Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 28, Number 5, October 2023
Page(s) 373 - 378
DOI https://doi.org/10.1051/wujns/2023285373
Published online 10 November 2023

© Wuhan University 2023

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

In this paper, we consider the lower bound of blow up time for a class of slow reaction diffusion equations with nonlocal source and inner absorption terms

u t = u h 1 ( Δ u m 1 + Ω v s 1 d x - k 1 u r 1 ) ,    ( x , t ) Ω × ( 0 , t * ) (1)

v t = v h 2 ( Δ v m 2 + Ω u s 2 d x - k 2 v r 2 ) ,    ( x , t ) Ω × ( 0 , t * ) (2)

u ( x , 0 ) = u 0 ( x ) ,    v ( x , 0 ) = v 0 ( x ) ,    x Ω (3)

Under either homogeneous Dirichlet boundary condition

u ( x , t ) = v ( x , t ) = 0 ,    ( x , t ) Ω × ( 0 , t * ) (4)

or nonhomogeneous Neumann boundary condition

u m 1 υ = u 1 - h 1 , v m 2 υ = v 1 - h 2 ,    ( x , t ) Ω × ( 0 , t * ) (5)

where Δ is a Laplace operator, ΩR3 is a bounded region with smooth boundary Ω, 0<hi<1,mi>1,ri,si, hi+si>1, hi+mi>1,i=1,2,υ is the unit external normal vector in the external normal direction of Ω.

Equations (1)-(5) can be used to describe slow diffusion phenomena in physics and chemistry, such as combustion of two mixtures in heat conduction process, reaction changes of two reactants in chemical reaction, and so on. u,v represent temperature of two media and concentration of reactants respectively etc.

There are many research achievements on the lower bound of blow up time of the following single reaction-diffusion equation with absorption term,

u t = Δ u m + a ( x ) u p Ω u q d x - k u s (6)

When m=1,a(x)=1,p=0, Song[1] studied the lower bound of blow up time for solution of equation (6) with homogeneous Dirichlet and homogeneous Neumann boundary conditions; Liu[2] studied the lower bound of blow up time for the solution of equation (6) with nonlinear boundary conditions; Tang et al[3] has extended the results in equation (6) to higher dimensional cases, see Refs. [4-7] for other relevant achievements.

Relatively speaking, there are few studies on the lower bound of blow up time for the solution of cross coupled reaction diffusion equations with nonlocal sources and absorption terms. Ouyang et al[8] studied global existence and blow up of solutions for the following generalized nonlocal porous media equations with time dependent coefficients and absorption terms

u t = Δ u a + k 1 ( t ) h 1 ( u , v ) - f 1 ( u ) v t = Δ v b + k 2 ( t ) h 2 ( u , v ) - f 2 ( v )

Ouyang et al[9] studied the global existence of the solution and the lower bound of blow up time of the solution for the following equations

u t = Δ u + k 1 ( t ) u p Ω v q d x - u α v t = Δ v + k 2 ( t ) v r Ω u s d x - v β

when blow up occurs. Other similar equations or equation set are shown in Refs. [10-16].

Inspired by Refs. [8-16], this paper studies the lower bound of blow up time for solutions of slow reaction-diffusion equations (1)-(5) with different boundary conditions when m>1,n>1, and generalizes the existing results. The results can better describe the reaction diffusion problems with the cross influence of two variables in physical, chemical and hydrodynamic problems.

1 Some Important Inequalities

This part introduces some important inequalities used in this paper.

Lemma 1[17] (Young inequality) Let 1<p,q<,1p+1q=1, then abapp+bqq, (a,b>0).

Lemma 2[17] (Membrane inequality)

λ Ω w 2 d x Ω | w | 2 d x

where λ is the first eigenvalue of Δw=λw=0,w>0,(xΩ), w=0 (xΩ).

Lemma 3[16] Let Ω be the bounded star region in RN, and N2, then

Ω u n d s N ρ 0 Ω u n d x + n d ρ 0 Ω u n - 1 | u | d x

where ρ0=minΩ(x.n)>0,d=maxΩ|x|.

