Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 30, Number 5, October 2025
Page(s) 463 - 470
DOI https://doi.org/10.1051/wujns/2025305463
Published online 04 November 2025

© Wuhan University 2025

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

Let Rn,n2,Mathematical equation be the nMathematical equation-dimensional Euclidean spaces. This paper aims to investigate the compactness of the commutator of the Adams type bilinear fractional integral operator (or Riesz potential) Iα,0<α<n.Mathematical equation The bilinear fractional integral operator IαMathematical equation is defined by

I α ( f , g ) ( x ) = R n R n f ( y ) g ( z ) ( | x - y | + | x - z | ) 2 n - α d y d z , Mathematical equation

where xRn,Mathematical equationand f,gMathematical equation are locally integrable functions.

When considering a bilinear operator Iα(f,g),Mathematical equation we define the commutators {[b,Iα]i}i=12Mathematical equation to be

[ b , I α ] 1 ( f , g ) = b I α ( f , g ) - I α ( b f , g ) , Mathematical equation

and

[ b , I α ] 2 ( f , g ) = b I α ( f , g ) - I α ( f , b g ) , Mathematical equation

where bLloc1(Rn)Mathematical equation.

Riesz[1] developed a theory of multidimensional fractional integration and derived a powerful method for solving linear differential equations of the hyperbolic type from it. In 1978, Uchiyama[2] showed that linear commutators of Calderón-Zygmund operators and pointwise multiplication with a symbol belonging to an appropriate subspace of the John-Nirenberg space (BMO(Rn))Mathematical equation are compact. For a proof of the boundedness of multilinear fractional integrals, see the papers by Chen and Xue[3] and Chen and Wu[4]. Bényi et al[5] established the compactness of commutators of bilinear fractional integrals from Lp(Rn)×Lq(Rn)Mathematical equation to Lr(Rn)Mathematical equation with bBMO(Rn)Mathematical equation. In 2015, Ding and Mei[6] obtained the compactness of commutators of bilinear Riesz potential on Morrey spaces, from L(p1,λ1)(Rn)×L(p2,λ2)(Rn)Mathematical equation to L(q,λ)(Rn)Mathematical equation with bBMO(Rn)Mathematical equation. Subsequently, the compactness of commutators of multilinear operators was studied extensively, see Refs. [7-10].

On the other hand, Arai and Nakai[11-12] studied the commutators [b,Iρ]Mathematical equation of the fractional integral operator IρMathematical equation on the generalized Morrey spaces and showed that if bMathematical equation is a function of generalized Campanato spaces ε(1,ψ)(Rn)Mathematical equation, which contain the BMO(Rn)Mathematical equation and Lipschitz spaces as special examples, then [b,Iρ]Mathematical equation is bounded and compact on the generalized Morrey spaces. The corresponding result for the commutator of a general fractional integral was also obtained.

Based on the results above, it is natural to ask the following question:

Question: What are the mapping properties of [b,Iα]i,i=1,2,Mathematical equation on the generalized Morrey spaces when bMathematical equation is a function in the generalized Campanato spaces? Moreover, whether it is compact or not in generalized Morrey spaces?

The main purpose of this paper is to address this question. To state our main results, we first recall some relevant definitions and notations. Let B(x,r)Mathematical equation be the open ball centered at xRnMathematical equation and of radius rMathematical equation, that is,

B ( x , r ) = { y R n : | y - x | < r } . Mathematical equation

For a measurable set ERn,Mathematical equation we denote by |E|Mathematical equation and χEMathematical equation the Lebesgue measure of EMathematical equation and the characteristic function of EMathematical equation, respectively. For a function fLloc1(Rn)Mathematical equation and a ball B,Mathematical equation let fB=1|B|Bf(y)dy.Mathematical equation

Moreover, for a measurable function ϕ: Rn×(0,)(0,)Mathematical equation, while a ball B=B(x,r)Mathematical equation, we denote by ϕ(B)=ϕ(x,r).Mathematical equation

Definition 1[11] Let ϕ(x,r)Mathematical equation be a positive measurable function on Rn×(0,)Mathematical equation and p[1,)Mathematical equation, the generalized Morrey space L(p,ϕ)(Rn)Mathematical equation is denoted by:

L ( p , ϕ ) ( R n ) : = { f : f L ( p , ϕ ) ( R n ) = s u p B ( 1 ϕ ( B ) | B | B | f ( y ) | p d y ) 1 / p < } , Mathematical equation

where the supremum is taken over all balls BMathematical equation in Rn.Mathematical equation

We know that fL(p,ϕ)(Rn)Mathematical equation is a norm and L(p,ϕ)(Rn)Mathematical equation is a Banach space. More generally, if ϕλ(x,r)=rλMathematical equation for λ[-n,0]Mathematical equation, then L(p,ϕ)(Rn)Mathematical equation is the classical Morrey space, that is,

f L ( p , ϕ λ ) ( R n ) = s u p B ( 1 ϕ λ ( B ) | B | B | f ( y ) | p d y ) 1 / p = s u p B = B ( x , r ) ( 1 r λ | B | B | f ( y ) | p d y ) 1 / p , Mathematical equation

In particular, L(p,ϕ-n)(Rn)=Lp(Rn)Mathematical equation and L(p,ϕ0)(Rn)=L(Rn).Mathematical equation

We recall the definition of BMO(Rn)Mathematical equation, denoted by

B M O ( R n ) : = { b L l o c 1 ( R n ) : b B M O ( R n ) Mathematical equation

= s u p B 1 | B | B | b ( x ) - b B | d x < } , Mathematical equation

where the supremum is taken over all balls BRn.Mathematical equation

We also consider the generalized Campanato spaces with variable growth condition, which are defined as follows.

