Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 30, Number 6, December 2025
Page(s) 535 - 539
DOI https://doi.org/10.1051/wujns/2025306535
Published online 09 January 2026

© Wuhan University 2025

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

In 1897, Minkowski posed the Minkowski problem[1]. Minkowski[1-2] resolved its discrete 3D case. For arbitrary measures, Aleksandrov[3], Fenchel and Jessen[4] established complete solutions via variational methods, requiring the convex body's centroid to lie at the origin.

Lutwak[5] established the Lp-Brunn-Minkowski theory, formulating the Lp Minkowski problem[6-9]. Further generalization emerges through Orlicz-Brunn-Minkowski theory[10-14], extending the Lp framework[15].

Recent studies have extended Minkowski problems to Gaussian spaces. Huang et al[16] introduced the Gaussian surface area measure Sγn,K, establishing the Gaussian-Minkowski problem with existence and uniqueness in classical cases. Feng et al[17] proposed Lp Gaussian surface area measures and corresponding Minkowski problems, proving existence in normalized settings.

Let R  n denote the n-dimensional Euclidean space. Let n denote a vector in R  n. The s-Gaussian probability measure γns for ERn and s(0,) is outlined in Ref. [18] as follows:

γ n s ( E ) = 1 C s , n E ( 1 - s | x | 2 2 ) + 1 s d x (1)

where Cs,n:=nωn22snβ(1s+1,n2), and ωn is the volume of the unit ball. When s0+, γns is the classical Gaussian probability measure

γ n ( E ) = 1 ( 2 π ) n E e - | x | 2 2 d x

The generalized Gaussian probability space[19-20] features the generalized Gaussian density gα ,q. Ref. [21] introduced a generalized Gaussian surface area measure. Moreover, Liu et al[21] proposed the generalized Gaussian-Minkowski problem and established the existence and uniqueness of solutions in the smooth case.

Definition 1   Let p>1, s>0 and KKon. The Lp,s-Gaussian surface area measure of K, denoted by Sγns,p,K, is a Borel measure on Sn-1 given by

S γ n s , p , K ( η ) = 1 p C s , n v K - 1 ( η ) ( x v K ( x ) ) 1 - p ( 1 - s | x | 2 2 ) + 1 s d    n - 1 ( x )   (2)

for any Borel measurable ηSn-1. When s0+, then the Lp,s-Gaussian surface area measure is the Lp-Gaussian surface area measure.

The L p , s -Gaussian-Minkowski Problem: If p>1, given a finite Borel measure μ on the Sn-1, what is the sufficient and necessary condition on the measure μ so that there exists a convex body KKon and α(0,1n) such that μ=Sγns,p,Kγns(K)1-α.

The following theorem present a solution to the Lp,s-Gaussian-Minkowski problem for the case of even measures.

Theorem 1   Suppose μ is a non-zero finite even Borel measure not concentrated in any closed hemisphere and α(0,1n). Then there exists an o-symmetric convex body KKen for s(0,) such that μ=Sγns,p,Ksγns(Ks)1-α.

1 Preliminaries

We introduce some notations and, for ease of reference, summarize some basic properties of convex bodies. For comprehensive treatments of convex body theory, we refer readers to the texts by Gardner[22], Gruber[23], and Schneider[24], etc.

Let xR  n, the norm of a vector x is given by |x|=xx, x¯ denotes x|x|. The unit sphere in Rn is denoted by Sn-1. Let C(Sn-1) represent the set of continuous functions on Sn-1. Furthermore, Ce+(Sn-1) denotes the set of even, positive, continuous functions on Sn-1. For a finite measure μ on Sn-1, the total mass of μ is denoted by |μ|=μ(Sn-1).

1.1 Convex Bodies

The set of convex bodies (compact convex subsets) in R  n is denoted by Kn, the set of convex bodies containing the origin in their interiors is denoted by Kon, and KenKon denotes the set of origin-symmetric convex bodies. The unit ball centered at the origin in Rn is denoted by B n, and its volume by ωn. K denotes the boundary of KKn.

The support function, hK: Sn-1R, of a nonempty compact convex set K, is the continuous function on the unit sphere Sn-1, defined by hK(u)=max{ux: xK}. The radial function, ρK: Sn-1R for K is the continuous function, defined by ρK(x)=max{λ: λxK}.

For KKon, the polar body K* of K is defined by K*={xR n: yK, xy1}.

Let hC+(Sn-1), the Wulff shape [h] associated with h be defined as [h]={xR n: xvh(v),vSn-1}. The collection of nonempty compact convex sets can be viewed as a metric space with the Hausdroff metric, where the Hausdorff distance between K and L is defined by

d ( K , L ) = m i n { t 0 :   K L + t B n , L K + t B n } .

