Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 27, Number 3, June 2022
Page(s) 189 - 194
DOI https://doi.org/10.1051/wujns/2022273189
Published online 24 August 2022

© Wuhan University 2022

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

In this paper, we consider the Cauchy problem for the evolutionary Hamilton-Jacobi equation

{ut(x,t)+H(x,u(x,t),Du(x,t))=0,(x,t)Tn×[0,)u(x,0)=f(x),xTn

Here u(x,t) is an unknown function on Tn×[0,), f(x) is a given function, and ut:=u/t,Du:= (u/x1,,u/xn). We study the long-time asymptotic behavior of the viscosity solution to (CP) and furthermore, discuss the relation between the limit of the viscosity solution of (CP) and the viscosity solution of the stationary Hamilton-Jacobi equation

H(x,u(x),Du(x))=c,xTn

There has been much study about the long-time behavior of the viscosity solutions of Hamilton-Jacobi equations either by means of dynamical techniques or by PDE methods. We occasionally suppress "viscosity" for simplicity.

The dynamical approach is based on the weak KAM theory initiated by Fathi[1,2]. It needs strong regularity assumptions on the Hamiltonian H(x,p) (C2-regularity, strict convexity and superlinearity in p) because it is based on the analysis of the associated Hamiltonian flow. Such flow is connected with the visc.solution of tu+H(x,Du(x))=0 through the Lax-Oleinik formula. The dynamical approach has been later modified by Roquejoffre[3], Davini and Siconolfi in Ref. [4], and others.

The PDE approach is initiated by the work of Namah and Roquejoffre[5]. It does not depend on the Lax-Oleinik formula, so it is possible to be applied to more general cases. Barles and Souganidis have obtained in Ref. [6] more general results in the case Ω=Tn, for possible non-convex Hamiltonians. We refer to Ref. [7] for a recent view on this approach.

In this paper, we will explore the visc. solutions'long time behavior of the Hamilton-Jacobi equation of contact type, in which the Hamiltonian H(x,u,p) explicitly depends on the unknown function u. The contact Hamiltonian system is a natural extension to Hamiltonian system. Various applications of contact Hamiltonian dynamics has been found in many fields such as classic mechanics of dissipative system[8,9], mesoscopic dynamics[10], equilibrium statistical mechanics[11], and thermodynamics[12,13], etc. Su, Wang, and Yan first studied visc.solutions' long-time behavior of the contact Hamilton-Jacobi equation with implicit variational principle in Ref. [14], under Tonelli assumptions (H(x,u,p) is Cr(r2), strict convexity and superlinear growth in p for every (x,u), uniform Lipschitzity and monotonicity with respect to u). Their series of work are aimed at building the variational frame in the contact Hamiltonian system[15-17]. In the recent paper, the author has studied the long-time behavior of solutions of the contact Hamilton-Jacobi equations with the method combining the PDE-viscosity solutions approach and dynamical approach under more general conditions (H(x,u,p) is C, strict convexity and coercive in p for every (x,u), monotonicity with respect to u)[18].

Motivated by above-mentioned results, we will continue this direction of research on the long-time behavior of visc. solutions and we want to discuss if the conditions are necessary for the convergence in this paper. We mainly use and slightly modify the PDE approach which has been introduced by Barles, Ishii and Mitake (see Ref. [7]). The main difference is that we deal with the contact Hamiltonian-Jacobi equation for the consideration of the effect of u in the proof.

We assume that

HC(Tn×R×Rn)(C)

limR+inf{H(x,u,p):xTn,|p|>R}=, for all uR (CER)

The function uH(x,u,p) is non-decreasing on R, for all (x,p)Tn×Rn (MON)

(EP) with c=0 has a visc. solution ω0C (Tn) (Z)

There exist positive constants η0>0,θ0>1 and a positive constant ψ=ψ(η,θ) with (η,θ) (0,η0)×(1,θ0), such that for all x,p,qRn,u,vR, if H(x,u,q)η and H(x,u,q)0, then H(x,v+θ(u-v),p+θ(q-p))ηθ+ψ.

(DSTC+)

There exist positive constants η0>0,θ0>1 and a positive constant ψ=ψ(η,θ) with (η,θ) (0,η0)×(1,θ0), such that for all x,p,qRn, u,vR, if H(x,u,q)-η and H(x,u,q)0, then H(x,v+θ(u-v),p+θ(q-p))-ηθ+ψ.