Definition 2[11] Let ψ(x,r)Mathematical equation be a positive measurable function on Rn×(0,)Mathematical equation and p[1,)Mathematical equation, the generalized Campanato spaces ε(p,ψ)(Rn)Mathematical equation are denoted by

ε ( p , ψ ) ( R n ) : = { f L l o c 1 ( R n ) : f ε ( p , ψ ) ( R n ) < } , Mathematical equation

where fε(p,ψ)(Rn)=supB(1ψ(B)|B|B|f(y)-fB|pdy)1/p,Mathematical equation the supremum is taken over all balls BRn.Mathematical equation

It is easy to check that fε(p,ψ)(Rn)Mathematical equation is a normed modulo constant functions and thereby ε(p,ψ)(Rn)Mathematical equation is a Banach space. If p=1Mathematical equation and ψ1,Mathematical equation then ε(p,ψ)(Rn)=BMO(Rn)Mathematical equation. If p=1Mathematical equation and ψ(x,r)=rαMathematical equation(0<α1),Mathematical equation then coincide with Lipα(Rn).Mathematical equation

We say that a function θ:Rn×(0,)(0,)Mathematical equation satisfies the doubling condition if there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r,s(0,),Mathematical equation such that

1 C θ ( x , r ) θ ( x , s ) C , i f 1 2 r s 2 . Mathematical equation(1)

We say that θMathematical equation is almost increasing (resp. almost decreasing) if there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r,s(0,),Mathematical equation such that θ(x,r)Cθ(x,s), (resp.Mathematical equation

θ ( x , s ) C θ ( x , r ) ) ,   i f   r s . Mathematical equation

We also consider the following condition: there exists a positive constant C,Mathematical equation for all x,yRnMathematical equation and r(0,),Mathematical equation such that

1 C θ ( x , r ) θ ( y , r ) C , i f | x - y | r . Mathematical equation(2)

For two functions θ,κ:Rn×(0,)(0,)Mathematical equation, we write θ~κMathematical equation if there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation such that

1 C θ ( x , r ) κ ( x , r ) C . Mathematical equation(3)

Definition 3 (i)   Let ςdecMathematical equation be the set of all functions ϕ:Rn×(0,)(0,)Mathematical equation such that ϕMathematical equation is almost decreasing and that rϕ(x,r)rnMathematical equation is almost increasing. That is, there exists a positive constant C,Mathematical equationfor all xRnMathematical equation and r,s(0,),Mathematical equation such that

C ϕ ( x , r ) ϕ ( x , s ) , ϕ ( x , r ) r n C ϕ ( x , s ) s n , i f r < s . Mathematical equation

(ii) Let ςincMathematical equation be the set of all functions ϕ:Rn×(0,)(0,)Mathematical equation such that ϕMathematical equation is almost increasing and that rϕ(x,r)/rMathematical equation is almost decreasing. That is, there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r,s(0,),Mathematical equation such that ϕ(x,r)Cϕ(x,s),Cϕ(x,r)/rϕ(x,s)/s,ifr<s.Mathematical equation

Remark 1 (i)   If ϕςdecMathematical equation or ϕςinc,Mathematical equation then ϕMathematical equation satisfies the doubling condition (1).

(ii) It follows from Ref. [11] that for ϕςdecMathematical equation, if ϕMathematical equation satisfies

l i m r + 0 ϕ ( x , r ) = , l i m r ϕ ( x , r ) = 0 , Mathematical equation(4)

then there exists ϕ˜ςdecMathematical equation such that ϕ~ϕ˜Mathematical equation and that ϕ˜(x,)Mathematical equation is continuous, strictly decreasing and bijective from (0,)Mathematical equation to itself for each x.Mathematical equation

(iii) Assume that ϕςdecMathematical equation and there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equationwe get

r ϕ ( x , t ) t d t C ϕ ( x , r ) . Mathematical equation(5)

For fL(p1,ϕ1)(Rn),gL(p2,ϕ2)(Rn),1<p1,p2<,Mathematical equation we denote fχ2B(y):=f1(y), fχ(2B)C(y):=f2(y),Mathematical equation gχ2B(z):=g1(z),Mathematical equation

g χ ( 2 B ) C ( z ) : = g 2 ( z ) , Mathematical equation We define Ια(f,g)(x)Mathematical equation on each ball BMathematical equation by

Ι α ( f , g ) ( x ) = Ι α ( f 1 , g 1 ) ( x ) + Ι α ( f 1 , g 2 ) ( x ) + Ι α ( f 2 , g 1 ) ( x ) + Ι α ( f 2 , g 2 ) ( x ) . Mathematical equation(6)

Note that Ια(f1,g1)(x)Mathematical equation is well defined since fχ2BLp1(Rn)Mathematical equation, and gχ2BLp2(Rn),Mathematical equation it is easy to check that Iα(f1,g2)(x), Iα(f2,g1)(x), and Iα(f2,g2)(x)Mathematical equation converge absolutely. Iα(f,g)(x)Mathematical equation defined in (6) is independent of the choice of the ball containing x.Mathematical equation Moreover, we can show that Iα(f,g)(x)Mathematical equation is bounded from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(p˜,ϕ)(Rn)Mathematical equation, see Lemma 4.1 in Ref. [13].

