t = Δ u + e p v ,   ( x , t ) Ω × ( 0 , T ) , v t = Δ v + e q u ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation

and they obtained the life span (or blow up time) and maximal existence time of blow up solutions. Zhou[5] investigated the upper and lower bound for the life span of solutions for the following parabolic system with large initial values,

u t = Δ u + e m u + p v ,   ( x , t ) Ω × ( 0 , T ) , v t = Δ v + e q u + n v ,   ( x , t ) Ω × ( 0 , T ) , Mathematical equation

and he obtained the upper and lower bound for the life span of solutions.

Other relevant achievements on the estimation of upper and lower bounds for blow up time see Refs. [6-9]. Current research mainly focuses on the nonlinear term being in the form of polynomial or exponential functions. Then, can we obtain results similar to those in Refs. [2,5] when the nonlinear term is cross coupled with power and exponential functions? This article studies the upper and lower bounds of the life span of equations (1)-(4), cleverly resolving the difficulty of integration when multiplying power and exponential functions. The conclusion can better describe the situation where the reaction rate of the medium is inconsistent during the combustion and diffusion process of porous media flow and two com- ponent continuous media.

The arrangement of this article is as follows: in Section 1, two important theorems of this article are presented. In Section 2, in order to prove the theorems, a system of ordinary differential equations (ODE) is constructed and solved. In Section 3, the main theorems are proved in detail.

1 Main Results

In this section, we state the following main results.

Theorem 1   Let q1<q2,p1<min{1,1+p2},Mathematical equation suppose that θ,ϑC(Ω¯)Mathematical equation satisfy θ,ϑ0Mathematical equation in Ω ,Mathematical equationθ=ϑ=0Mathematical equation on ΩMathematical equation.

(i) If θ0,Mathematical equation then we have

l i m   i n f ρ ( ρ M ( θ ) ) q 2 ( 1 - p 1 ) + p 2 q 1 q 1 - q 2 T ( ρ ) = ( 1 + p 2 - p 1 q 1 - q 2 ) q 1 q 1 - q 2 1 d z z p 1 ( z 1 + p 2 - p 1 - 1 ) , Mathematical equation

(ii) If θ=0,Mathematical equation then we have

l i m   i n f ρ [ e ρ M ( ϑ ) ] p 2 ( q 1 - q 2 ) 1 + p 2 - p 1 T ( ρ ) = ( q 1 - q 2 1 + p 2 - p 1 ) p 2 1 + p 2 - p 1 1 d w e q 2 ρ M ( ϑ ) w q 2 ρ M ( ϑ ) [ e ( q 1 - q 2 ) ρ M ( ϑ ) w e ( q 1 - q 2 ) ρ M ( ϑ ) - 1 ] p 2 1 + p 2 - p 1 . Mathematical equation

Theorem 2   Let q1<q2,p1<min{p2,p2-1},Mathematical equation suppose that θ,ϑC(Ω¯)Mathematical equation satisfy θ,ϑ0Mathematical equation in Ω ,Mathematical equationθ=ϑ=0Mathematical equation on ΩMathematical equation.

(i) If θ0,Mathematical equation then we have

l i m   s u p ρ [ ρ α ( R ) ] T ( ρ ) = 1 d z q 1 ( 1 - ε ) 2 2 { z 2 + 2 [ ρ α ( R ) ] p 1 - 2 e ρ β ( R ) ( 1 - ε ) q 1 ( 1 - ε ) 2 - 1 } , Mathematical equation

(ii) If θ=0,Mathematical equation then we have

l i m   s u p ρ [ ρ β ( R ) ] T ( ρ ) = 1 d w p 2 q 1 ( 1 - ε ) [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] . Mathematical equation

2 Blow up Time of ODE System

In this section, we consider the ODE system as follows:

z t = z p 1 e q 1 w , t > 0 , Mathematical equation(5)

w t = z p 2 e q 2 w , t > 0 , Mathematical equation(6)

z ( 0 ) = α , w ( 0 ) = β , Mathematical equation(7)

where α,βMathematical equation are two nonnegative numbers.