(DSTC-)

Condition (DSTC+)((DSTC-)) means some kind of strict convexity of H(x,u,p) in (u,p). Indeed, if H is strictly convex in (u,p), then

ηH(x,u,q)=H{x,θ-1[v+θ(u-v)]+(1-θ-1)v,θ-1[p+θ(q-p)]+(1-θ-1)p}<θ-1H(x,v+θ(u-v),p+θ(q-p))+(1-θ-1)H(x,v,p)<θ-1H(x,v+θ(u-v),p+θ(q-p)).

A condition similar to DSTC+(DSTC-) has appeared in Ref. [1]. The difference is the strict convexity about (u,p) in this paper and the strict convexity about p both in the u-independent case in Ref. [7] and in the u-dependent case in Ref. [18]. The convexity in (u,p) is the necessary condition for using this PDE approach, bcause we cannot fix H(x,u(x), Du(x))=c to H(x,u,Du(x))=c as we have done with the PDE approach in Ref. [18].

In this case, we can deal with the convergence problem of the Hamiltonian H(x,u,p) which is not strictly convex in p in contrast to what happens in Ref.[14, 18]. Our main result is:

Theorem 1   Assume (C), (CER), (MON), (Z) and (DSTC+)((DSTC-)). Let fC(Tn), and let uC(Tn×[0,)) be the visc.solution of (CP). Then there exists uC(Tn) such that

limtu(x,t)=u(x) uniformly on Tn.

Moreover, u is a visc. solution of (EP), with c=0.

The paper is organized as follows. In Section 1, we will give some classical results about visc.solution theory which are needed for the next proof. Based on the comparison theorem and the Perron method, we get the existence theorem of (CP) (Theorem 3). Assuming moreover (Z), u(x,t) is bounded and uniformly continuous on Tn×[0,). In Section 2, we will give the proof of Theorem 1 with the condition (DSTC+)((DSTC-)) instead of the condition (CON) in the Ref.[18].

1 The Preliminary Results

As the basis of the existence theorem and the uniqueness theorem, we first introduce the comparison theorem.

Theorem 2[18] Assume (C), (CER) and (MON). Let uUSC(Tn×[0,T)) and vLSC(Tn×[0,T)) be a visc. subsolution and a visc.supersolution of (CP), respectively, where 0<T. Then

u(x,t)-v(x,t)max{maxTn(u(,0)-v(,0)),0}

for all (x,t)Tn×(0,T).

Corollary 1[18] If, in addition, u,v are both visc. solutions of (CP), then we have

supTn×[0,T)|u-v|maxTn|u(,0)-v(,0)|

Theorem 3[18] Assume (C), (CER) and (MON). Let fC(Tn). Then there exists a (unique) solution uC(Tn×[0,)) of (CP).

Theorem 4 [18] Assume (C), (CER), (MON) and (Z). Let uC(Tn×[0,)) be a visc. solution of (CP). Then u is bounded and uniformly continuous on Tn×[0,).

We will give some stability results concerning viscosity solutions.

Theorem 5[18] Let Ω be locally compact. is a family of viscosity subsolutions of (EP). Assume that sup is locally bounded in Ω, then sup is also a visc. subsolution of (EP).

The theorems above are classical results in viscosity solution theory. We can find the proof in Refs. [19-22].

2 The Main Result

In this section, we want to prove our main result.

Theorem 6   Assume (C), (CER), (MON), (Z) and (DSTC+)((DSTC-)). Let fC(Tn), and let uC(Tn×[0,)) be a visc.solution of (CP). Then there exists uC(Tn) such that

limtu(x,t)=u(x) uniformly on Tn.

Moreover, u is a visc. solution of (EP), with c=0.

First, we reduce the result to the case fLip (Tn). Indeed, we have

Lemma 1   If the result of Theorem 6 holds for any fLip(Tn), then it holds for any fC(Tn).

This is an easy consequence of Theorem 2 and the reader can find a proof of the lemma above in Ref. [7].

Lemma 2   There exists a viscosity subsolution v0Lip(Tn) of (EP), with c=0, such that

0u(x,t)-v0(x)C0 for all (x,t)Tn×[0,).

