Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 28, Number 2, April 2023
Page(s) 99 - 105
DOI https://doi.org/10.1051/wujns/2023282099
Published online 23 May 2023

© Wuhan University 2023

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

Let m1Mathematical equation, p>1Mathematical equation and q(1,2)Mathematical equation be three constants, ΩRN(N>p)Mathematical equation be a bounded domain with smooth boundary ΩMathematical equation, and u0(x)Mathematical equation be a bounded non-trivial function with |u0|m-1u0W01,p(Ω)Mathematical equation. We focus our attention here on dealing with the global existence, extinction and non-extinction phenomenon of the following doubly nonlinear parabolic equation

{ u t - d i v ( | ( | u | m - 1 u ) | p - 2 ( | u | m - 1 u ) ) = f ( u ) ,    ( x , t ) Ω × ( 0 , + ) u ( x , t ) = 0 ,                                          ( x , t ) Ω × ( 0 , + ) u ( x , 0 ) = u 0 ( x ) ,                                   x Ω Mathematical equation(1)

with

f ( u ) = { | u | q - 2 u l o g | u | ,    i f   u 0 0 ,                             i f   u = 0 Mathematical equation(2)

Nonlinear evolutionary problems with logarithmic nonlinearity like model (1) came from inflation cosmology, super symmetric field theories, quantum mechanics and nuclear physics[1-6].

In the past few decades, many mathematical researchers have devoted themselves to investigating the doubly nonlinear parabolic equations, and obtained many meaningful results, such as local and global well-posedness, regularity, blow-up in a finite time and extinction singularity [7-12]. Especially, the authors [13-15] studied the problem

{ u t - d i v ( | u m | p - 2 u m ) = λ u q ,    ( x , t ) Ω × ( 0 , + ) u ( x , t ) = 0 ,                                   ( x , t ) Ω × ( 0 , + ) u ( x , 0 ) = u 0 ( x ) ,                            x Ω Mathematical equation(3)

where m>0Mathematical equation, p>1Mathematical equation, λ>0Mathematical equation, q>0Mathematical equation and u0(x)Mathematical equation is a non-negative bounded non-trivial function with u0m(x)W01,p(Ω)Mathematical equation. For the case 0<m(p-1)<1Mathematical equation, the authors [14,15] proved that the critical blow-up and extinction exponents are qbc=1Mathematical equation and qec=m(p-1)Mathematical equation, respectively. Compared with the case 0<m(p-1)<1Mathematical equation, the solution for the case m(p-1)1Mathematical equation exhibits completely different properties [13]. On the one hand, for any q>0Mathematical equation, the non-trivial solution to problem (3) will never become extinct at a finite time. On the other hand, the critical blow-up exponent becomes qbc*=m(p-1)Mathematical equation.

Recently, Le and Le [16,17] considered problem (1) with m(p-1)>1Mathematical equation and obtained the existence and non-existence results of the global weak solutions. Precisely speaking, they concluded that if m(p-1)>q-1Mathematical equation, then for any |u0|m-1u0W01,p(Ω)Mathematical equation, problem (1) admits a global solution; if m(p-1)q-1Mathematical equation, then there exists a weak solution to problem (1) which is global provided that u0(x)Mathematical equation belongs to some specific stable sets, and the weak solution blows up in a finite time provided that u0(x)Mathematical equation belongs to some specific unstable sets.

According to our knowledge, there is no extinction result of the solution to problem (1) with 0<m(p-1)<1Mathematical equation. Inspired by the above works, we naturally take the following two questions into consideration. Does the solution to problem (1) with 0<m(p-1)<1Mathematical equation exist globally under some certain conditions? If so, is there a critical extinction exponent of the global solutions? In fact, in this paper, we work with the following equivalent formulation of problem (1), obtained by changing variable v=|u|m-1uMathematical equation,

{ ( | v | 1 - m m v ) t - d i v ( | v | p - 2 v ) = f ( v ) ,    ( x , t ) Ω × ( 0 , + ) v ( x , t ) = 0 ,                                            ( x , t ) Ω × ( 0 , + ) v ( x , 0 ) = v 0 = | u 0 | m - 1 u 0 ,                    x Ω Mathematical equation(4)

with

f ( v ) = { 1 m | v | q - 1 - m m v l o g | v | ,    i f   v 0 0 ,                                     i f   v = 0 Mathematical equation(5)

It is clear that the first equation in problem (4) has degeneracy or singularity at the points where v(x,t)=0Mathematical equation or |v(x,t)|=0Mathematical equation, and hence problem (4) might not have classical solution in general. We introduce the definition of the weak solution to problem (4) as follows.

