Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 30, Number 5, October 2025
Page(s) 471 - 478
DOI https://doi.org/10.1051/wujns/2025305471
Published online 04 November 2025

© Wuhan University 2025

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

The setting for this paper will be n-dimensional Euclidean space, Rn. A compact convex set with nonempty interior is called a convex body. A polytope in Rn is the convex hull of a finite set of points in Rn. The Minkowski problem for electrostatic q-capacity is a very significant variant among Minkowski problems, regarding the research and applications of the Minkowski problems, we can refer to Refs. [1-18]. For the Lp Minkowski problem for electrostatic q-capacity, we refer to Refs. [19-32] and reference therein. When q=n, the n-capacity is also known as the logarithmic capacity. The logarithmic capacity in the Euclidean plane R2 has been researched systemically because of its function in two-dimensional potential theory, which is the study of planar harmonic functions in mathematics and mathematical physics (see e.g., Refs. [33-39]); Nevertheless, as a result of its nonlinear nature, the planar logarithmic capacity in higher dimensional extension has gotten comparatively little attention (see Refs. [20,37]).

The collection of convex bodies will be denoted by Kn. For 1<q<n, the electrostatic q-capacity of a compact set K is defined by (see Ref. [21])

C q ( K ) = i n f { | v | q d x :   x C c ( R n )   a n d   v χ K } , (1)

where Cc(Rn) denotes the set of smooth functions with compact supports, and χK is the characteristic function of K. For KKn, its electrostatic q-capacitary measure μq(K,) is a finite Borel measure on Sn-1, defined for Borel ωSn-1 and q(1,n) by

μ q ( K , ω ) = x g - 1 ( ω ) | V ( x ) | q d n - 1 ( x ) , (2)

where g-1: Sn-1K denotes the inverse Gauss map and V is the q-equilibrium potential of K, see Ref. [38] for details.

Jerison [34] solved the Minkowski problem for classical capacity (q=2) and established the necessary and sufficient condition for existence of its solution. It is surprising to note that these conditions are the same as those in the classical Minkowski problem. Caffarelli et al[39] settled the uniqueness of its solutions, while the regularity depends on the regularity of solutions to the Monge-Ampère equation (see Ref. [40]). Colesanti et al[21] demonstrated the existence and regularity of the solution for q(1, 2) as well as the uniqueness of the solution when q(1, n). Akman et al[41] solved the existence of the solution for q(2, n).

For KKn, the support function of K is defined by hK(v)=max{xv: xK}, where xv denotes the standard inner product in Rn. The support function is positively homogeneous of degree 1, and is usually restricted to Sn-1. The collection of convex bodies containing the origin o in their interiors will be denoted by Kon. Firey[42] first proposed the concept of the Lp Minkowski sum of convex bodies in the 1962. The Lp q-capacitary measure was introduced by Du and Xiong[28], and they also began to study the Lp Minkowski problem for electrostatic q-capacity.

Suppose pR and q(1, n), the Lp q-capacitary measure of Cn(K) is a finite Borel measure on Sn-1, defined for any Borel ωSn-1 by

μ p , q ( K , ω ) = ω h K ( v ) 1 - p d μ q ( K , v ) . (3)

The Lp q-capacitary measure is resulted from the variation of the q-capacity functional of the Lp Minkowski sum of convex bodies. For p[1, ) and K,LKon (see Refs. [26,28]),

d d t C q ( ( 1 - t ) K + p t L ) | t = 0 + = q - 1 p S n - 1 h L p ( v ) d μ p , q ( K , v ) . (4)

The L p Minkowski problem for q -capacity. Given a finite Borel measure µ on Sn-1, what are the necessary and sufficient conditions on µ so that µ is the Lp q-capacitary measure μp,q(K,) of a convex body K in Rn?

Wang et al [25] and Xiong et al [36] studied the discrete logarithmic Minkowski problem for q-capacity for p=0 and q(1, n). Zou et al[28] solved the Lp Minkowski problem for q-capacity for p(1, ) and q(1, n). Xiong et al[26] solved the Lp discrete Minkowski problem for q-capacity for p(0, 1) and q(1, 2).This conclusion was augmented for general measures by Feng et al[23].