For fL(p1,ϕ1)(Rn), gL(p2,ϕ2)(Rn),1<p1,p2<Mathematical equation, employing the notation as in (6), we will define [b,Iα]i(f,g)(x),i=1,2,Mathematical equationon each ball BMathematical equation by

[ b , I α ] i ( f , g ) ( x ) = [ b , I α ] i ( f 1 , g 1 ) ( x ) + [ b , I α ] i ( f 1 , g 2 ) ( x ) + [ b , I α ] i ( f 2 , g 1 ) ( x ) + [ b , I α ] i ( f 2 , g 2 ) ( x ) . Mathematical equation(7)

Let bε(1,ψ)(Rn),Mathematical equation note that [b,Iα]i(f1,g1)(x)Mathematical equation is well defined since fχ2BLp1(Rn)Mathematical equation, and gχ2BLp2(Rn),Mathematical equation it is easy to check that [b,Iα]i(f1,g2)(x), [b,Iα]i(f2,g1)(x), andMathematical equation

[ b , I α ] i ( f 2 , g 2 ) ( x ) Mathematical equation converge absolutely, then (7) is well defined. Moreover, we can show that [b,Iα]i(f,g)(x),Mathematical equation defined in (7), is independent of the choice of the ball containing x,Mathematical equationsee Lemma 4.2 in Ref. [13]. Furthermore, we can show that [b,Iα]i(f,g)(x),i=1,2,Mathematical equation is bounded from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn)Mathematical equation. See Lemma 1 for the details.

For the commutators [b,Iα]i(f,g)(x),i=1,2,Mathematical equation we have Lemma 1.

Lemma 1[13] Let p,p1,p2,q(1,),p<q,1p+1q<1,α(0,2n)Mathematical equation satisfies α/n<1/p,Mathematical equation1/q=1/p-α/n,Mathematical equation and ϕ,ϕ1,ϕ2,ψ:Rn×(0,)(0,)Mathematical equation.

(i) Assume that ϕ,ϕ1,ϕ2ςdecMathematical equation and ψςincMathematical equation, ψMathematical equation satisfies (2), ϕ,ϕ1,ϕ2Mathematical equation satisfy (5) and there exist positive constants C0,C1Mathematical equation and an exponent p˜(p,q],Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation we get

1 p 1 + 1 p 2 = 1 p , Mathematical equation(8)

ϕ 1 1 / p 1 ϕ 2 1 / p 2 = ϕ 1 / p , Mathematical equation(9)

0 r t α - 1 d t ϕ ( x , r ) 1 / p + r t α - 1 ϕ ( x , t ) 1 / p d t C 0 ϕ ( x , r ) 1 / p ˜ , Mathematical equation(10)

ψ ( x , r ) ϕ ( x , r ) 1 / p ˜ C 1 ϕ ( x , r ) 1 / q Mathematical equation(11)

If bε(1,ψ)(Rn),Mathematical equation then [b,Iα]i(f,g)(x),i=1,2Mathematical equation is well defined for all fL(p1,ϕ1)(Rn),Mathematical equationgMathematical equationL(p2,ϕ2)(Rn).Mathematical equation That is, for all f,g,Mathematical equation there exists a positive constant C,Mathematical equation independent of b,f,g,Mathematical equation such that

[ b , I α ] i ( f , g ) L ( q , ϕ ) C b ε ( 1 , ψ ) f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) . Mathematical equation

(ii) Conversely, assume that ϕMathematical equation satisfies (2), and there exist positive constants C2,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equationwe get

C 2 ψ ( x , r ) r α ϕ ( x , r ) 1 / p ϕ ( x , r ) 1 / q . Mathematical equation(12)

If [b,Iα]i(f,g)(x),i=1,2,Mathematical equation is bounded from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn),Mathematical equation then bε(1,ψ)(Rn),Mathematical equation such that bε(1,ψ)[b,Iα]i(f,g)L(p1,ϕ1)×L(p2,ϕ2)L(q,ϕ).Mathematical equation

In this paper, we use the method of Arai and Nakai[12], and give sufficient conditions for the compactness of commutators of bilinear fractional integral operator.

We denote by Ccomp(Rn)¯ε(1,ψ)(Rn),Mathematical equation the closure of Ccomp(Rn)Mathematical equation with respect to ε(1,ψ)(Rn)Mathematical equation. If ψ1Mathematical equation, then ε(1,ψ)(Rn)=BMO(Rn)Mathematical equation and Ccomp(Rn)¯BMO(Rn)=CMO(Rn).Mathematical equation

In order to obtain the compactness of the commutators [b,Iα]i(f,g)(x),i=1,2,Mathematical equation we consider the following condition on ψMathematical equation: there exists a positive constant C,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation such that

r ψ ( x , t ) t 2 d t C ψ ( x , r ) r . Mathematical equation(13)

In the end, the main results of this work are stated as follows.

Theorem 1   Let p,p1,p2(1,), p<qMathematical equation and ϕ,ϕ1,ϕ2:Rn×(0,)(0,)Mathematical equation, assume the same condition as Lemma 1, ϕMathematical equation and ψMathematical equation satisfy (2) and (13), respectively. If bCcomp(Rn)¯ε(1, ψ)(Rn),Mathematical equation then [b,Iα]i(f,g)(x),i=1,2,Mathematical equation are compact from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn).Mathematical equation

Remark 2   From the theorem above, we have the following several corollaries.

1) Take ϕ(x,r)=rλ, λ(-n,0), ψ(x,r)1.Mathematical equation Then we have the result for Morrey spaces L(p1,ϕ1)(Rn)=L(p1,λ1)(Rn), L(p2,ϕ2)Mathematical equation(Rn)=L(p2,λ2)(Rn),Mathematical equation ε(1,ψ)(Rn)=BMO(Rn).Mathematical equation This case is known by Ding and Mei[6].

2) Take ϕ(x,r)=r-n, ψ(x,r)1.Mathematical equation Then L(p1,ϕ1)(Rn)=Lp1(Rn),Mathematical equation L(p2,ϕ2)(Rn)=Lp2(Rn),Mathematical equation ε(1,ψ)(Rn)=Mathematical equationBMO(Rn).Mathematical equation This is the result obtained by Bényi et al[14].