Definition 1   Let T>0Mathematical equation. A measurable function v(x,t)Mathematical equation defined in Ω×[0,T)Mathematical equation is called a weak solution to problem (4) if vL(0,T;W01,p(Ω))Mathematical equation, (|v|1-mmv)tL2(0,T;L2(Ω))Mathematical equation, v(x,0)=|u0|m-1u0W01,p(Ω)Mathematical equation and

Ω [ ( | v | 1 - m m v ) t φ + | v | p - 2 v φ ]   d x = 1 m Ω | v | q - 1 - m m v l o g | v | φ d x Mathematical equation(6)

holds for a.e. t(0,T)Mathematical equation and any φW01,p(Ω)Mathematical equation.

Similar to the proof of Theorem 3.3 [17], by Faedo-Galerkin method, we can prove the local existence result of the weak solution to problem (4). Now, we state the main results of this paper as follows.

Theorem 1   Assume that 0<m(p-1)<1Mathematical equation. Then the weak solution u(x,t)Mathematical equation of problem (1) exists globally.

Theorem 2   Assume that 0<m(p-1)<q-1<1Mathematical equation. If

m a x { ( Ω ( | u 0 | m - 1 u 0 ) + m p a + m + 1 m d x ) θ , ( Ω ( | u 0 | m - 1 u 0 ) - m p a + m + 1 m d x ) θ } κ 6 2 κ 7 Mathematical equation(7)

with θ=q-1-m(p-1)+mβmpa+m+1Mathematical equation, β(0,2-qm)Mathematical equation and a>max{-1p,-1mp,(N-p)(m+1)-Npmmp2}Mathematical equation.Then the weak solution u(x,t)Mathematical equation to problem (1) will vanish in finite time, where κ6Mathematical equation and κ7Mathematical equation are two positive constants, given by (23) and (24), respectively.

Theorem 3   Assume that 0<q-1m(p-1)<1Mathematical equation. If

{ Ω | u 0 | m + 1 d x > 0   a n d   E ( | u 0 | m - 1 u 0 ) 0 ,                                             m ( p - 1 ) = q - 1 Ω | u 0 | m + 1 d x > 0   a n d   E ( | u 0 | m - 1 u 0 ) < - m | Ω | [ m ( p - 1 ) - ( q - 1 ) ] e p ( q + m - 1 ) 2 ,    m ( p - 1 ) > q - 1 Mathematical equation(8)

Then the weak solution to problem (1) cannot vanish in finite time, where

E ( | u 0 | m - 1 u 0 ) = 1 p Ω | ( | u 0 | m - 1 u 0 ) | p d x - m q + m - 1 Ω | u 0 | q + m - 1 l o g | u 0 | d x [ + m q + m - 12 Ω u 0 q + m - 1 d x ] Mathematical equation(9)

Remark 1   From Theorems 2 and 3, we know that the critical extinction exponent of the global solutions to problem (1) is qec=m(p-1)+1Mathematical equation.

1 Proofs of the Main Results

Proof of Theorem 1   Multiplying both sides of the first equality in (4) by v(x,t)Mathematical equation and integrating over ΩMathematical equation, one gets

1 m + 1 d d t Ω | v | m + 1 m d x + Ω | v | p d x = 1 m Ω | v | m + q - 1 m l o g | v | d x Mathematical equation(10)

Remembering that q(1,2)Mathematical equation and m1Mathematical equation, we can select β(0,2-qm)Mathematical equation such that q+mβ(1,2)Mathematical equation. For this chosen βMathematical equation, we know log|v|1eβ|v|βMathematical equation. Then, from (10), it holds that

1 m + 1 d d t Ω | v | m + 1 m d x + Ω | v | p d x 1 e m β Ω | v | m + q - 1 m + β d x Mathematical equation(11)

By using Hölder's inequality, (11) leads to

d d t Ω | v | m + 1 m d x m + 1 e m β Ω | v | m + q - 1 m + β d x κ 1 ( Ω | v | m + 1 m d x ) m β + m + q - 1 m + 1 Mathematical equation(12)

where κ1=m+1emβ|Ω|2-q-mβm+1Mathematical equation. By a simple calculation, we get

Ω | v | m + 1 m d x [ ( Ω | v 0 | m + 1 m d x ) 2 - q - m β m + 1 + ( 2 - q - m β ) κ 1 m + 1 t ] m + 1 2 - q - m β Mathematical equation(13)