For KKn, Akman et al[43] proved that there exists a unique solution V=VK to the boundary value problem of n-Laplace equation:

{ ( | v | n - 2 v ) = 0 i n   R n \ K , v = 0 o n   K , v ( x ) = F ( x ) + a + o ( 1 ) a s   | x | ,

where aR\{0} is uniquely determined by K, and

F ( x ) = ( n ω n ) 1 1 - n l o g | x | + 1

is the functional solution to n-Laplace equation, ωn denotes the volume of unit ball Bn in Rn. Then, the logarithmic capacity Cn(K) of K is defined by

C n ( K ) = e x p ( - a ( n ω n ) 1 1 - n ) . (5)

Furthermore, the Hadamard variational formula is established:

d C n ( K + t L ) d t | t = 0 + = ( n ω n ) 1 n - 1 C n ( K ) S n - 1 h L ( v ) d μ n ( K , v ) . (6)

Henceforth, the logarithmic capacitary measure μn(K,) of K has emerged. By (6) and the positive homogeneity of Cn(K), it follows that

( n ω n ) 1 1 - n = S n - 1 h K ( v ) d μ n ( K , v ) . (7)

Following Xiao[44], for KKn, the logarithmic capacitary measure μn(K,) of K is a finite Borel measure on Sn-1, defined for Borel ωSn-1 by

μ n ( K , ω ) = 1 ω n g - 1 ( ω ) | V ( x ) | n d n - 1 ( x ) . (8)

The Minkowski problem for the logarithmic capacity was introduced by Akman et al[43], who also solved its existence and uniqueness. For p(0, 1), Lu et al[24] extended the q-index of the Lp q-capacitary measure to q=n, and solved its associated Lp Minkowski problem. For more other works related to the Lp Minkowski problem for the logarithmic capacity, we refer to Chen[5,19].

The study of the Orlicz Minkowski problem for q-capacity is of great importance, especially in light of the classical Minkowski problem and its numerous extensions. The Orlicz additions were proposed by Gardner et al[45] and independently by Xi et al[46], in order to provide the foundation of the newly initiated Orlicz-Brunn-Minkowski theory for convex bodies starting from the works of Lutwak et al[47-48]. The Orlicz theory is in great demand and is rapidly developing (see e.g., Refs. [49-54] ). Hong et al[55] combined the q-capacity for q(1, n) with the Orlicz addition of convex domains to develop the q-capacitary Orlicz-Brunn-Minkowski theory. Ji et al[56] demonstrated the existence part of the discrete Orlicz Minkowski problem for q-capacity when q(1, 2). Xiong et al[57] solved the existence of solutions to the Orlicz Minkowski problem for q-capacity for q(n, ). Hu and Li[58] proved the existence of the Orlicz Minkowski problem for logarithmic capacity (q=n).

The Orlicz Minkowski problem for the logarithmic capacity. Given a function ϕ and finite Borel measure µ on Sn-1, what are the necessary and sufficient conditions on µ such that there exists a convex body K, satisfying

α d μ n ( K , ) = d μ φ ( h K ) ,

where α>0 is a constant?

Our main goal is to solve the Orlicz Minkowski problem for the logarithmic capacity. It is worth noting that Hu and Li [58] first studied the Orlicz Minkowski problem for the logarithmic capacity. However, we consider a different extremal problem, which may contribute to a more concise proof process. Meanwhile, for discrete measures, we remove their restrictive condition that the measure μ does not have any pair of antipodal point masses, without using an approximation scheme. Additionally, we generalize the Orlicz Minkowski problem for the logarithmic capacity to general measures by applying an approximation scheme.

Theorem 1   Suppose µ is a finite Borel measure on Sn-1 which is not concentrated on any closed hemisphere and that φ: (0,)(0,) is continuous decreasing and φ(s) as s0+. Then there exists a convex body K containing the origin and a constant α>0, such that

α d μ n ( K , ) = d μ φ ( h K ) .