Remark 3   Under the assumption of Theorem 1, by Ref. [13], for all fL(p1,ϕ1)(Rn),Mathematical equation gL(p2,ϕ2)(Rn),Mathematical equation and a.e.xRn,Mathematical equation then we get

[ b , I α ] i ( f , g ) ( x ) = l i m ε + 0 ( | x - y | 2 + | x - z | 2 ) 1 2 > ε ( b ( x ) - b ( y ) ) | f ( x ) g ( z ) | ( | x - y | + | x - z | ) 2 n - α d y d z , Mathematical equation(14)

where i=1,2.Mathematical equation

The rest of this paper is organized as follows. In Section 1, we will recall Musielak-Orlicz spaces and establish some auxiliary lemmas. The proof of Theorem 1 will be given in Section 2. In Section 3, we discuss the compactness of the commutators of the m-linear fractional integral operator. Finally, we make some conventions on notation. Throughout this paper, we always use CMathematical equation to denote a positive constant that is independent of the main parameters involved but whose value may differ from line to line. Constants with subscripts, such as CpMathematical equation ,are dependent on the subscripts. We denote fgMathematical equation if fCg,Mathematical equation and f~gMathematical equation if fgf.Mathematical equation For 1p, p'Mathematical equation is the conjugate index of pMathematical equation, and 1p+1p'=1.EC=Rn\EMathematical equation is the complementary set of any measurable subset EMathematical equation of Rn.Mathematical equation

1 Preliminaries

In order to obtain our result, we recall Young functions and Musielak-Orlicz spaces. Let ΦYMathematical equation be the set of all Young functions, see Ref. [15].

Let ΦYυMathematical equation be the set of all Φ:Rn×[0,][0,]Mathematical equation such that Φ(x,)Mathematical equation is a Young function for every xRn,Mathematical equation and that Φ(,t)Mathematical equation is measurable on RnMathematical equation for every t[0,].Mathematical equation

For ΦΦYυMathematical equation and xRn,Mathematical equation let

Φ - 1 ( x , u ) = { i n f { t 0 : Φ ( x , t ) > u } , u [ 0 , ) , ,    u = . Mathematical equation

We also define the complementary function Φ˜:Rn×[0,][0,]Mathematical equation by

Φ ˜ ( x , t ) = { s u p { t u - Φ ( x , u ) : u [ 0 , ) } , t [ 0 , ) , ,   t = . Mathematical equation

Definition 4   (Musielak-Orlicz space) For a function ΦΦYυMathematical equation, let

L Φ ( R n ) = { f : R n Φ ( x , ε | f ( x ) | d x < , f o r   s o m e   ε > 0 } , Mathematical equation

f L Φ = i n f { λ > 0 : R n Φ ( x , | f ( x ) | λ ) d x 1 } . Mathematical equation

Then LΦMathematical equation is a norm, which is called the Luxemburg-Nakano norm, and thereby LΦ(Rn)Mathematical equation is a Banach space.

Lemma 2[12] Let 1q<Mathematical equation and ϕ:Rn×(0,)(0,)Mathematical equation, assume that ϕMathematical equation is in ϕςdecMathematical equation and satisfies (2) and (4). Then there exists a function Φq,ϕΦYυMathematical equation such that

L Φ q , ϕ ( R n ) L ( q , ϕ ) ( R n ) ,   a n d   f L ( q , ϕ ) C f L Φ q , ϕ , Mathematical equation

where Φq,ϕ(x,t)=Φϕ(x,tq),Mathematical equation and CMathematical equation is a positive constant independent of fLΦq,ϕ(Rn).Mathematical equation

Remark 4[12] By Lemma 2, we see that, for all balls B,Mathematical equation then χBLΦq,ϕ1ϕ(B)1/q.Mathematical equation

For a function ρ:Rn×(0,)(0,),Mathematical equationthe generalized bilinear Hardy-Littlewood maximal operator is defined by

Μ ρ ( f , g ) ( x ) = s u p x B ρ ( B ) 1 | B | 2 B | f ( y ) | d y B | g ( z ) | d z . Mathematical equation

Clearly, if ρ1,Mathematical equation then Μρ(f,g)(x)Mathematical equation is the bilinear of the Hardy-Littlewood maximal operator Μ,Mathematical equation and if ρ(B)=|B|α/n,Mathematical equation then Μρ(f,g)(x)Mathematical equation is the fraction maximal operator ΜαMathematical equation defined by

Μ α ( f , g ) ( x ) = s u p x B 1 | B | 2 - α / n B | f ( y ) | d y B | g ( z ) | d z . Mathematical equation

The boundedness of ΜρMathematical equation is the consequence of the following theorems.

Theorem 2[16] Let p,p1,p2,q(1,),p<qMathematical equation satisfies (8). Let ρ,ϕ,ϕ1,ϕ2:Mathematical equationRn×(0,)Mathematical equation(0,).Mathematical equation

Assume that ϕ,ϕ1,ϕ2Mathematical equation are in ςdecMathematical equation and satisfy (4) and (9). Assume also that there exists a positive constant C0,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation such that

ρ ( x , r ) ϕ ( x , r ) 1 / p C 0 ϕ ( x , r ) 1 / q , Mathematical equation(15)

then Μρ(f,g)Mathematical equation is bounded from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn).Mathematical equation

In order to obtain the compactness of the commutators, [b,Iα]i(f,g)(x),i=1,2,Mathematical equation we construct the integral operator as follows:

T 0 ( f , g ) ( x ) = ( n ) 2 K 0 ( x , y , z ) f ( y ) g ( z ) d y d z , x R n , Mathematical equation(16)

for a kernel function K0: (Rn)3C.Mathematical equation In this section, we will prove the following proposition.