1.2 The Radial Gauss Map of a Convex Body

For KKon and each vSn-1, the hyperplane

H K ( v ) = { x R   n :   x v = h K ( v ) }

is called the supporting hyperplane to K with unit normal v. For σK, the Gaussian image of σ is defined by

v K ( σ ) = { v S n - 1 :   x H K ( v )   f o r   s o m e   x σ } S n - 1 .

For ηSn-1, the reverse Gaussian image of η is defined by vK-1(η)={xK: xHK(v) for some vη}K.

Huang et al[25] gave the definitions of radial Gaussian image. For KKon and ηSn-1, the radial Gaussian image αK(u) is the set of outer unit normals of K from the boundary points ρK(u)u, for some uη; that is,

α K ( η ) = u η { v S n - 1 :   ρ K ( u ) u v = h K ( v ) } .

Denote ωKSn-1 as the set of uSn-1 such that αK(u) contains more than one point; that is, the point ρK(u)uK has more than one outer unit normal. We now define the radial Gauss map αK: Sn-1\ωKSn-1, satisfying αK({u})={αK(u)}.

2 Variational Formulas for the Lp,s-Gaussian Surface Area Measure

In this section, we derive the variational formula for the Lp,s-Gaussian surface area measure.

Lemma 1   (Ref.[16], Lemma 3.2) Let KKon and gC(Sn-1). Suppose δ>0 is sufficiently small so that for each t(-δ,δ), there is ht=hK+tg>0. Then,

l i m t 0 ρ [ h t ] ( u ) - ρ K ( u ) t = g ( α K ( u ) ) h K ( α K ( u ) ) ρ K ( u )

for almost all uSn-1 with respect to spherical Lebesgue measure. Moreover, there exists a constant M>0, such that

| ρ [ h t ] ( u ) - ρ K ( u ) | < M | t | (3)

for all uSn-1 and t(-δ,δ).

Theorem 2   Let KKon, s(0,), gC(Sn-1). Then,

l i m t 0 γ n s ( [ ( h K p + t g ) 1 p ] ) - γ n s ( K ) t = S n - 1 g d S γ n s , p , K .

Proof   Let ht=(hKp+tg)1p, then

h t = ( h K p + t g ) 1 p = h K + 1 p h K p   ( 1 p - 1 ) g t + o ( t ) = h K + 1 p h K 1 - p g t + o ( t ) , (4)

where o(t) is the same order infinitesimal of t. It is evident that [ht]Kon when t is sufficiently small. By the definition of the s-Gaussian probability measure in (1) and employing polar coordinates, we obtain the following expression:

γ n s ( [ h t ] ) = 1 C s , n [ h t ] ( 1 - s | x | 2 2 ) + 1 s d x = 1 C s , n S n - 1 0 ρ [ h t ] ( u ) ( 1 - s | r u | 2 2 ) + 1 s r n - 1 d r d u . (5)

Denote F(t)=0t(1-s|ru|22)+1srn-1dr. By the mean value theorem and (3), we have

| F ( ρ [ h t ] ( u ) ) - F ( ρ K ( u ) ) | = | F ' ( θ ) | | ρ [ h t ] ( u ) - ρ K ( u ) | M | F ' ( θ ) | | t | ,

where θ is between ρ[ht](u) and ρK(u). Therefore, by definition of F, we have |F'(θ)| is bounded from above by some constant M1. Furthermore, there exists M2=M1M>0 such that

| F ( ρ [ h t ] ( u ) ) - F ( ρ ( u ) ) | M 2 t

Together with (5), the dominated convergence theorem, Lemma 1, (4) and (2), we attain

l i m t 0 γ n s ( [ ( h K p + t g ) 1 p ]   ) - γ n s ( K ) t = l i m t 0 1 C s , n S n - 1 1 t ρ K ( u ) ρ [ h t ] ( u ) ( 1 - s | r u | 2 2 ) + 1 s r n - 1 d r d u = 1 C s , n S n - 1 1 p h K 1 - p ( u ) g ( α K ( u ) ) ( 1 - s ρ K ( u ) 2 2 ) + 1 s ρ K ( u ) n h K ( α K ( u ) ) d u = 1 C s , n ' K 1 p ( x v K ( x ) ) 1 - p g ( v K ( x ) ) ( 1 - s | x | 2 2 ) + 1 s d n - 1 ( x ) = S n - 1 g ( u ) d S γ n s , p , K ( u ) ,

which is the desired conclusion.

3 The Lp,s-Gaussian-Minkowski Problem and Its Solution

In this section, we focus on the normalized version of the Lp,s-Gaussian-Minkowski problem for even measure when s(0,). For 0<α<1n and p>1, we first transform the problem of the existence of solutions to the Lp,s-Gaussian-Minkowski problem into the following maximisation problem:

s u p { F s ( f ) :   f C e + ( S n - 1 ) } (6)

where Fs: Ce+(Sn-1)R is given for fCe+(Sn-1) by

F s ( f ) = 1 α γ n s ( [ f ] ) α - S n - 1 f p d μ (7)

For KKen, denote Fs(K)=Fs(hK).