This article is structured as follows. In Section 1, we introduce some basic facts about convex body and the logarithmic capacity. In Section 2, we investigate an extreme problem and elucidate the connection between its solution and the solution to the Orlicz Minkowski problem for the logarithmic capacity, and complete the proof of the main result.

1 Preliminaries

For basic facts on convex bodies, we recommend the books by Gardner[59], Gruber[60], Schneider[61].

Denote Bn is the standard unit ball of Rn and denote its surface by Sn-1. For a set ARn, int A and A denote the interior and boundary of A, respectively. For a compact convex set K,

d ( K ) = s u p { | x - y | :   x , y K }

is the diameter of K. Write S(K, ·) for the classical surface area measure of K. For KKn, the support hyperplane H(K, v) in the direction vSn-1 is defined by

H ( K , v ) = { x R   n :   x v = h ( K , v ) } .

The support set F(K, v) in the direction vSn-1 is defined by

F ( K , v ) = K H ( K , v ) .

For nonnegative continuous function f defined on Sn-1, the Aleksandrov body [f] is defined by

[ f ]   = u S n - 1 { x   n :   x v f ( v ) } .

This collection also called the Wulff shape associated with f. Obviously, [f]Kon and K=[hK] for every KKon.

Suppose the unit vectors v1,,vN are not concentrated on any closed hemi-sphere. Let P(v1,,vN) be the set with PP(v1,,vN) such that for fixed α1,,αN0,

P = j = 1 N { x   n :   x v j α j } .

If PP(v1,,vN), then P has at most N facets (i.e., (n-1)-dimensional faces) and the collection of the unit outer normals of P is a subset of {v1,,vN}. Let PN(v1,,vN) be the subset of P(v1,,vN) such that a polytope PPN(v1,,vN) if PP(v1,,vN) and P has exactly N facets. A finite subset U of Sn-1 is said to be in general position if U is not concentrated on any closed hemisphere of Sn-1 and any k elements of V, 1kn, are linearly independent. It is of great importance that the outer unit normals of the polytope are in general position, since any convex body can be approximated by these polytopes.

In the following, we list some properties about the logarithmic capacity. For more details, see, e.g., Refs. [5,19,24,43-44,62].

Let KKn. First, by the definition of the logarithmic capacity, Cn(K) is positively homogeneous of degree 1, that is, Cn(tk)=tCn(k), for t>0. Second, the functional Cn is translation invariant, namely, Cn(K+x)=Cn(K), for xRn. Third, if a sequence of compact convex sets {Ki}(i=1)() converges to a compact set K, then either K is a single point or limiCn(Ki)=Cn(K)>0.

Since μq(K,) is absolutely continuous with respect to the surface measure S(K,). The logarithmic capacitary measure μn is positively homogeneous of degree -1, that is, μn(tK,)=t-1μn(K,), for t>0.

The following Lemma will be used. For its proof, we can refer to the Theorem 3.2 in Ref. [24].

Lemma 1   Let IR be an interval containing o in its interior, and assume that ht(v)=h(t,v): I×Sn-1(0,) is continuous, such that the convergence

h ' ( 0 , v ) = l i m t 0 h ( t , v ) - h ( 0 , v ) t

is uniform on Sn-1. Then

d C n ( [ h t ] ) d t | t = 0 = ( n ω n ) 1 n - 1 C n ( [ h 0 ] ) S n - 1 h ' ( 0 , v ) d μ n ( [ h 0 ] , v ) . (9)

2 Proof of Main Result

In this section, we first study the Orlicz Minkowski problem for logarithmic capacity for discrete measures and then study the general measures by means of approximation methods.

Suppose that φ:(0,)(0,) be a continuous, decreasing function and satisfying φ(s), as s0+. Define the function ϕ by

ϕ ( t ) = 0 t 1 φ ( s ) d s , t > 0 . (10)

Since φ is decreasing, it follows that the derivative of ϕ is increasing and therefore ϕ is convex.