Proposition 1   Let p,p1,p2,q(1,),pqMathematical equation and ϕ, ϕ1, ϕ2:Rn×(0,)(0,)Mathematical equation, assume that ϕ, ϕ1,Mathematical equation ϕ2Mathematical equation are in ςdecMathematical equation and satisfy (2) and (4). If K0Lcomp((Rn)3),Mathematical equation then T0Mathematical equation defined by (16) is a compact operator from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn).Mathematical equation

To prove Proposition 1, we use Lemma 2 and the following Lemma 3.

Lemma 3   Let ΦΦYυMathematical equation, if

K 0 L Φ ( R n ; L p ' ( ( R n ) 2 ) ) : = ( ( R n ) 2 | K 0 ( , y , z ) | p ' d y d z ) 1 / p ' L Φ < , Mathematical equation

then T0Mathematical equation is compact from Lp1(Rn)×Lp2(Rn)Mathematical equation to LΦ(Rn),Mathematical equation and

T 0 L p 1 × L p 2 L Φ K 0 L Φ ( R n ; L p ' ( ( R n ) 2 ) ) , Mathematical equation(17)

where Lp1×Lp2LΦMathematical equation is the operator norm from Lp1(Rn)×Lp2(Rn)Mathematical equation to LΦ(Rn).Mathematical equation

Proof   By Hölder's inequality, we have

| T 0 ( f , g ) ( x ) | ( R n ) 2 | K 0 ( x , y , z ) | | f ( y ) g ( z ) | d y d z Mathematical equation

( ( R n ) 2 | K 0 ( x , y , z ) | p ' d y d z ) 1 / p ' f L p 1 g L p 2 , Mathematical equation

which implies

T 0 ( f , g ) L Φ ( ( R n ) 2 | K 0 ( , y , z ) | p ' d y d z ) 1 / p ' L Φ f L p 1 g L p 2 . Mathematical equation

This proofs (17). Next, we show the compactness. For any ε>0,Mathematical equation there exists a finite number of bounded measurable sets E1,E2,,Ek,F11,,F1k,F21,,F2k,Mathematical equation and z11,,z1k,z21,,z2kC,Mathematical equation such that

K 0 - K 0 , ε L Φ ( R n ; L p ' ( ( R n ) 2 ) ) < ε , Mathematical equation

K 0 , ε ( x , y , z ) = j = 1 k { z 1 j χ E j ( x ) χ F 1 j ( y ) + z 2 j χ E j ( x ) χ F 2 j ( z ) } . Mathematical equation

This means that T0Mathematical equation can be approximated by a finite rank operator T0,εMathematical equation, whose kernel is K0,εMathematical equation, which implies that T0Mathematical equation is compact.

Proof of Proposition 1   For qMathematical equation and ϕMathematical equation, take a function Φq,ϕΦYυMathematical equation as in Lemma 2. Then we see that K0LΦq,ϕ(Rn;Lp'((Rn)2))<,Mathematical equation by Remark 4. Let B0Mathematical equation be a ball in RnMathematical equation and satisfy sup K0B0×B0×B0.Mathematical equation Then T0:Mathematical equationL(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)L(q,ϕ)(Rn)Mathematical equation can be factorized as

T 0 : L ( p 1 , ϕ 1 ) ( R n ) × L ( p 2 , ϕ 2 ) ( R n ) T 1 L p ( R n ) T 2 L Φ q , ϕ ( R n ) T 3 Mathematical equation

L ( q , ϕ ) ( R n ) ,   w h e r e   T 1 :   f g χ B 0 ( y ) f ( y ) χ B 0 ( z ) g ( z ) , T 2 :   f g Mathematical equation

T 0 ( f , g ) , T 3 :   f χ B 0 f ,   s o   T 0 ( f , g ) ( x ) = χ B 0 ( x ) ( R n ) 2 K 0 , ε ( x , y , z ) Mathematical equation

χ B 0 ( y ) f ( y ) χ B 0 ( z ) g ( z ) d y d z . Mathematical equation

The operator T1Mathematical equation is clearly bounded and T2Mathematical equation is compact by Lemma 3. The operator T3Mathematical equation is also bounded by Lemma 2. Then T0=T3T2T1Mathematical equation is compact.

Lemma 4[12] Let ϕMathematical equation satisfy the doubling condition (1) and (5), that is, rϕ(x,t)tdtCϕ(x,r).Mathematical equation

Then there exist positive constants εMathematical equation and CεMathematical equation for all xRnMathematical equation and r(0,),Mathematical equationsuch that

r ϕ ( x , t ) t ε t d t C ϕ ( x , r ) r ε . Mathematical equation

Moreover, for all p(0,),Mathematical equationthere exists a positive constant Cp,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equationsuch that

r ϕ ( x , t ) 1 / p t d t C p ϕ ( x , r ) 1 / p . Mathematical equation

Lemma 5[12] If ϕMathematical equation is in ςdecMathematical equation and satisfies (5), then ϕMathematical equation satisfies (4). Actually, ϕMathematical equation satisfies the doubling condition and the following inequalities hold:

ϕ ( x , r ) r 2 r ϕ ( x , t ) t d t r ϕ ( x , t ) t d t ϕ ( x , r ) . Mathematical equation

Then we see that limr+0ϕ(x,r)=Mathematical equation and that limrϕ(x,r)=0Mathematical equation.