It follows from (13) and Hölder's inequality that

Ω | v | m β + m + q - 1 m d x | Ω | 2 - q - m β m + 1 ( Ω | v | m + 1 m d x ) m β + m + q - 1 m + 1 | Ω | 2 - q - m β m + 1 [ ( Ω | v 0 | m + 1 m d x ) 2 - q - m β m + 1 + ( 2 - q - m β ) κ 1 m + 1 t ] m β + m + q - 1 2 - q - m β Mathematical equation(14)

On the other hand, multiplying both sides of the first equality in (4) by vt=(|u|m-1u)tMathematical equation and integrating over ΩMathematical equation, then with the help of Hölder's inequality and Cauchy's inequality with εMathematical equation, we get

4 m 2 ( m + 1 ) 2 Ω [ ( | v | m + 1 2 m ) t ] 2 d x + m p d d t Ω | v | p d x = Ω | v | m + q - 1 m - 2 v l o g | v | v t d x = Ω 1 = { x Ω : | v | 1 } | v | m + q - 1 m - 2 v l o g | v | v t d x + Ω 2 = { x Ω : | v | < 1 } | v | m + q - 1 m - 2 v l o g | v | v t d x 2 m e β ( m + 1 ) Ω 1 | v | 2 m β + 2 q + m - 3 2 m | ( v m + 1 2 m ) t | d x + 4 m 2 e ( m + 1 ) ( m + 2 q - 3 ) Ω 2 | ( v m + 1 2 m ) t | d x m 2 ε 1 e β ( m + 1 ) Ω | v | 2 m β + 2 q + m - 3 2 m d x + 2 m ε 1 e β ( m + 1 ) Ω | ( v m + 1 2 m ) t | 2 d x + m 2 | Ω | e ε 2 ( m + 1 ) ( m + 2 q - 3 ) + 4 m 2 ε 2 e ( m + 1 ) ( m + 2 q - 3 ) Ω | ( v m + 1 2 m ) t | 2 d x Mathematical equation(15)

If ε1Mathematical equation and ε2Mathematical equation are sufficiently small such that ε1β+2mε2m+2q-32mem+1Mathematical equation, then from (15), it holds that

d d t Ω | v | p d x κ 3 + κ 2 ( Ω | v | m β + m + q - 1 m d x ) 2 m β + 2 q + m - 3 m β + m + q - 1 Mathematical equation(16)

where κ2=p2eβε1(m+1)|Ω|2-q-mβmβ+m+q-1Mathematical equation and κ3=mp|Ω|eε2(m+1)(m+2q-3)Mathematical equation. Combining (14) and (16) tells us that

d d t Ω | v | p d x κ 3 + κ 4 [ ( Ω | v 0 | m + 1 m d x ) 2 - q - m β m + 1 + ( 2 - q - m β ) κ 1 m + 1 t ] 2 m β + 2 q + m - 3 2 - q - m β Mathematical equation(17)

where κ4=κ2|Ω|(2-q-mβ)(2mβ+2q+m-3)(m+1)(mβ+m+q-1)Mathematical equation. Integrating (17), we arrive at

Ω | v | p d x Ω | v 0 | p d x - ( m + 1 ) κ 4 κ 1 ( m β + q + m - 1 ) ( Ω | v 0 | m + 1 m d x ) m β + q + m - 1 m + 1 + κ 3 t + ( m + 1 ) κ 4 κ 1 ( m β + q + m - 1 ) ( ( Ω | v 0 | m + 1 m d x ) 2 - q - m β m + 1 + ( 2 - q - m β ) κ 1 m + 1 t ) m β + q + m - 1 2 - q - m β Mathematical equation(18)

which implies that Ω|v|pdx=Ω|(|u|m-1u)|pdxMathematical equation is bounded for all t[0,+)Mathematical equation. The proof of Theorem 1 is complete.