Proof   Due to (Z), there exists a solution ω Lip(Tn) of (EP), with c=0. Since the function ω(x,t):=ω0(x) is a solution of (CP), by Theorem 2 we obtain

|u(x,t)-ω0(x)|maxTn|(u(,0)-ω0|

for all (x,t)Tn×(0,), which can be written as

-Cu(x,t)-ω0(x)C for all (x,t)Tn×[0,)

with C=maxTn|(u(,0)-ω0|. If we set v0(x)=ω0(x)  -C and C0=2C, then we have

0u(x,t)-ω0(x)C0 for all (x,t)Tn×[0,),

and, by (MON), the function v0 is a subsolution of (EP), with c=0.

For (η,θ)(0,η0)×(1,θ0), we define the function ω on Q¯, Q:=Tn×(0,) by

ω(x,t)=supst[u(x,t)-v0(x)-θ(u(x,s)-v0(x)+η(s-t))](1)

where v0(x) is the function given by Lemma 2. We define the functions ωH,R, with R>0, by

ωH,R(r)=sup{|H(x,u,p)-H(x,u,q)|:xTn,p,qB¯R,|p-q|r}.

Lemma 3   We have

-C0(θ-1)ω(x,t)C0 for all (x,t)Tn×(0,).

Proof   According to Lemma 2, for all (x,t) Q¯,

ω(x,t)(1-θ)(u(x,t)-v0(x))-C0(θ-1)

and

ω(x,t)maxst(u(x,t)-v0(x))C0

Theorem 7   The function ω is a subsolution of

min{ω(x,t),ωt(x,t)-ωH,R( |Dxω(x,t)|+ψ)}0 in Q(2)

where ψ=ψ(η,θ) is the constant from (DSTC+), R :=(2θ0+1)L and L:=max{||Dxu||,||Dxv0||}.

Proof   Noting that uLip(Tn×(0,)) and v0 Lip(Tn), then ωLip(Tn×(0,)).

Fix any ϕ0C1(Q) and (x̂,t̂)Q, and assume that

maxQ(ω-ϕ0)=(ω-ϕ0)(x̂,t̂)

If ω(x̂,t̂)0, then we have finished the proof. Therefore, we may assume that ω(x̂,t̂)>0. We choose an ŝ>t̂ so that

ω(x̂,t̂)=u(x̂,t̂)-v0(x̂)-θ(u(x̂,ŝ)-v0(x̂)+η(ŝ-t̂))

If ŝ=t̂, we get ω(x̂,t̂)=(1-θ)(u(x̂,t̂)-v0(x̂))0, and we are done. We may thus assume that ŝ>t̂.

Define the function ϕC1(Q×(0,)) by

ϕ(x,t,s)=ϕ0(x,t)+(x-x̂)2+(t-t̂)2+(s-ŝ)2

Note that the function

u(x,t)-v0(x)-θ(u(x,s)-v0(x)+η(s-t))-ϕ(x,t,s)(3)

on Q×(0,) attains a strict maximum at (x̂,t̂,ŝ), and that Dxϕ(x̂,t̂,ŝ)=Dxϕ0(x̂,t̂), ϕt(x̂,t̂,ŝ)=ϕ0,t(x̂, t̂) and ϕs(x̂,t̂,ŝ)=0.

Now, if B is an open ball of T3n+2 centered at (x̂,x̂,x̂,t̂,ŝ) with its closure B¯ contained in T3n× (0,)2, we consider the function Φ on B¯ given by

Φ(x,y,z,t,s)=u(x,t)-v0(z)-θ(u(y,s)-v0(z)+η(s-t))-ϕ(x,t,s)-α(|x-y|2+|x-z|2),

where α>0 is a large constant.

Let (xα,yα,zα,tα,sα)B¯ be a maximum point of Φ. We can get

limα(xα,yα,zα,tα,sα)=(x̂,x̂,x̂,t̂,ŝ)(4)

Next, set

pα=2(θ-1)-1α(zα-xα) and qα=2θ-1α(xα-yα).

We observe that

pαD+v0(zα)

(qα,-θ-1ϕs(xα,tα,sα)-η)D-u(yα,sα)

(Dxϕ(xα,tα,sα)+θqα-(θ-1)pα,ϕt(xα,yα,sα)-θη)D+u(xα,tα).