Lemma 1   If the equations (5)-(7) have solutions for the following form,

z ( t ; α , β ) = F - 1 ( F ( α ; α , β ) - t ; α , β ) , w ( t ; α , β ) = G - 1 ( G ( β ; α , β ) - t ; α , β ) , Mathematical equation

where

F ( α ; α , β ) = α d ξ ξ p 1 { q 1 - q 2 1 + p 2 - p 1 [ ξ 1 + p 2 - p 1 - α 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) β } q 1 q 1 - q 2 , G ( β ; α , β ) = β d η e q 2 η { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) η - e ( q 1 - q 2 ) β ] + α 1 + p 2 - p 1 } p 2 1 + p 2 - p 1 , Mathematical equation

F - 1 ( F ( α ; α , β ) - t ; α , β ) , Mathematical equation G - 1 ( G ( β ; α , β ) - t ; α , β ) Mathematical equation represent the inverse functions of F(α;α,β)Mathematical equation and G(β;α,β)Mathematical equation with respect to the first variable, respectively. Then the life span of (z(t),w(t))Mathematical equation is T(α,β)=F(α;α,β)=G(β;α,β).Mathematical equation

Proof   Let the first equations of (5)-(7) divide the second one, then it gives zp2-p1zt=e(q1-q2)wwt,Mathematical equation integrating the equation over (0,t)Mathematical equation above, we can obtain

z 1 + p 2 - p 1 - α 1 + p 2 - p 1 1 + p 2 - p 1 = e ( q 1 - q 2 ) w - e ( q 1 - q 2 ) β q 1 - q 2 . Mathematical equation

Hence we have

z = { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) w - e ( q 1 - q 2 ) β ] + α 1 + p 2 - p 1 } 1 1 + p 2 - p 1 , w = 1 q 1 - q 2 l n { q 1 - q 2 1 + p 2 - p [ z 1 + p 2 - p 1 - α 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) β } . Mathematical equation

Substituting those equalities in the equations (5)-(7), we set that (z(t),w(t))Mathematical equation satisfies the initial value problem

z t = z p 1 { q 1 - q 2 1 + p 2 - p 1 [ z 1 + p 2 - p 1 - α 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) β } q 1 q 1 - q 2 , t > 0 , z ( 0 ) = α , w t = e q 2 w { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) w - e ( q 1 - q 2 ) β ] + α 1 + p 2 - p 1 } p 2 1 + p 2 - p 1 , t > 0 , w ( 0 ) = β . Mathematical equation

Integrating the first equation above over (0,t)Mathematical equation, we can show

F ( α ; α , β ) - F ( z ( t ) ; α , β ) = t . Mathematical equation

Hence we obtain

z ( t ; α , β ) = F - 1 ( F ( α ; α , β ) - t ; α , β ) . Mathematical equation

This implies that the life span Tα,β*Mathematical equation of (z,w) is

T α , β * = m i n { F ( α ; α , β ) , G ( β ; α , β ) } . Mathematical equation

By using the change of variables

η = 1 q 1 - q 2 l n { q 1 - q 2 1 + p 2 - p [ z 1 + p 2 - p 1 - α 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) β } , Mathematical equation

it is easy to obtain that

F ( α ; α , β ) = α d ξ ξ p 1 { q 1 - q 2 1 + p 2 - p 1 [ ξ 1 + p 2 - p 1 - α 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) β } q 1 q 1 - q 2 = β d η e q 2 η { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) η - e ( q 1 - q 2 ) β ] + α 1 + p 2 - p 1 } p 2 1 + p 2 - p 1 = G ( β ; α , β ) , Mathematical equation

that is T(α,β)=F(α;α,β)=G(β;α,β).Mathematical equation

3 Proof of Main Results

In this section, we prove the main results by first proving Theorem 1.

Proof   Choosing α=ρM(θ), β=ρM(ϑ),Mathematical equation by virtue of comparison principle, see also Lemma 3.1 in Ref. [6], it follows that

u ( x , t ) z ( t ; ρ M ( θ ) , β = ρ M ( ϑ ) ) , v ( x , t ) w ( t ; ρ M ( θ ) , β = ρ M ( ϑ ) ) , Mathematical equation

for xΩMathematical equation and 0<tmin{T(ρ),T(ρM(θ),ρM(ϑ))},Mathematical equationthis implies T(ρ)T(ρM(θ),ρM(ϑ)).Mathematical equation