Suppose μ is a discrete Borel measure on Sn-1 such that μ=k=1Nckδvk, where c1,,cN(0,) and δvk denotes the delta measure that is concentrated at the point vk. For a polytope Q containing the origin, define

Ψ μ ( Q ) = S n - 1 ϕ ( h Q ( v ) ) d μ ( v ) = k = 1 N c k ϕ ( h Q ( v k ) ) . (11)

In the following, we study the extremal problem

i n f { Ψ μ ( Q ) :   Q P ( v 1 , , v N ) , C n ( Q ) = 1 } , (12)

and show the relationship between the extreme problem and the Orlicz Minkowski problem for logarithmic capacity for the discrete measure μ.

We focus on the existence of the extreme problem for Ψμ, and demonstrate that there is a solution to the Orlicz Minkowski problem for logarithmic capacity for the discrete measure μ. To complete the proof of existence, Lemma 2 will be required, for its proof can refer to the Theorem 4.3 in Ref. [13].

Lemma 2   If the unit vectors v1,,vN are in general position,PiP(v1,,vN) with oP and d(Pi) is not bounded, then V(Pi) is not bounded.

Lemma 3   Suppose μ is a finite discrete Borel measure on Sn-1. If the support set of μ is in general position, then there exists an n-dimensional polytope P solving the extremal problem (12).

Proof   Let

β = i n f { Ψ μ ( Q ) :   Q P ( v 1 , , v N ) , C n ( Q ) = 1 } .

Take a minimizing sequence {Pi}i for the extremal problem (12), such that PiP(v1,,vN), Cn(Pi)=1 and

l i m i Φ μ ( P i ) = β .

We show that the sequence {Pi}i is bounded. Assume that {Pi}i is not bounded, by Lemma 2, we have V(Pi) is not bounded. On the other hand, from the fact that Cn(Pi)=1 and the isocapacitary inequality for logarithmic capacity (Theorem 4.1 in Ref. [44]), i.e.,

( V ( P i ) ω n ) 1 n C n ( P i ) ,

we have V(Pi)ωn, which is a contradiction. Thus, {Pi}i is bounded.

According to the Blaschke selection theorem, {Pij}j is a convergent subsequence of {Pi}i that converges to P.

In the following, we show dimP=n.

If dimP=n-1, then there exists a vi0{v1,,vN} such that Pvi0 and thus,

h P ( v i 0 ) = h P ( - v i 0 ) = 0 .

Then the surface measure S(P,) is concentrated at the points {±vi0}. Since the logarithmic capacitary measure μn(P,) is absolutely continuous with respect to S(P,), so μn(P,) is also concentrated at the points {±vi0}. By (5) and (7), we get Cn(P)=0 or Cn(P)=, which contradicts that Cn(P)=1.

If dimPn-2, then S(P,)0. Since the logarithmic capacitary measure μn(P,) is absolutely continuous with respect to S(P,), we have μn(P,)0. By (5) and (7), we get Cn(P)=0 or Cn(P)=, which is a contradiction.

Therefore, dimP=n. This completes the proof.

Lemma 4   Let K be a convex body in Rn with oKB(o,r). Then there exists a constant c>0, such that for Borel set ωSn-1,μn(K,ω)cS(K,ω).

Proof   According to Theorem 3.2 of Xiao[62], there exists a constant d>0 depending only on r and n, such that |V(x)|d almost everywhere on K with respect to dn-1. Then, by (8) we get

μ n ( K , ω ) = 1 ω n g - 1 ( ω ) | V ( x ) | n d n - 1 ( x ) d n ω n S ( K , ω )                  = c S ( K , ω ) ,

where c=dnωn.

Lemma 5   The solution P contains the origin in its interior.

Proof   Suppose that oP. Without loss of generality, let F(P,vi0) be a facet of P, where vi0{v1,,vN}. Thus hP(vi0)=0. For sufficiently small t>0, we write

P t = k = 1 N { x   n :   x v k h P ( v k ) + t δ v i 0 } ,

τ ( t ) P t = P t C n ( P t ) .