We have max{|pα|,|qα|}L by the definition of L, and by sending α+ along an appropriate sequence, we can find points p̂,q̂BL such that

p̂D¯+v0(x̂)(5)

(q̂,-θ-1ϕs(x̂,t̂,ŝ)-η)D¯-u(x̂,ŝ)(6)

(Dxϕ(x̂,t̂,ŝ)+θq̂-(θ-1)p̂,ϕt(x̂,ŷ,ŝ)-θη)D¯+u(x̂,t̂)(7)

where D¯± stands for the closure of D±, for instance, D¯+u(x̂,ŝ) denotes the set of points (q,b)Tn×R for which there are sequences {(qj,bj)}jTn×R and {(xj,sj)}jQ such that limj(qj,bj,xj,sj)=(q, b,x̂,ŝ) and (qj,bj)D+u(xj,sj) for all j. Recall that ϕs(x̂,t̂,ŝ)=ϕ0,t(x̂,t̂) and Dxϕ(x̂,t̂,ŝ)=Dxϕ0(x̂, t̂), so that we have

H(x̂,v0(x̂),p̂)0,-η+H(x̂,u(x̂,ŝ),q̂)0

from (5) and (6). Therefore, (DSTC+) ensures

H(x̂,v0(x̂)+θ(u(x̂,ŝ)-v0(x̂)),p̂+θ(q̂-p̂))>ηθ+ψ(8)

Since ω(x̂,t̂)>0, we have

u(x̂,t̂)>θu(x̂,ŝ)+(1-θ)v0(x̂)+θη(ŝ-t̂)(9)

Because of the assumption (MON), (8) and (9),

0ϕt(x̂,ŷ,ŝ)-θη+H(x̂,u(x̂,t̂),Dxϕ(x̂,t̂,ŝ)+θq̂+(1-θ)p̂)ϕt(x̂,ŷ,ŝ)-θη+H(x̂,θu(x̂,ŝ)+(1-θ)v0(x̂),

θq̂+(1-θ)p̂)-ωH,R(|Dxϕ|)ϕt(x̂,ŷ,ŝ)+ψ-ωH,R(|Dxϕ|).

The second inequality holds since |θq̂+(1-θ)p̂| (1+2θ)LR and |Dxϕ0(x̂,t̂)+θq̂+(1-θ)p̂|L because of (7). Therefore, we get

ϕt(x̂,t̂,ŝ)-ωH,R(|Dxϕ|)+ψ0

i.e.,

ϕ0,t(x̂,t̂)-ωH,R(|Dxϕ0|)+ψ0

We set

ω(x)=limsuptω(x,t) for all xTn.

Lemma 4   We have

ω(x)0 for all xTn.

Moreover, the convergence

limtmax{ω(x,t),0}=0

is uniform in xTn.

Proof   If the convergence does not hold uniformly in xTn, we can choose a sequence (xj,tj) such that limjtj= and ω(xj,tj)δ for all j N and some constant δ>0. We may assume that limjxj=y for some yTn. In view of the Ascoli-Arzela theorem, we may assume by passing to a subsequence of (xj,tj) if needed that

limjω(x,t+tj)=g(x,t) uniformly in Tn×(-,+),

for some bounded function gLip(Tn×R) and g(y,0)δ.

By the stability of the subsolution property under uniform convergence, we see that g is a subsolution of

min{g(x,t),gt(x,t)-ωH,R( |Dxg(x,t)| )+ψ}0

in Tn+1. Since gLip(Tn×R) and g is bounded on Rn+1, for every ε>0, the function g(x,t)-εt2 attains a maximum at a point (xε,tε), then we have

g(xε,tε)-εtε2g(y,0)δ

Therefore, we know that

g(xε,tε)>δ and ε|tε|(ε||g||)1/2.

In particular, we have limε0+εtε=0. Then, as usual in the viscosity solutions theory, we get

2εtε-ωH,R(0)+ψ0

which, in the limits as ε0+, yields ψ0, a contradiction.

Proof of Theorem 6 under condition (   DSTC+ )

Let ω be the function defined by (1), with arbitrary (η,θ)(0,η0)×(1,θ0).

Fix any ε>0. Because of (1), we may choose a constant Tε so that for any t>Tε, ω(x,t)ε for all xTn.

From the above, for any s>t, we have

u(x,t)-v0(x)ε+θ(u(x,s)-v0(x))+θη(s-t)ε+u(x,s)-v0(x)+(θ-1)C0+θη(s-t).

Thus, for any 0s1, we have

u(x,t)u(x,t+s)+(θ-1)C0+θη+ε(10)

Now, since u is bounded and Lipschitz continuous in Q¯, in view of the Ascoli-Arzela theorem, we may choose a sequence τj and a bounded function zLip(Tn×(-,+)) so that

limju(x,t+τj)=z(x,t) locally uniformly on Tn+1(11)

By (10) we get

z(x,t)z(x,t+s)+(θ-1)C0+θη+ε(12)

for all (x,t,s)Rn+1×[0,1]. This is valid for all (η, θ)(0,η0)×(1,θ0). Hence we obtain

z(x,t)z(x,t+s) for all (x,t,s)Tn×R×[0,1](13)

Thus we find that the function z(x,t) is nondecreasing in tR for all xTn.