If θ0,Mathematical equationwe obtain

T ( ρ ) ρ M ( θ ) d ξ ξ p 1 { q 1 - q 2 1 + p 2 - p 1 [ ξ 1 + p 2 - p 1 - ( ρ M ( θ ) ) 1 + p 2 - p 1 ] + e ( q 1 - q 2 ) ρ M ( ϑ ) } q 1 q 1 - q 2 = 1 ρ M ( θ ) d z ( ρ M ( θ ) z ) p 1 { q 1 - q 2 1 + p 2 - p 1 ( ρ M ( θ ) z ) 1 + p 2 - p 1 + e ( q 1 - q 2 ) ρ M ( ϑ ) - q 1 - q 2 1 + p 2 - p 1 ( ρ M ( θ ) ) 1 + p 2 - p 1 } q 1 q 1 - q 2 = ( ρ M ( θ ) ) - q 2 ( 1 - p 1 ) + p 2 q 1 q 1 - q 2 1 ρ M ( θ ) d z ( z ) p 1 { q 1 - q 2 1 + p 2 - p 1 ( z ) 1 + p 2 - p 1 + e ( q 1 - q 2 ) ρ M ( ϑ ) ( ρ M ( θ ) ) 1 + p 2 - p 1 - q 1 - q 2 1 + p 2 - p 1 } q 1 q 1 - q 2 . Mathematical equation

Multiplying (ρM(θ))q2(1-p1)+p2q1q1-q2Mathematical equation to both sides above inequality and taking ρ,Mathematical equationwe obtain the result (i) of Theorem 1 by Lebesgue theorem[10].

If θ=0,Mathematical equationwe have

T ( ρ ) ρ M ( ϑ ) d η e q 2 η { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) η - e ( q 1 - q 2 ) ρ M ( ϑ ) ] } p 2 1 + p 2 - p 1 = 1 q 2 ρ M ( ϑ ) d w e q 2 ρ M ( ϑ ) w { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) ρ M ( ϑ ) w - e ( q 1 - q 2 ) ρ M ( ϑ ) ] } p 2 1 + p 2 - p 1 = [ e ρ M ( ϑ ) ] - p 2 ( q 1 - q 2 ) 1 + p 2 - p 1 1 d w e q 2 ρ M ( ϑ ) w q 2 ρ M ( ϑ ) { 1 + p 2 - p 1 q 1 - q 2 [ e ( q 1 - q 2 ) ρ M ( ϑ ) w e ( q 1 - q 2 ) ρ M ( ϑ ) - 1 ] } p 2 1 + p 2 - p 1 . Mathematical equation

Multiplying [eρM(ϑ)]p2(q1-q2)1+p2-p1Mathematical equation to both sides above inequality and taking ρ,Mathematical equationwe obtain the result (ii) of Theorem 1 by Leesgue theorem[10]. This completes the proof of the Theorem 1.

The following proof proves Theorem 2.

Proof   In order to prove this Lemma, we employ Kaplan's method[7]. First we consider the case of θ0,Mathematical equation assume without loss generality that θ(0)=M(θ),Mathematical equation define by μ(R)Mathematical equation the first eigenvalue of -ΔMathematical equation in the ball B(R)=BR(0),Mathematical equation and ψRMathematical equation is the corresponding eigenfunction.

Thus, we have

{ - Δ ψ R = μ R ψ R ,     i n    B R , ψ R = 0 ,                  o n    B R . Mathematical equation

Assuming that BRψR(x)dx=1,Mathematical equation it is easy to note that μ(R)=μ1R2,ψR(x)=R-Nψ1(xR).Mathematical equation

Let BRΩ,Mathematical equation we set

z ( t ) = B R u ( x , t ) ψ R ( x ) d x , w ( t ) = B R v ( x , t ) ψ R ( x ) d x ,   α ( R ) = B R θ ( x ) ψ R ( x ) d x ,   β ( R ) = B R ϑ ( x ) ψ R ( x ) d x . Mathematical equation

Since θ(x), ϑ(x)C(Ω¯), BRψ1(x)dx=1,Mathematical equation we obtain limR0α(R)=θ(0), limR0β(R)=ϑ(0).Mathematical equation

Multiplying the equations of (1)-(4) by ψR,Mathematical equationintegrating by parts and using Jensen inequality[10], we have

z t - μ R z + z p 1 e q 1 w , t > 0 , w t - μ R w + z p 2 e q 2 w , t > 0 , z ( 0 ) = ρ α ( R ) , w ( 0 ) = ρ β ( R ) . Mathematical equation

By using the derivative formula of the product of two terms and performing simple calculations, we obtain

( e μ R t z ) t e μ R t + q 1 w z p 1 ,   ( e μ R t w ) t e μ R t + q 1 w z p 2 . Mathematical equation

Integrating these inequalities over (0,t),Mathematical equation we see that

e μ R t z - ρ α ( R ) 0 t ( z ( s ) ) p 1 e μ R s + q 1 w ( s ) d s ,   e μ R t w - ρ β ( R ) 0 t ( z ( s ) ) p 2 e μ R s + q 2 w ( s ) d s . Mathematical equation