Proof of Theorem 2   Multiplying both sides of the first equality in (4) by φ=|v|pav+=Mathematical equation|u|mpa(|u|m-1u)+Mathematical equation, we find that

1 m p a + m + 1 d d t Ω v + m p a + m + 1 m d x + p a + 1 ( a + 1 ) p Ω | v + a + 1 | p d x = 1 m Ω | v | q - 1 - m m v | v | p a v + l o g | v | d x 1 m e β Ω v + m ( p a + β + 1 ) + q - 1 m d x Mathematical equation(19)

By virtue of Hölder's inequality and Sobolev embedding inequality, we have

Ω v + m p a + m + 1 m d x | Ω | 1 - ( N - p ) ( m p a + m + 1 ) N p m ( a + 1 ) ( Ω ( v + a + 1 ) m p a + m + 1 m ( a + 1 ) · N p m ( a + 1 ) ( N - p ) ( m p a + m + 1 ) d x ) ( N - p ) ( m p a + m + 1 ) N p m ( a + 1 ) | Ω | 1 - ( N - p ) ( m p a + m + 1 ) N p m ( a + 1 ) κ 5 ( N - p ) ( m p a + m + 1 ) N p m ( a + 1 ) ( Ω | v + a + 1 | p d x ) m p a + m + 1 p m ( a + 1 ) Mathematical equation(20)

which implies that

Ω | v + a + 1 | p d x | Ω | ( N - p ) ( m + 1 ) - m p ( N + p a ) N ( m p a + m + 1 ) κ 5 p - N N ( Ω v + m p a + m + 1 m d x ) p m ( a + 1 ) m p a + m + 1 Mathematical equation(21)

where κ5=κ5(p,N)Mathematical equation is the optimal Sobolev embedding constant. Substituting (21) into (19) and using Hölder's inequality, we get

d d t Ω v + m p a + m + 1 m d x + κ 6 ( Ω v + m p a + m + 1 m d x ) p m ( a + 1 ) m p a + m + 1 κ 7 ( Ω v + m p a + m + 1 m d x ) m ( p a + β + 1 ) + q - 1 m p a + m + 1 Mathematical equation(22)

where

κ 6 = ( m p a + m + 1 ) ( p a + 1 ) ( a + 1 ) p κ 5 p - N N | Ω | ( N - p ) ( m + 1 ) - p m ( N + p a ) N ( m p a + m + 1 ) Mathematical equation(23)

and

κ 7 = m p a + m + 1 m e β | Ω | 1 - m ( p a + β + 1 ) + q - 1 m p a + m + 1 Mathematical equation(24)

Recalling that 0<m(p-1)<q-1Mathematical equation and q+mβ<2Mathematical equation, we check that

0 < p m ( a + 1 ) m p a + m + 1 < m ( p a + β + 1 ) + q - 1 m p a + m + 1 < 1 Mathematical equation(25)

On the other hand, our assumption (7) tells us that

0 < κ 7 < 1 2 κ 6 ( Ω v 0 + m p a + m + 1 m d x ) m ( p - 1 ) - ( q - 1 ) - m β m p a + m + 1 Mathematical equation(26)

Combining (22), (25), (26) and Lemma 1 [18], one can claim that there exist two positive constants ξMathematical equation and ηMathematical equation such that

0 y ( t ) : = Ω v + m p a + m + 1 m d x ξ e - η t ,    t 0 Mathematical equation(27)

Choosing

T 0 > m a x { 0 , 1 η l n [ ξ ( 2 κ 7 k 6 ) m p a + m + 1 q - 1 - m ( p - 1 ) + m β ] } Mathematical equation(28)

Then it follows from (22) and (27) that

d d t y ( t ) + κ 6 2 ( y ( t ) ) p m ( a + 1 ) m p a + m + 1 0 ,    t T 0 Mathematical equation(29)

Integrating above inequality, one has

0 y 1 - p m ( a + 1 ) m p a + m + 1 ( t ) y 1 - p m ( a + 1 ) m p a + m + 1 ( T 0 ) - κ 6 ( m + 1 - p m ) 2 ( m p a + m + 1 ) ( t - T 0 ) Mathematical equation(30)

which suggests that there exists a

T 0 ' [ T 0 , T 0 + 2 ( m p a + m + 1 ) κ 6 ( m + 1 - p m ) y m + 1 - p m m p a + m + 1 ( T 0 ) ] Mathematical equation(31)

such that

l i m t T 0 ' - y ( t ) = l i m t T 0 ' - Ω v + m p a + m + 1 m ( t ) d x = 0 Mathematical equation(32)

Moreover, it can be concluded that

Ω v + ( t ) d x | Ω | m p a + 1 m p a + m + 1 ( Ω v + m p a + m + 1 m d x ) m m p a + m + 1 0   a s   t T 0 ' - Mathematical equation(33)

On the other hand, by a similar way, it can be shown that Ωv-(t)dxMathematical equation will vanish in finite time. Thus Ω|v(t)|dx=Ωv+(t)dx+Ωv-(t)dxMathematical equation vanishes in finite time. Recalling that v=|u|m-1uMathematical equation, one can claim that the solution u(x,t)Mathematical equation to problem (1) possesses the extinction property. The proof of Theorem 2 is completed.