Then Cn(τ(t)Pt)=1,τ(t)PtP, as t0+, and hPt(vk)=hP(vk)+tδvi0, k=1,,N.

From (10), (11), Lemma 1, the fact that hP(vi0)=0 and μn(P,{vi0})cS(P,{vi0})>0 by Lemma 4, we have

t | t = 0 + Ψ μ ( τ ( t ) P t ) = k = 1 N c k ϕ ' ( h P ( v k ) ) ( τ ' ( 0 ) h P ( v k ) + δ v i 0 ) = k = 1 N c k 1 φ ( h P ( v k ) ) ( - ( n ω n ) 1 n - 1 j = 1 N δ v i 0 μ n ( P , { v j } ) h P ( v k ) + δ v i 0 ) = c i 0 φ ( h P ( v i 0 ) ) - ( n ω n ) 1 n - 1 ( k = 1 N c k h P ( v k ) φ ( h P ( v k ) ) ) μ n ( P , { v i 0 } ) < 0 .

Then there exists a t0>0 such that Ψμ(τ(t0)Pt0)<Ψμ(P), which contradicts Ψμ(P) is the minimum. Therefore, the origin must be inside the solution P.

Lemma 6   The solution P has exactly N facets whose outer normal vectors are v1,,vN.

Proof   We employ the method of proof by contradiction. Suppose vi0{v1,,vN} such that the support set F(P,vi0)=PH(P,vi0) is not a facet of P. For sufficiently small t>0, let

P t = P { x R   n :   x v i 0 h P ( v i 0 ) - t }

and

τ P t = τ ( t ) P t = C n ( P t ) - 1 P t .

Thus, Cn(τPt)=1 and τPtP, as t0+ and hPt(vk)=hP(vk)-tδvi0,k=1,,N.

From (10), (11) and Lemma 1, we get t|t=0+Ψμ(τ(t)Pt)

= k = 1 N c k ϕ ' ( h P ( v k ) ) ( τ ' ( 0 ) h P ( v k ) - δ v i 0 )

= k = 1 N c k 1 φ ( h P ( v k ) ) ( ( n ω n ) 1 n - 1 j = 1 N δ v i 0 μ n ( P , { v j } ) h P ( v k ) - δ v i 0 )

= - c i 0 φ ( h P ( v i 0 ) ) + ( n ω n ) 1 n - 1 ( k = 1 N c k h P ( v k ) φ ( h P ( v k ) ) ) μ n ( P , { v i 0 } ) .

Since F(P,vi0) is not a facet of P, we calculate that μn(P,{vi0})=0. Thus

t | t = 0 + Φ μ ( τ ( t ) P t ) < 0 .

Then there exists a t0>0 such that Ψμ(τ(t0)Pt0)<Ψμ(P), which contradicts Ψμ(P) is the minimum. Thus, P has exactly N facets.

Lemma 7   If the polytope PPN(v1,,vN) and oint P is the solution to the extremal problem (10), then

α d μ n ( P , ) = d μ φ ( h P ) ,

where α=(nωn)1n-1Sn-1hPφ(hP)dμ.

Proof   For a1,,aNR and small |t|, let polytope

P t = k = 1 N { x   n :   x v k h P ( v k ) + t a k } .

Since v1,,vN are normal vectors of P, there exists an ε>0, such that for any |t|<ε,v1,,vN are normals vectors of Pt. Then hPt(vk)=hP(vk)+tak,k=1,,N,|t|<ε.

Let

τ ( t ) P t = P t C n ( P t ) .

Since Cn(τ(t)Pt)=1,τ(t)PtP as t0 and P is the solution to the extremal problem, which gives

0 = t | t = 0 Ψ μ ( τ ( t ) P t )     = k = 1 N c k t | t = 0 ϕ ( τ ( t ) h P t ( v k ) )     = k = 1 N c k ϕ ' ( τ ( t ) h P t ( v k ) ) | t = 0 [ τ ' ( t ) h P t ( v k ) | t = 0 + τ ( t ) a k | t = 0 ]     = k = 1 N c k ϕ ' ( h P t ( v k ) ) | t = 0 [ τ ' ( 0 ) h P ( v k ) + a k ] .