Substituting the second inequality into the first, it follows that

z ( t ) ρ α ( R ) e - μ R t + e - μ R t 0 t ( z ( s ) ) p 1 e x p { μ R s + q 1 ρ β ( R ) e - μ R s + q 1 e - μ R s 0 s ( z ( y ) ) p 2 e μ R y + q 2 w ( y ) d y } d s ρ α ( R ) e - μ R t + e μ R ( s - t ) 0 t ( z ( 0 ) ) p 1 e x p { q 1 ρ β ( R ) + q 1 0 s ( z ( y ) ) p 2 d y } e - μ R s d s ρ α ( R ) e - μ R t + e - μ R t e q 1 ρ β ( R ) e - μ R s [ ρ α ( R ) ] p 1 0 t { e x p [ q 1 0 s ( z ( y ) ) d y ] e - μ R s } d s . Mathematical equation

where, when 0st,Mathematical equation we use the following inequality

e μ R ( s - t ) = e μ R s e - μ R t > e - μ R t , e - μ R s > e - μ R t . Mathematical equation

We fix 0<ε<1Mathematical equation and take TR>0,Mathematical equation such that e-μRTR>1-ε,Mathematical equation then we have

z ( t ) ρ α ( R ) ( 1 - ε ) + ( 1 - ε ) e q 1 ρ β ( R ) ( 1 - ε ) [ ρ α ( R ) ] p 1 0 t { e x p [ q 1 0 s ( z ( y ) ) d y ] ( 1 - ε ) } d s . Mathematical equation

We set

H ( t ) = ρ α ( R ) ( 1 - ε ) + ( 1 - ε ) e q 1 ρ β ( R ) ( 1 - ε ) [ ρ α ( R ) ] p 1 0 t { e x p [ q 1 0 s ( z ( y ) ) d y ] ( 1 - ε ) } d s , H ' ( t ) = ( 1 - ε ) [ ρ α ( R ) ] p 1 e q 1 ρ β ( R ) ( 1 - ε ) { e x p [ q 1 0 s ( z ( y ) ) d y ] ( 1 - ε ) } , H ' ' ( t ) = ( 1 - ε ) 2 [ ρ α ( R ) ] p 1 e q 1 ρ β ( R ) ( 1 - ε ) { e x p [ q 1 0 s ( z ( y ) ) d y ] ( 1 - ε ) } q 1 z ( t )   . Mathematical equation

Since z(t)H(t),Mathematical equation we see that

H ' ' ( t ) q 1 ( 1 - ε ) H ( t ) H ' ( t ) . Mathematical equation

Integrating these inequalities over (0,t),Mathematical equation it follows that

H ' ( t ) ( 1 - ε ) [ ρ α ( R ) ] p 1 e ρ β ( R ) ( 1 - ε ) + q 1 ( 1 - ε ) 2 H 2 ( t ) - q 1 ( 1 - ε ) 2 ρ 2 [ α ( R ) ] 2 ( 1 - ε ) 2 . Mathematical equation

Dividing the left hand side by the right hand side and integrating over (0,t),Mathematical equation we have

( 1 - ε ) ρ α ( R ) H ( t ) d s ( 1 - ε ) [ ρ α ( R ) ] p 1 e ρ β ( R ) ( 1 - ε ) + q 1 ( 1 - ε ) 2 s 2 - q 1 ( 1 - ε ) 2 ρ 2 [ α ( R ) ] 2 ( 1 - ε ) 2 t . Mathematical equation

We take large ρ<0,Mathematical equation such that

T ε , R = ( 1 - ε ) ρ α ( R ) d s q 1 ( 1 - ε ) 2 s 2 + ( 1 - ε ) [ ρ α ( R ) ] p 1 e ρ β ( R ) ( 1 - ε ) - q 1 ( 1 - ε ) 3 2 ρ 2 [ α ( R ) ] 2 = 1 ( 1 - ε ) ρ α ( R ) d z q 1 ( 1 - ε ) 3 2 ρ 2 ( α ( R ) ) 2 z 2 + ( 1 - ε ) [ ρ α ( R ) ] p 1 e ρ β ( R ) ( 1 - ε ) - q 1 ( 1 - ε ) 3 2 ρ 2 [ α ( R ) ] 2 = [ ρ α ( R ) ] - 1 1 d z q 1 ( 1 - ε ) 2 2 { z 2 + 2 [ ρ α ( R ) ] p 1 - 2 e ρ β ( R ) ( 1 - ε ) q 1 ( 1 - ε ) 2 - 1 } . Mathematical equation