Lemma 4[17] (Special Young inequality) Let λ be an arbitrary constant, and 0<x<1, then

a x b y = ( λ a ) x ( b y 1 - x λ x 1 - x ) 1 - x λ x a + ( 1 - x ) λ x x - 1 b y 1 - x ,   ( a , b > 0 ) .

2 Lower Bound of Blow up Time under Homogeneous Dirichlet Boundary Conditions

The lower bound of blow up time for solutions of equations under homogeneous Dirichlet boundary conditions is discussed below.

Theorem 1   Define an auxiliary functions

H ( t ) = Ω ( u l + v l ) d x (7)

for l>max{1,si,hi+mi-1,2hi+3si-2,i=1,2}. If (u,v) is a non-negative classical solution of equations (1)-(4) and blow up occurs in the sense of measure H(t) at time t*, then the lower bound of t* is

t * H ( 0 ) d ξ J 1 ξ c 1 + ( J 2 + J 3 ) ξ

where H(0)=Ω(u0l+v0l)dx. The normal number J1,J2,J3,c1 are given in the following proof.

Proof  

H ( t ) = l Ω u l - 1 u t d x + l Ω v l - 1 v t d x = l Ω u l + h 1 - 1 Δ u m 1 d x + l Ω u l + h 1 - 1 Ω v s 1 d x d x - l k 1 Ω u l + h 1 + r 1 - 1 d x + l Ω v l + h 2 - 1 Δ v m 2 d x + l Ω v l + h 2 - 1 Ω u s 2 d x d x - l k 2 Ω v l + h 2 + r 2 - 1 d x = - l Ω u l + h 1 - 1 Δ u m 1 d x + l Ω u l + h 1 - 1 Δ u m 1 υ d s + l Ω u l + h 1 - 1 Ω v s 1 d x d x - l k 1 Ω u l + h 1 + r 1 - 1 d x - l Ω v l + h 2 - 1 v m 2 d x + l Ω v l + h 2 - 1 Δ v m 2 υ d s + l Ω v l + h 2 - 1 Ω u s 2 d x d x - l k 2 Ω v l + h 2 + r 2 - 1 d x = - m 1 l ( l + h 1 - 1 ) Ω u l + h 1 + m 1 - 3 | u | 2 d x + l Ω u l + h 1 - 1 Δ u m 1 υ d s + l Ω u l + h 1 - 1 Ω v s 1 d x d x - l k 1 Ω u l + h 1 + r 1 - 1 d x - m 2 l ( l + h 2 - 1 ) Ω v l + h 2 + m 2 - 3 | v | 2 d x + l Ω v l + h 2 - 1 Δ v m 2 υ d s + l Ω v l + h 2 - 1 Ω u s 2 d x d x - l k 2 Ω v l + h 2 + r 2 - 1 d x = - 4 m 1 l ( l + h 1 - 1 ) ( k + h 1 + m 1 - 1 ) 2 | u l + h 1 + m 1 - 1 2 | 2 d x + l Ω u l + h 1 - 1 Δ u m 1 υ d s (8)

When the equations (1)-(4) take homogeneous Dirichlet boundary conditions, equation (8) becomes

H 1 ' ( t ) = α 1 Ω | u a | 2 d x + l Ω u l + h 1 - 1 d x Ω v s 1 d x - l k 1 Ω u l + h 1 + r 1 - 1 d x (9)

H 2 ' ( t ) = β 1 Ω | v b | 2 d x + l Ω v l + h 2 - 1 d x Ω u s 2 d x - l k 2 Ω v l + h 2 + r 2 - 1 d x (10)

here

α 1 = - 4 m 1 l ( l + h 1 - 1 ) ( l + h 1 + m 1 - 1 ) 2 , β 1 = - 4 m 2 l ( l + h 2 - 1 ) ( l + h 2 + m 2 - 1 ) 2 , a = l + h 1 + m 1 - 1 2 , b = l + h 2 + m 2 - 1 2 .