From this we conclude that

limtz(x,t)=u(x) uniformly on  Tn(14)

for some function uLip(Tn). Since u(x,t) is a viscosity solution of (CP), and u(x,t) is bounded on Tn×[0,), we get from Theorem 5 that z(x,t) is a solution of (CP), and moreover, u(x) is a solution of (EP).

Fix any δ>0. By (14) there is a constant τ>0 such that

||z(,τ)-u||<δ

and by (11) there is a jN such that

||z(,τ+τj)-u(,τ+τj)||<δ

Therefore,

||u(,τ+τj)-u||<2δ

By the contraction property, we see that for any t τ+τj,

||u(,t)-u||||u(,τ+τj)-u||<2δ

which completes the proof.

Proof of Theorem 6 under condition (   DSTC- )

We adjust ω(x,t) to the form

ω(x,t)=sup0st[u(x,t)-v0(x)-θ(u(x,s)-v0(x)-η(s-t))]

where (η,θ) is chosen arbitrarily in (0,η0)×(1,θ0) and the constants η0 and θ0 are from (DSTC-).

Theorem 8   The function ω is a subsolution of

min{ω(x,t),ωt(x,t)-ωH,R( |Dxω(x,t)| )+ψ}0,(x,t)Tn×(T,),

where ψ=ψ(η,θ)>0 is the constant from (DST C-), T:=C0/η and R:=(2θ0+1)L.

We can prove

-C0(θ-1)ω(x,t)C0 for all (x,t)Q¯.

On the other hand, for any (x,t)Tn×(T,) and s [0,t-T),

u(x,t)-v0(x)-θ(u(x,s)-v0(x)-η(s-t))C0-θη(t-s)<C0-θηT=-(θ-1)C0.

Hence, for any (x,t)Tn×(T,) we have

ω(x,t)=maxt-Tst[u(x,t)-v0(x)-θ(u(x,s)-v0(x)-η(s-t))]

=max-Ts0[u(x,t)-v0(x)-θ(u(x,s+t)-v0(x)-ηs)]

We fix any test function ϕ0C1(Tn×(T,)) and assume that ω-ϕ0 attains a strict maximum at a point (x̂,t̂).

We can get the following conclusion like the proof of (DSTC+):

p̂D¯+v0(x̂),(q̂,η)D¯-u(x̂,ŝ),(Dxϕ0(x̂,t̂)+θq̂-(θ-1)p̂,ϕ0,t(x̂,t̂)+θηD¯+u(x̂,t̂),

for some p̂,q̂Tn.

Similarly, we can assume ω(x̂,t̂)>0. According to assumption (MON), we have

0ϕt(x̂,ŷ,ŝ)+θη+H(x̂,u(x̂,t̂),Dxϕ(x̂,t̂,ŝ)+θq̂+(1-θ)p̂)ϕt(x̂,ŷ,ŝ)+θη+H(x̂,u(x̂,t̂),θq̂-(θ-1)p̂)-ωH,R(|Dx(ϕ)|)ϕt(x̂,ŷ,ŝ)+θη-ωH,R(|Dx(ϕ)|)+H(x̂,θu(x̂,ŝ)+(1-θ)v0(x̂),θq̂+(1-θ)p̂)

Since -ηH(x,u(x̂,ŝ),q̂),H(x̂,v0(x̂),p̂)0, we get

ϕt(x̂,t̂,ŝ)-ωH,R(|Dx(ϕ)|)+ψ<0

by the condition (DSTC-).

Also, we can prove

limtmax{ω(x,t),0}=0 uniformly in Tn(15)

We can get u(x,t) is nonincreasing for all xTn and enough large t from (15). Since u is bounded and Lipschitz continuous in Tn×(-,), we can choose a sequence τj such that for some function zLip(Tn×R),

limju(x,t+τj)=z(x,t) locally uniformly on Tn×R.

z(x,t) is nonincreasing in t for all xTn, then there exists the function uC(Tn) such that

limtz(x,t)=u(x) uniformly on Tn.

Furthermore

limtu(x,t)=u(x) uniformly on Tn.

Thus we complete the proof.

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