Lemma 6[12] If ψMathematical equation satisfies (13), then there exist constants θ(0,1)Mathematical equation and C[1,),Mathematical equation for bCcomp(Rn),Mathematical equation and all x,yRnMathematical equation with |x-y|<1,Mathematical equation such that

| b ( x ) - b ( y ) | C b L | x - y | θ ψ ( x , | x - y | ) . Mathematical equation

2 Proof of Theorem 1

This section is devoted to the proof of Theorem 1.

We consider i=1Mathematical equation and it is enough to prove that [b,Iα]1Mathematical equation is compact for bCcomp(Rn),Mathematical equation since bkbMathematical equation in ε(1,ψ)(Rn),Mathematical equation as k+Mathematical equation, then Lemma 1 shows that

[ b k , I α ] 1 - [ b , I α ] 1 L ( p 1 ,   ϕ 1 ) × L ( p 2 ,   ϕ 2 ) L ( q ,   ϕ ) b k - b ε ( 1 , ψ ) 0 , Mathematical equation

where L(p1, ϕ1)×L(p2, ϕ2)L(q, ϕ)Mathematical equation is the operator norm from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn)Mathematical equation.

For 0<ε<R<,Mathematical equation we denote

I α , ε ( f , g ) ( x ) = ( | x - y | 2 + | x - z | 2 ) 1 / 2 > ε f ( y ) g ( z ) ( | x - y | + | x - z | ) 2 n - α d y d z , Mathematical equation

I α , ε , R ( f , g ) ( x ) = ε < ( | x - y | 2 + | x - z | 2 ) 1 / 2 < R f ( y ) g ( z ) ( | x - y | + | x - z | ) 2 n - α d y d z . Mathematical equation

From Remark 3, it follows that

[ b , I α ] 1 ( f , g ) ( x ) = l i m ε + 0 [ b , I α , ε ] 1 ( f , g ) ( x ) , Mathematical equation

[ b , I α , ε ] 1 ( f , g ) ( x ) = l i m R [ b , I α , ε , R ] 1 ( f , g ) ( x ) , a . e . x R n , Mathematical equation

for all fL(p1,ϕ1)(Rn)Mathematical equation and gL(p2,ϕ2)(Rn)Mathematical equation. If bCcomp(Rn),Mathematical equation then

[ b , I α , ε , R ] 1 ( f , g ) ( x ) = ε < ( | x - y | 2 + | x - z | 2 ) 1 / 2 < R ( b ( x ) - b ( y ) ) f ( y ) g ( z ) ( | x - y | + | x - z | ) 2 n - α d y d z Mathematical equation

is a compact operator from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn)Mathematical equation by Proposition 1 and Lemma 5. Therefore, it is enough to show the following proposition to prove Theorem 1.

Proposition 2   Under the assumption in Theorem 1, if bCcomp(Rn),Mathematical equation then we have

( i ) l i m ε + 0 [ b , I α , ε ] 1 - [ b , I α ] 1 L ( p 1 ,   ϕ 1 ) × L ( p 2 ,   ϕ 2 ) L ( q ,   ϕ ) = 0 , ( i i ) l i m R [ b , I α , ε , R ] 1 - [ b , I α , ε ] 1 L ( p 1 ,   ϕ 1 ) × L ( p 2 ,   ϕ 2 ) L ( q ,   ϕ ) = 0 , Mathematical equation

where L(p1, ϕ1)×L(p2, ϕ2)L(q, ϕ)Mathematical equation is the operator norm from L(p1,ϕ1)(Rn)×L(p2,ϕ2)(Rn)Mathematical equation to L(q,ϕ)(Rn)Mathematical equation.

Proof of Proposition 2(i)   Let fL(p1,ϕ1)(Rn),Mathematical equation gMathematical equation

L ( p 2 , ϕ 2 ) ( R n ) , Mathematical equation and ε(0,1].Mathematical equation Then, from (14), it follows that [b,Iα]1(f,g)(x)-[b,Iα,ε]1(f,g)(x)=limη+0η<(|x-y|2+|x-z|2)12<ε(b(x)-b(y))f(y)g(z)(|x-y|+|x-z|)2n-αdydz.Mathematical equation

By Lemma 5 and ψςinc,Mathematical equationwe obtain:

| [ b , I α ] 1 ( f , g ) ( x ) - [ b , I α , ε ] 1 ( f , g ) ( x ) | ( B ( x , ε ) ) 2 | b ( x ) - b ( y ) | | f ( y ) g ( z ) | ( | x - y | + | x - z | ) 2 n - α d y d z ( B ( x , ε ) ) 2 ψ ( x , | x - y | ) | f ( y ) g ( z ) | ( | x - y | + | x - z | ) 2 n - α d y d z = k = 0 ( B ( x , 2 - k ε ) ) 2 \ ( B ( x , 2 - k - 1 ε ) ) 2 ψ ( x , | x - y | ) | f ( y ) g ( z ) | ( | x - y | + | x - z | ) 2 n - α d y d z Mathematical equation

k = 0 ψ ( x , 2 - k ε ) ( 2 - k - 1 ε ) ( B ( x , 2 - k ε ) ) 2 | f ( y ) g ( z ) | d y d z k = 0 ( 2 - k - 1 ε ) α + θ M ψ ( f , g ) ( x ) ε α + θ M ψ ( f , g ) ( x ) , a . e . x R n , Mathematical equation

for some θ(0,1].Mathematical equation Hence, by Theorem 2 and Lemma 6, we get [b,Iα]1(f,g)-[b,Iα,ε]1(f,g)L(q,ϕ )εα+θMψ(f,g)L(q,ϕ )Mathematical equation

ε α + θ f L ( p 1 , ϕ 1   ) g L ( p 2 , ϕ 2   ) . Mathematical equation

This proofs (i).