Proof of Theorem 3   Denoting

E ( v ( t ) ) = 1 p Ω | v | p d x - 1 q + m - 1 Ω | v | q + m - 1 m l o g | v | d x + m ( q + m - 1 ) 2 Ω | v | q + m - 1 m d x Mathematical equation(34)

with v=|u|m-1uMathematical equation, then a direct calculation shows that

d E ( v ( t ) ) d t = - 4 m ( m + 1 ) 2 Ω [ ( v m + 1 2 m ) t ] 2 d x Mathematical equation(35)

which implies

E ( v ( t ) ) = E ( v 0 ) - 4 m ( m + 1 ) 2 0 t Ω [ ( v m + 1 2 m ) t ] 2 d x d τ Mathematical equation(36)

Set

M ( t ) = 1 m + 1 Ω | v | m + 1 m d x Mathematical equation(37)

A direct calculation tells us that

M ' ( t ) = - Ω | v | p d x + 1 m Ω | v | q + m - 1 m l o g | v | d x = - p E ( v ( t ) ) + q - 1 - m ( p - 1 ) m ( q + m - 1 ) Ω | v | q + m - 1 m l o g | v | d x   + m p ( q + m - 1 ) 2 Ω | v | q + m - 1 m d x - p E ( v ( t ) ) + q - 1 - m ( p - 1 ) m ( q + m - 1 ) Ω | v | q + m - 1 m l o g | v | d x Mathematical equation(38)

By virtue of (36), (38) and Hölder's inequality, one derives

M ' ( t ) - p E ( v 0 ) - m ( p - 1 ) - ( q - 1 ) q + m - 1 Ω 1 = { x Ω : | v | 1 } Ω 2 = { x Ω : | v | < 1 } | v | q + m - 1 m | l o g | v | | d x - p E ( v 0 ) - m ( p - 1 ) - ( q - 1 ) q + m - 1 ( 1 e β Ω 1 | v | m β + m + q - 1 m d x + m | Ω | e ( m + q - 1 ) ) - p E ( v 0 ) - m ( p - 1 ) - ( q - 1 ) e β ( q + m - 1 ) | Ω | 2 - q - m β m + 1 ( Ω | v | m + 1 m d x ) m β + m + q - 1 m + 1 - [ m ( p - 1 ) - ( q - 1 ) ] m | Ω | e ( q + m - 1 ) 2 Mathematical equation(39)

If m(p-1)=q-1Mathematical equation. Then from (39), one can see that, for any t0Mathematical equation,

M ( t ) M ( 0 ) - p E ( v 0 ) t Mathematical equation(40)

Keeping in mind that

M ( 0 ) = 1 m + 1 Ω | v 0 | m + 1 m d x = 1 m + 1 Ω | u 0 | m + 1 d x > 0 Mathematical equation(41)

and

E ( v 0 ) = E ( | u 0 | m - 1 u 0 ) 0 Mathematical equation(42)

then (40) gives us that M(t)>0Mathematical equation, which means that the solution u(x,t)Mathematical equation to problem (1) cannot vanish in finite time.

If m(p-1)q-1Mathematical equation. Remembering that

M ( 0 ) = 1 m + 1 Ω | v 0 | m + 1 m d x = 1 m + 1 Ω | u 0 | m + 1 d x > 0 Mathematical equation(43)

and

E ( v 0 ) = E ( | u 0 | m - 1 u 0 ) < - m | Ω | [ m ( p - 1 ) - ( q - 1 ) ] e p ( q + m - 1 ) 2 Mathematical equation(44)

combining (39) and Lemma 1.2 [19] gives us that, for any t0Mathematical equation,

M ( t ) m i n { M ( 0 ) , ( κ 8 κ 9 ) m + 1 m β + q + m - 1 } > 0 Mathematical equation(45)

which means that the solution u(x,t)Mathematical equation to problem (1) cannot vanish in finite time, where

κ 8 = - ( p E ( v 0 ) + [ m ( p - 1 ) - ( q - 1 ) ] m | Ω | e ( q + m - 1 ) 2 ) > 0 Mathematical equation(46)

κ 9 = m ( p - 1 ) - ( q - 1 ) e β ( q + m - 1 ) | Ω | 2 - q - m β m + 1 > 0 Mathematical equation(47)

The proof of Theorem 3 is completed.

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