Lemma 1   and Cn(P)=1 yields

τ ' ( 0 ) = - C n ( P t ) - 2 | t = 0 l i m t 0 C n ( P t ) - C n ( P ) t           = - ( n ω n ) 1 n - 1 C n ( P ) S n - 1 l i m t 0 h P t ( v ) - h P ( v ) t d μ n ( P , v )           = - ( n ω n ) 1 n - 1 j = 1 N a j μ n ( P , { v j } ) .

Hence,

0 = k = 1 N c k 1 φ ( h P ( v k ) ) ( - ( n ω n ) 1 n - 1 h P ( v k ) j = 1 N a j μ n ( P , { v j } ) + η k )

    = k = 1 N c k a k φ ( h P ( v k ) ) - ( n ω n ) 1 n - 1 ( k = 1 N c k h P ( v k ) φ ( h P ( v k ) ) ) ( j = 1 N a j μ n ( P , { v j } ) )     = k = 1 N a k ( c k φ ( h P ( v k ) ) - ( n ω n ) 1 n - 1 ( j = 1 N c j h P ( v j ) φ ( h P ( v j ) ) ) μ n ( P , { v k } ) ) .

Since akR,k=1,,N are arbitrary, we conclude that

α μ n ( P , { v k } ) = c k φ ( h P ( v k ) ) , k = 1 , , N ,

where

α = ( n ω n ) 1 n - 1 j = 1 N c j h P ( v j ) φ ( h P ( v j ) ) = ( n ω n ) 1 n - 1 S n - 1 h P φ ( h P ) d μ .

Then

α μ n ( P , ) = d μ φ ( h P ) ,

as desired.

Now, we focus on the Orlicz Minkowski problem for logarithmic capacity for general measures. The following Lemma (see Lemma 4.1 in Ref. [57]) will be needed.

Lemma 8   Suppose that μ is a finite Borel measure on Sn-1 which is not concentrated on any closed hemisphere. Then there exists a sequence of discrete measures μi such that supp μi are in general position and μiμ, weakly.

In the end, we have completed the proof of the main theorem.

Proof of Theorem 1   By Lemma 8, let {μi} be the discrete measure sequence such that supp μi are in general position and μiμ, weakly. By Lemmas 3, 5, 6 and 7, there exists a polytope Pi containing the origin in its interior, such that Pi is the solution to the extreme problem

i n f { S n - 1 ϕ ( h Q ( v ) ) d μ i ( v ) :   s u p p   S Q s u p p   μ i , C n ( Q ) = 1 }

and

α i d μ n ( P i , ) = d μ i φ ( h P i ) ,

where αi=(nωn)1n-1Sn-1hPiφ(hPi(v))dμi(v).

Next, we show that {Pi} is bounded. Suppose that {Pi} is not bounded, by Lemma 2, we have V(Pi) is not bounded. On the other hand, from the fact that Cn(Pi)=1 and the isocapacitary inequality for logarithmic capacity (Theorem 4.1 in Ref. [44]), i.e.,

( V ( P i ) ω n ) 1 n C n ( P i ) ,

we have V(Pi)ωn, which is a contradiction. Thus, {Pi} is bounded.

By the Blaschke selection theorem, there exists a convergent subsequence {Pij} of {Pi} such that {Pij}K. Then oK. It remains to show dim K=n. With similar argument in the proof of Lemma 3, we conclude that dim K=n.

Finally, we show that K is the solution to the Orlicz Minkowski problem for μ. Since Pi is the solution to the Orlicz Minkowski problem for μi, we have

α i d μ n ( P i , ) = d μ i φ ( h P i ) .

Combined this with PiK and μiμ weakly, it follows that μn(Pi,)μn(K,),hPihK uniformly on Sn-1 and αiα. Then

α d μ n ( K , ) = d μ φ ( h K ) ,

where α=(nωn)1n-1Sn-1hKφ(hK(v))dμ(v), as desired.

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