First, Hölder's inequality is used to estimate the second term of H1'(t) in equation (9), and we obtain

Ω u l + h 1 - 1 d x ( Ω ( u l + h 1 - 1 ) l l - s 1 d x ) l - s 1 l | Ω | s 1 l , Ω v s 1 d x ( Ω ( v s 1 ) l s 1 d x ) s 1 l | Ω | l - s 1 l , Ω u l + h 1 - 1 d x Ω v s 1 d x ( Ω ( u l + h 1 - 1 ) l l - s 1 d x ) l - s 1 l ( Ω ( v s 1 ) l s 1 d x ) s 1 l | Ω | .

According to Lemma 1 and equation aboves, we get

Ω u l + h 1 - 1 d x Ω v s 1 d x | Ω | ( l - s 1 ) l Ω u l ( l + h 1 - 1 ) l - s 1 d x + | Ω | s 1 k Ω v l d x (11)

Second, Hölder's inequality is used to estimate the first term on the right side of inequality (11), and it is obtained that

Ω u l ( l + h 1 - 1 ) l - s 1 d x = Ω u a u l ( l + h 1 - 1 ) l - s 1 - a d x ( Ω u 4 a d x ) 1 4 ( Ω u 2 [ 2 l ( l + h 1 - 1 ) l - s 1 - ( l + h 1 + m 1 - 1 ) ] 3 d x ) 3 4 (12)

From the second term on the right side of inequality sign of (12) and Hölder's inequality, we can get

{ Ω u 2 [ 2 l ( l + h 1 - 1 ) l - s 1 - ( l + h 1 + m 1 - 1 ) ] 3 d x } 3 4 ( Ω u l d x ) 1 + 2 ( h 1 + s 1 - 1 ) l - s 1 - h 1 + m 1 - 1 l 2 | Ω | 1 2 - 2 ( h 1 + s 1 - 1 ) l - s 1 + h 1 + m 1 - 1 l 2 (13)

From the first term on the right side of inequality sign of (12) and Hölder's inequality, we know

Ω u 4 a d x = Ω u a u 3 a d x ( Ω u 2 a d x ) 1 2 ( Ω ( u a ) 6 d x ) 1 2 (14)

Using the following Sobolev inequality[17]

( Ω | ϕ | γ 1 d x ) 1 γ 1 C ( Ω | ϕ | γ 2 d x ) 1 γ 2

where γ1=6,γ2=2,C=4133-12π-23, and the second term of inequality (14) can be simplified to

( Ω ( u a ) 6 d x ) 1 2 C 3 ( Ω | u a | 2 d x ) 3 2 (15)

By synthesizing inequalities (14) and (15), we have

( Ω u 4 a d x ) 1 4 C 3 4 ( Ω u 2 a d x ) 1 8 ( Ω | u a | 2 d x ) 3 8 (16)

Based on lemma 2, inequality (16) becomes

( Ω u 4 a d x ) 1 4 C 3 4 λ - 1 8 ( | u a | 2 d x ) 1 2 (17)

Combining inequalities (13) and (17), inequality (12) becomes

Ω u l ( l + h 1 - 1 ) l - s 1 d x α 2 ( Ω | u a | 2 d x ) 1 2 ( Ω u l d x ) d 1 (18)

where

α 2 = C 3 4 λ - 1 8 | Ω | 1 2 [ 1 2 - 2 ( h 1 + s 1 - 1 ) l - s 1 + h 1 + m 1 - 1 l ] , d 1 = 1 2 [ 1 2 - 2 ( h 1 + s 1 - 1 ) l - s 1 - h 1 + m 1 - 1 l ] .

Secondly, for h1+γ1>1, the order-preserving property of integrals is quoted in the third term of H1'(t) in equation (9), we have

- l k 1 Ω u l + h 1 + r 1 - 1 d x - l k 1 Ω u l d x (19)

By synthesizing inequalities (11), (18), (19) with an undetermined positive weight factor φ1,H1'(t) of inequality (9) becomes

H 1 ' ( t ) α 1 Ω | u a | 2 d x + α 2 | Ω | ( l - s 1 ) ( φ 1 [ Ω | u a | 2 d x ] 1 2 φ 1 - 1 [ ( Ω u l d x ) 2 d 1 ] 1 2 ) + s 1 | Ω | Ω v l d x - l k 1 Ω u l d x (20)

where φ1 is given in the later proof, according to the arithmetic geometric mean inequality

a q b p < q a + p b   ( a , b , p , q 0 , p + q = 1 ) .