(ii) Let sup bB0=B(0,R0).Mathematical equation Then

| [ b , I α ] 1 ( f , g ) ( x ) - [ b , I α , ε ] 1 ( f , g ) ( x ) | Mathematical equation

( | x - y | 2 + | x - z | 2 ) 1 / 2 > R | b ( x ) - b ( y ) | | f ( y ) g ( z ) | ( | x - y | + | x - z | ) 2 n - α d y d z ( | x - y | 2 + | x - z | 2 ) 1 / 2 > R ( χ B 0 ( x ) + χ B 0 ( y ) ) ( | x - y | + | x - z | 1 t 2 n - α + 1 d t ) | f ( y ) g ( z ) | d y d z = 0 ( n ) 2 χ { R < ( | x - y | 2 + | x - z | 2 ) 1 / 2 < t } ( y , z , t ) Mathematical equation

( χ B 0 ( x ) + χ B 0 ( y ) ) | f ( y ) g ( z ) | t 2 n - α + 1 d y d z d t R ( ( B ( x , t ) ) 2 ( χ B 0 ( x ) + χ B 0 ( y ) ) | f ( y ) g ( z ) | d y d z ) 1 t 2 n - α + 1 d t . Mathematical equation

Denote

E 1 ( x ) R ( ( B ( x , t ) ) 2 χ B 0 ( x ) | f ( y ) g ( z ) | d y d z ) 1 t 2 n - α + 1 d t , Mathematical equation

E 2 ( x ) R ( ( B ( x , t ) ) 2 χ B 0 ( y ) | f ( y ) g ( z ) | d y d z ) 1 t 2 n - α + 1 d t . Mathematical equation

Then

| [ b , I α ] 1 ( f , g ) ( x ) - [ b , I α , ε ] 1 ( f , g ) ( x ) | E 1 ( x ) + E 2 ( x ) . Mathematical equation

By Hölder's inequality, then

( B ( x , t ) ) 2 | f ( y ) g ( z ) | d y d z | B ( x , t ) | 2 ( 1 | B | B ( x , t ) | f ( y ) | p 1 d y ) 1 / p 1 ( 1 | B | B ( x , t ) | g ( z ) | p 2 d z ) 1 / p 2 ϕ ( x , t ) 1 / p t 2 n f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) , Mathematical equation

Using (2) and (10), for large R,Mathematical equation we have

E 1 ( x ) χ B 0 ( x ) ϕ ( 0 , R ) 1 / q f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) . Mathematical equation

Then E1L(q,ϕ)χB0L(q,ϕ)ϕ(0,R)1/p˜fL(p1,ϕ1)gL(p2,ϕ2).Mathematical equation

Next, we estimate E2L(q,ϕ).Mathematical equation By Hölder's inequality, we get

E 2 = R ( B ( x , t ) χ B 0 ( y ) | f ( y ) | d y ) ( B ( x , t ) | g ( z ) | d z ) 1 t 2 n + 1 d t R ( B ( x , t ) χ B 0 ( y ) | f ( y ) | d y ) ( ϕ 2 ( 0 , t ) 1 p 2 t n g L ( p 2 , ϕ 2 ) ) 1 t 2 n + 1 d t = R ( B ( x , t ) χ B 0 ( y ) | f ( y ) | d y ) ϕ 2 ( 0 , t ) 1 p 2 g L ( p 2 , ϕ 2 ) 1 t n + 1 d t . Mathematical equation

If yB0B(x,t)Mathematical equation and tMathematical equation is large, by Remark 4, then

χ B ( y , t ) L Φ q , ϕ = χ B ( y , t ) L Φ ϕ 1 / q 1 ϕ ( 0 , t ) 1 / q 1 t α ϕ ( 0 , t ) 1 / q ψ ( 0 , t ) . Mathematical equation

By ϕ2ςdecMathematical equation and t>R,Mathematical equation then ϕ2(x,t)ϕ2(B0).Mathematical equation Hence

E 2 L ( q , ϕ ) R ( B ( x , t ) χ B ( , t ) ( y ) L ( q , ϕ ) χ B 0 ( y ) | f ( y ) | d y ) ( ϕ 2 ( 0 , t ) 1 / p 2 g L ( p 2 , ϕ 2 ) ) d t t n - α + 1 R s u p y B 0 χ B ( y , t ) L ( q , ϕ ) ( ϕ 1 ( B 0 ) 1 / p 1 | B 0 | f L ( p 1 , ϕ 1 ) ) ( ϕ 2 ( 0 , t ) 1 / p 2 g L ( p 2 , ϕ 2 ) ) d t t n - α + 1 Mathematical equation

R s u p y B 0 χ B ( y , t ) L Φ q , ϕ d t t n - α + 1 f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) ϕ ( B 0 ) 1 / p | B 0 | R 1 ϕ ( 0 , t ) 1 / p ψ ( 0 , t ) t n + 1 d t ϕ ( B 0 ) 1 / p | B 0 | f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) . Mathematical equation

By the almost increasing of rϕ(0,r)rn,Mathematical equation and ψςinc,Mathematical equationwe obtain

R 1 ϕ ( 0 , t ) 1 / p ψ ( 0 , t ) t n + 1 d t 1 ( ϕ ( 0 , R ) R n ) 1 / p ψ ( 0 , R ) R 1 t n - n / p + 1 d t 1 ( ϕ ( 0 , R ) R n ) 1 / p ψ ( 0 , R ) R n - n / p , Mathematical equation

which implies

[ b , I α ] 1 ( f , g ) - [ b , I α , ε , R ] 1 ( f , g ) L ( q , ϕ ) ( χ B 0 L ( q , ϕ ) ϕ ( 0 , R ) 1 / p ˜ + | B 0 | ( ϕ ( B 0 ) ) 1 / p ( ϕ ( 0 , R ) R n ) 1 / p ψ ( 0 , R ) R n - n / p ) f L ( p 1 , ϕ 1 ) g L ( p 2 , ϕ 2 ) . Mathematical equation

By (4) and the almost increasing of rϕ(0,r)rn,Mathematical equationthis means that ϕ(0,R)0,Mathematical equation and 1(ϕ(0,R)Rn)1/pψ(0,R)Rn-n/p0Mathematical equation as R,Mathematical equation we have (ii).