Lemma 2   Let 0<α<1n and p>1. If an even function fs is a maximizer to the optimization problem (6), then fs must be the support function of an o-symmetric convex body; that is, there exists an o-symmetric convex body KsKen such that fs=hKs. Moreover, Ks satisfies

μ = S γ n s , p , K s γ n s ( K s ) 1 - α (8)

Proof   Note that for each fCe+(Sn-1), h[f]f and the Wulff shape of h[f] is the same as that of f . So according to (7), we have Fs(f)Fs(h[f]).

Therefore, the maximizer of (6) fs must be the support function of some o-symmetric convex body KsKen. We now use the variational formula to establish that Ks satisfies (8). To this end, for each gCe(Sn-1), consider the family of Wulff shapes

K t = [ ( h K s p + t g ) 1 p ] K e n ,

for t small enough.

Since fs=hKs is a maximizer of (6) and the definition of Fs given in equation (7) and by Theorem 2, it follows that

0 = d d t | t = 0 F s ( h K t ) = γ n s ( K s ) α - 1 S n - 1 g d S γ n s , p , K s - S n - 1 g d μ .

Note that the above equation holds for every gCe(Sn-1). Therefore, we conclude that Ks satisfies (8).

Lemma 3   Let 0<α<1n, p>1 and s(0,). For sufficiently small r>0, we have Fs(rBn)>0.

Proof   From the definition of Fs given in equation (7), we have

F s ( r B n ) = 1 α ( 1 C s , n r B n ( 1 - s | x | 2 2 ) + 1 s d x ) α - S n - 1 r p d μ = 1 α ( n ω n C s , n 0 r ( 1 - s t 2 2 ) + 1 s t n - 1 d t ) α - r p | μ | = r [ 1 α ( n ω n C s , n ) α ( 0 r ( 1 - s t 2 2 ) + 1 s t n - 1 d t r 1 α ) α - r p - 1 | μ | ] . (9)

It follows from L'Hôpital's rule[26] that when 0<α<1n, we have

l i m r 0 + 0 r ( 1 - s t 2 2 ) + 1 s t n - 1 d t r 1 α = l i m r 0 + α ( 1 - s t 2 2 ) + 1 s r n - 1 r 1 α - 1 = α l i m r 0 + r n - 1 α = (10)

According to (9), (10) and p>1, for r is sufficiently small, Fs(rBn)>0.

Proof of Theorem 1   By Lemma 2, it suffices to show that a maximizer to the optimization problem (6) exists. We assume that {Ki}i=1 is a sequence of o-symmetric convex bodies and

l i m i F s ( K i ) = s u p { F s ( f ) :   f C e + ( S n - 1 ) } F s ( r B n ) > 0 .

Choose ri>0 and uiSn-1 such that riuiKi and ri=maxuSn-1ρKi(u).

It is simple to notice that KiriBn. We claim that ri is a bounded sequence from above with upper bound M. Otherwise, by taking a subsequence rij, we may assume that limjrij = +. Since KijrijBn and (7), we have

F s ( K i j ) 1 α γ n s ( r i j B n ) α - S n - 1 h K i j p d μ .

Since rijuijKij, we have hKij(v)rijuijv. Therefore, we have

F s ( K i j ) 1 α γ n s ( r i j B n ) α - r i j p { v S n - 1 : v u i j 0 } | v u i j | p d μ (11)

By the fact that μ is even and not concentrated in any closed hemisphere, there exists a constant c0>0 such that

{ v S n - 1 : v u i j 0 } |   v u i j | p d μ c 0 (12)

as rij+, γns(rijBn)γns(Rn)=1. Therefore, according to (11), (12),

F s ( K i j ) 1 α γ n s ( r i j B n ) α - r i j p c 0 p < 0

as j. The above equation is in contradiction to

l i m j F s ( K i j ) = s u p { F s ( f ) :   f C e + ( S n - 1 ) } > 0 .

This leads to a contradiction. Therefore, the sequence of convex bodies {Ki}i=1 is uniformly bounded.

We use Blaschke selection theorem and assume (by taking a subsequence) that {Ki}i=1 converges to some K0Ken in Hausdorff metric. Note that by the continuity of the s-Gaussian volume with respect to the Hausdorff metric, definition of Fs, and Fs(rBn)>0, we have

1 α γ n s ( K 0 ) α F s ( K 0 ) = l i m i F s ( K i ) > 0 .

Combining the inequality mentioned above, with the fact that K0 is o-symmetric, implies that K0 contains the origin in its interior. Therefore, the convex body K0 is a maximizer to the optimization (6).

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