Inequality (20) becomes

H 1 ' ( t ) ( α 1 + α 2 | Ω | ( l - s 1 ) φ 1 2 ) Ω | u a | 2 d x + α 2 | Ω | ( l - s 1 ) φ 1 - 1 2 ( Ω u l d x ) 2 d 1 + s 1 | Ω | Ω v l d x - l k 1 Ω u l d x (21)

The same derivation method is used to estimate the H2'(t) term in inequality (10),

H 2 ' ( t ) ( β 1 + β 2 | Ω | ( l - s 2 ) φ 2 2 ) Ω | v b | 2 d x + β 2 | Ω | ( l - s 2 ) φ 2 - 1 2 ( Ω v l d x ) 2 d 2 + s 2 | Ω | Ω u l d x - l k 2 Ω v l d x (22)

where

β 2 = C 3 4 λ - 1 8 | Ω | 1 2 [ 1 2 - 2 ( h 2 + s 2 - 1 ) l - s 2 + h 2 + m 2 - 1 l ] , d 2 = 1 2 [ 2 ( h 2 + s 2 - 1 ) l - s 2 - h 2 + m 2 - 1 l ] .

φ 2 is given in the later proof, in order to deal with the gradient terms in (21) and (22), set

φ 1 = - 2 α 1 α 2 | Ω | ( l - s 1 ) , φ 2 = - 2 β 1 β 2 | Ω | ( l - s 2 ) .

Finally, by synthesizing inequalities (21) and (22), we can compute

H ' ( t ) - [ α 2 | Ω | ( l - s 1 ) ] 2 4 a 1 ( Ω u l d x ) 2 d 1 - [ β 2 | Ω | ( l - s 2 ) ] 2 4 β 1 ( Ω v l d x ) 2 d 2 + | Ω | ( s 1 Ω v l d x + s 2 Ω u l d x ) - l ( k 1 Ω u l d x + k 2 Ω v l d x ) (23)

take

J 1 = - [ α 2 | Ω | ( l - s 1 ) ] 2 4 α 1 - [ β 2 | Ω | ( l - s 2 ) ] 2 4 β 1 , J 2 = | Ω | ( s 1 + s 1 ) , J 3 = - l ( k 1 + k 2 ) , c 1 = m a x { 2 d 1 , 2 d 2 } > 1 ,

inequality (23) becomes

H ' ( t ) J 1 H c 1 ( t ) + ( J 2 + J 3 ) H ( t ) (24)

Integrating (24) from 0 to t*, we obtain

t * H ( 0 ) d ξ J 1 ξ c 1 + ( J 2 + J 3 ) ξ (25)

This completes the proof of the theorem.

3 Lower Bound of Blow up Time under Nonhomogeneous Neumann Boundary Conditions

Theorem 2   Define the same measure as (7) and the same condition as l. If (u,v) is a nonnegative classical solution to the equations (1)-(3) and (5), then the lower bound of t* is

t * H ( 0 ) d ξ J 1 ξ c 1 + J 5 ξ c 2 + ( J 2 + J 3 + J 4 ) ξ

where H(0)=Ω(u0l+v0l)dx, the normal number J1,J2,J3,J4,J5,c1,c2 are given in the following proof.

Proof   Lemma 3 is used to estimate two boundary terms in inequality (8), then

Ω u l + h 1 - 1 u m 1 υ d s = Ω u l d s 3 ρ 0 Ω u l d x + l d ρ 0 Ω u l - 1 | u | d x (26)

where ρ0=minΩ(xn)>0,d=maxΩ|x|.