Then zMathematical equation blows up at time T(ρ)Tε,R,Mathematical equation hence we get

[ ρ α ( R ) ] T ( ρ ) 1 d z q 1 ( 1 - ε ) 2 2 { z 2 + 2 [ ρ α ( R ) ] p 1 - 2 e ρ β ( R ) ( 1 - ε ) q 1 ( 1 - ε ) 2 - 1 } . Mathematical equation

Therefore, by p2Mathematical equation and Lebesgue's theorem, it follows that

l i m   s u p ρ [ ρ α ( R ) ] T ( ρ ) = 1 d z q 1 ( 1 - ε ) 2 2 { z 2 + 2 [ ρ α ( R ) ] p 1 - 2 e ρ β ( R ) ( 1 - ε ) q 1 ( 1 - ε ) 2 - 1 } . Mathematical equation

Taking R0Mathematical equation and then ε0,Mathematical equation we obtain the result (i) of Theorem 2.

Next we consider the case of θ=0.Mathematical equation Similarly, we have

w ( t ) ρ β ( R ) e - μ R t + e - μ R t 0 t [ e - μ R s 0 s ( z ( y ) ) p 1 e μ R y + q 1 w ( y ) d y ] p 2 e q 2 w ( s ) d s ρ β ( R ) e - μ R t + e - μ R t e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 0 t [ 0 s e q 1 w ( y ) d y ] p 2 d s . Mathematical equation

We fix 0<ε<1Mathematical equation and take TR>0,Mathematical equation such that e-μRTR>1-ε,Mathematical equationthen we have

w ( t ) ρ β ( R ) ( 1 - ε ) + ( 1 - ε ) e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 0 t [ 0 s e q 1 w ( y ) d y ] p 2 d s Mathematical equation

Taking p1min{p2,p2-1},Mathematical equation we set

Q ( t ) = ρ β ( R ) ( 1 - ε ) + ( 1 - ε ) e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 0 t [ 0 s e q 1 w ( y ) d y ] p 2 d s , Q ' ( t ) = ( 1 - ε ) e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 [ 0 s e q 1 w ( y ) d y ] p 2 ( 1 - ε ) e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 [ 0 s e q 1 w ( y ) d y ] p 1 , Q ' ' ( t ) = ( 1 - ε ) p 2 e p 2 q 2 ρ β ( R ) [ α ( R ) ] p 1 p 2 [ 0 s e q 1 w ( y ) d y ] p 2 - 1 e q 1 w ( t ) p 2 e q 1 Q ( t ) Q ' ( t ) . Mathematical equation

Integrating these inequalities over (0,t),Mathematical equation it follows that

Q ' ' ( t ) p 2 q 1 [ e q 1 Q ( t ) - e q 1 ρ β ( R ) ] . Mathematical equation

Dividing the left hand side by the right hand side and integrating over (0,t),Mathematical equation we obtain

( 1 - ε ) ρ β ( R ) Q ( t ) d s p 2 q 1 [ e q 1 s - e q 1 ρ β ( R ) ] t . Mathematical equation

We take large ρ>0, Mathematical equationsuch that

T ε , R = ( 1 - ε ) ρ β ( R ) d s p 2 q 1 [ e q 1 s - e q 1 ρ β ( R ) ] = 1 ( 1 - ε ) ρ β ( R ) d w p 2 q 1 [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] = 1 d w p 2 q 1 ( 1 - ε ) ρ β ( R ) [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] = [ ρ β ( R ) ] - 1 1 d w p 2 q 1 ( 1 - ε ) [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] . Mathematical equation

Then zMathematical equation blow up at time T(ρ)Tε,R,Mathematical equation hence we get

[ ρ β ( R ) ] T ( ρ ) 1 d w p 2 q 1 ( 1 - ε ) [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] . Mathematical equation

Therefore, by Lebesgue theorem[10], it follows that

l i m   s u p ρ [ ρ β ( R ) ] T ( ρ ) = 1 d w p 2 q 1 ( 1 - ε ) [ e q 1 ( 1 - ε ) ρ β ( R ) w - e q 1 ρ β ( R ) ] , Mathematical equation

taking R0Mathematical equation and then ε0,Mathematical equation we obtain the result (ii) of Theorem 2. This completes the proof of Theorem 2.

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