3 The Boundedness and Compactness of the Commutators of Multilinear Fractional Integrals

All the results obtained in Lemma 1 and Theorem 1 also hold for mMathematical equation-linear (m2)Mathematical equation operators. In fact, the proof of these results is similar to Theorem 1. We have the following results.

Let m2,0<α<mn.Mathematical equation The mMathematical equation-linear fractional integral operator Iα,mMathematical equation is defined by

I α , m ( f ) ( x ) = ( R n ) m i = 1 m f i ( y i ) ( i = 1 m | x - y i | ) m n - α d y . Mathematical equation(18)

where xRn,dy=dy1dym,Mathematical equation and f=(f1,,fm),Mathematical equation fi, i=1, 2, , m, Mathematical equationare locally integrable functions.

The boundedness of the mMathematical equation-linear fractional integral operator Iα,m,Mathematical equation is bounded from L(p1,ϕ1)(Rn)××L(pm,ϕm)(Rn)Mathematical equation to L(p˜,ϕ)(Rn),Mathematical equationthe proof of these results is similar to Lemma 4.1 of Ref. [13].

Let bjLloc1,j=1,,m,Mathematical equation we define the commutators Iα,mbMathematical equation of m-linear fractional integral operator as follows:

I α , m b ( f ) ( x ) = i = 1 m I α , m b i , i ( f ) ( x ) = i = 1 m ( R n ) m ( b i ( x ) - b i ( y i ) ) i = 1 m f i ( y i ) ( i = 1 m | x - y i | ) m n - α d y , Mathematical equation

where

I α , m b i , i ( f ) ( x ) = : b i ( x ) I α , m ( f 1 , , f i , , f m ) ( x ) - Ι α , m ( f 1 , , b i f i , , f m ) ( x ) . Mathematical equation

The boundedness of the commutators of m-linear fractional integral operator Iα,mbMathematical equation, our main result, is the following.

Theorem 3   Let p,pi,q(1,),i=1,,m,p<q,Mathematical equation such that i=1m1pi=1p=1q+αn,α Mathematical equation(0,mn),Mathematical equation and ϕ,ϕi,ψ:Rn×Mathematical equation

( 0 , ) ( 0 , ) , i = 1 , , m , Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation satisfies:

i = 1 m ϕ i 1 / p i = ϕ 1 / p , Mathematical equation(19)

(i) Assume that ϕ,ϕiςdecMathematical equation and ψςincMathematical equation, ψMathematical equation satisfies (2), ϕ,ϕiMathematical equation satisfy (5) and there exist positive constants C0,C1Mathematical equation and an exponent p˜(p,q],Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation such that

0 r t α - 1 d t ϕ ( x , r ) 1 / p + r t α - 1 ϕ ( x , t ) 1 / p d t C 0 ϕ ( x , r ) 1 / p ˜ , Mathematical equation(20)

ψ ( x , r ) ϕ ( x , r ) 1 / p ˜ C 1 ϕ ( x , r ) 1 / q Mathematical equation(21)

If bjε(1,ψ)(Rn),Mathematical equation then Iα,mbMathematical equation is well defined for all fiL(pi,ϕi)(Rn).Mathematical equation That is, for all fiL(pi,ϕi)(Rn),Mathematical equation i,j=1,,m,Mathematical equationsuch that

I α , m b ( f ) L ( q , ϕ ) b ( ε ( 1 , ψ ) ) m i = 1 m f i L ( p i , ϕ i ) , Mathematical equation(22)

where b(ε(1,ψ))m:=supj=1,,mbjε(1,ψ).Mathematical equation

(ii) Conversely, assume that ϕ,ϕi,i=1,,mMathematical equation satisfy (2), and that there exists a positive constant C2,Mathematical equation for all xRnMathematical equation and r(0,),Mathematical equation such that

C 2 ψ ( x , r ) r α ϕ ( x , r ) 1 / p ϕ ( x , r ) 1 / q . Mathematical equation(23)

If Iα,mbMathematical equation is bounded from L(p1,ϕ1)(Rn)××L(pm,ϕm)(Rn)Mathematical equation to L(q,ϕ)(Rn),Mathematical equation then bjε(1,ψ)(Rn), j=1,,m,Mathematical equation such that

b j ε ( 1 , ψ ) I α , m b L ( p 1 , ϕ 1 ) × × L ( p m , ϕ m ) L ( q , ϕ ) . Mathematical equation

The compactness of the commutators of the m-linear fractional integral operator Iα,mbMathematical equation, our main result, is the following.

Theorem 4   Let p, pi(1, ), i=1, , m, p < q,Mathematical equation i=1m1pi=1p=1q+αn,Mathematical equationα(0,mn),Mathematical equation and ϕ,ϕi:Rn×(0,)(0,),Mathematical equation

i = 1 , , m . Mathematical equation Assume the same condition as Lemma 1. Assume also that ϕ,ϕiMathematical equation and ψMathematical equation satisfy (2) and (13), respectively. If bjCcomp(Rn)¯ε(1, ψ)(Rn),j=1,,m,Mathematical equation then Iα,mbMathematical equation are compact from L(p1,ϕ1)(Rn)××L(pm,ϕm)(Rn)Mathematical equation to L(q,ϕ)(Rn).Mathematical equation

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