From the second term on the right side of inequality (26) and Hölder's inequality and Lemma 4, we can know

Ω u l - 1 | u | d x ( Ω u l + h 1 + m 1 - 3 | u | 2 d x ) 1 2 ( Ω u l - h 1 - m 1 + 1 d x ) 1 2 λ 1 2 ( Ω u k + p 1 + m 1 - 3 | u | 2 d x ) + 1 2 λ 1 Ω u k - p 1 - m 1 + 1 d x = - 2 λ 1 ( l + h 1 + m 1 - 3 ) 2 Ω | u l + h 1 + m 1 - 1 2 | 2 d x     + 1 2 λ 1 Ω u l - h 1 - m 1 + 1 d x (27)

where λ1 is an arbitrary constant.

The Hölder's inequality is used to estimate the second term on the right side of inequality (27), and we have

Ω u l - ( h 1 + m 1 - 1 ) d x ( Ω u l d x ) l - ( h 1 + m 1 - 1 ) l | Ω | h 1 + m 1 - 1 l (28)

Substituting (27) and (28) into inequality (26), we get

Ω u l + h 1 - 1 u m υ d s 3 ρ 0 Ω u l d x + α 3 Ω | u a | 2 d x + α 4 ( Ω u l d x ) d 3 (29)

where

α 3 = - 2 λ 1 l d ρ 0 ( l + h 1 + m 1 + 1 ) 2 , α 4 = l d 2 λ 1 ρ 0 | Ω | h 1 + m 1 - 1 k , d 3 = l - h 1 - m 1 + 1 l .

Similarly, another boundary term in inequality (8) is estimated as follows

Ω u l + h 2 - 1 u m 2 υ d s 3 ρ 0 Ω v l d x + β 3 Ω | v b | 2 d x + b 4 ( Ω v l d x ) d 4 (30)

β 3 = - 2 λ 2 l d ρ 0 ( l + h 2 + m 2 + 1 ) 2 ,   β 4 = l d 2 λ 2 ρ 0 | Ω | h 2 + m 2 - 1 l , d 4 = l - h 2 - m 2 + 1 l ,

λ 2 is an arbitrary constant.

Substituting (21), (22), (29) and (30) into inequality (8), we compute

H ' ( t ) ( α 1 - α 3 + α 2 | Ω | ( l - s 1 ) φ 3 2 ) Ω | u a | 2 d x       + ( β 1 - β 3 + β 2 | Ω | ( l - s 2 ) φ 4 2 ) Ω | v β | 2 d x - [ α 2 | Ω | ( l - s 1 ) ] 2 4 a 1 ( Ω u l d x ) 2 d 1 - [ β 2 | Ω | ( k - s 2 ) ] 2 4 β 1 ( Ω v k d x ) 2 d 2 + α 4 ( Ω u k d x ) d 3 + β 4 ( Ω v k d x ) d 4 + ( 3 ρ 0 + | Ω | s 2 - l k 1 ) Ω u l d x + ( 3 ρ 0 + | Ω | s 1 - l k 2 ) Ω v l d x (31)

Let

φ 3 = - 2 ( α 1 + α 3 ) α 2 | Ω | ( l - s 1 ) , φ 4 = - 2 ( β 1 + β 3 ) β 2 | Ω | ( l - s 2 ) , J 1 = - [ α 2 | Ω | ( l - s 1 ) ] 2 4 α 1 - [ β 2 | Ω | ( l - s 2 ) ] 2 4 β 1 , J 2 = | Ω | ( s 1 + s 2 ) , J 3 = - l ( k 1 + k 2 ) , J 5 = α 4 + β 4 , J 4 = 3 ρ 0 , c 1 = m a x { 2 d 1 , 2 d 2 } > 1 , c 2 = m a x { d 3 , d 4 } > 0 ,

inequality (31) becomes

H ' ( t ) J 1 H c 1 ( t ) + J 5 H c 2 ( t ) + ( J 2 + J 3 + J 4 ) H ( t ) (32)

Integrating (32) from 0 to t*, we obtain

t * H ( 0 ) d ξ J 1 ξ c 1 + J 5 ξ c 2 + ( J 2 + J 3 + J 4 ) ξ ,

where H(0)=Ω(u0L+v0L)dx.

This completes the proof of the theorem.

Acknowledgments

The author would like to thank the referees for their valuable suggestions and comments which helped to improve this paper.

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