Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 28, Number 1, February 2023
Page(s) 1 - 10
DOI https://doi.org/10.1051/wujns/2023281001
Published online 17 March 2023

© Wuhan University 2023

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

In this paper, we study the following three-dimensional Brinkman-Forchheimer equation:

{ u t - γ Δ u + a u + b | u | u + c | u | β u + p = f ( x ) ,   ( x , t ) Ω × R + d i v u = 0 ,                                                                  ( x , t ) Ω × R + u ( x , t ) | Ω = 0 ,                                                        ( x , t ) Ω × R + u ( x , 0 ) = u 0 ( x ) ,                                                                     x Ω Mathematical equation(1)

where a>0Mathematical equation is the Darcy coefficient, b>0,c>0Mathematical equation are the Forchheimer coefficients, β>0Mathematical equation is a constant, and ΩR3Mathematical equation is an open and bounded set, which is sufficiently regular. Here u=(u1(x,t),u2(x,t),u3(x,t))Mathematical equation is the fluid velocity vector, p(x,t)Mathematical equation denotes the pressure field, f(x)Mathematical equation is the external force, γMathematical equation is the Brinkman coefficient and u0=u0(x)Mathematical equation is the initial velocity.

As a mathematical model, Brinkman-Forchheimer equation describes the motion of a fluid flowing in saturated porous media [1-3], which has received much attention on several issues over the last decades. From a mathematical point of view, the research on the three-dimensional Brinkman-Forchheimer equation is mainly divided into two categories. One is the structural stability of the equation with respect to the coefficients γ,bMathematical equation and cMathematical equation[4-9], and the other is the long-term behavior of the solution of the equation [10-18].

If a system has a global attractor, then the attractor will contain all possible limit states of the solutions of the system. Therefore, studying the dynamic system restricted to the global attractor will be able to reveal a lot of information about the original system. So proving the existence of global attractors is a basic and important problem in infinite-dimensional dynamical systems. For the 3D Brinkman-Forchheimer equation, Ugurlu [10], Ouyang and Yang [11] showed the existence of global attractor in (H01(Ω))3Mathematical equation when β=2Mathematical equation and 1<β<4/3Mathematical equation by condition-(C) method, respectively. Wang and Lin[12] showed the existence of global attractor in (H2(Ω))3Mathematical equation when β=2Mathematical equation. In Ref.[13], the existence of DMathematical equation-pullback attractors for three-dimensional non-autonomous Brinkman-Forchheimer equation is deduced by establishing the DMathematical equation-pullback asymptotical compactness of θMathematical equation-cocycle. In Ref.[14], Song et al discussed the L2Mathematical equation decay of the weak solution of the Brinkman-Forchheimer equation in three-dimensional full space. In Ref.[15], Song and Wu investigated the uniform boundedness of uniform attractor Aε Mathematical equationof equation (1) with singularly oscillating external force. They established the convergence of the attractor AεMathematical equation to the attractor A0Mathematical equation of the averaged equation as ε0+Mathematical equation. In Ref.[16], the pullback dynamics and asymptotic stability for a 3D Brinkman-Forchheimer equation with finite delay was concerned. In Ref.[17], by some estimates and the variable index to deal with the delay term, Yang et al got the sufficient conditions for asymptotic stability of trajectories inside the pullback attractors for a fluid flow model in porous medium by generalized Grashof numbers. In Ref.[18], Qiao et al proved the existence of a global attractor for the strong solution of the Brinkman-Forchheimer equation in a three-dimensional bounded domain.

In the geometric structure of the global attractor, the dimension is a very important property. This is because if the fractal dimension of the global attractor is finite, the original infinite-dimensional dynamical system can be reduced to a finite-dimensional ordinary differential equation system, so that the relatively complete theory of the finite-dimensional dynamical system can be used to study infinite dimensional dynamical system. As far as we know, there is no results on dimension estimate of global attractor of 3D Brinkman-Forchheimer. In this paper, inspired by Refs.[19-21], based on Ref.[18], we will discuss the Hausdorff dimension and fractal dimension of global attractors for strong solutions of the equation.

The structure of this paper is arranged as follows: In Section 1, we give some function space symbols and some inequalities that will be used later. In Section 2, we discuss the Hausdorff dimension and fractal dimension of global attractors for strong solution of the equation.

1 Preliminaries

In this section, we introduce some notations and preliminaries, which will be used throughout this paper.

First, let us introduce the following function spaces:

E = { u ( C 0 ( Ω ) ) 3 :   d i v u = 0 } ,   H = c l ( L 2 ( Ω ) ) 3 E ,   V = c l ( H 0 1 ( Ω ) ) 3 E , Mathematical equation

where clXMathematical equation denotes the closure in space XMathematical equation. HMathematical equation is the closure of the set EMathematical equation in (L2(Ω))3Mathematical equation topology, and VMathematical equation is the closure of the set EMathematical equation in (H01(Ω))3Mathematical equation topology. H'Mathematical equation and V'Mathematical equation are the dual spaces of HMathematical equation and VMathematical equation, respectively. HMathematical equation and VMathematical equation are equipped with the following inner products:

( u , v ) = Ω u v d x , u , v H , ( ( u , v ) ) = i = 1 3 Ω u i v i d x , u , v V ,    Mathematical equation

and norms =(,)12, V=((,))12.Mathematical equation Let Lp(Ω)=(Lp(Ω))3, H2(Ω)=(H2(Ω))3.Mathematical equation Throughout this paper, we use pMathematical equation to denote the norm in Lp(Ω)Mathematical equation. CMathematical equation or CiMathematical equation will stand for some generic positive constants, depending on ΩMathematical equation and some constants, but independent of time tMathematical equation.

We call uL(0,T;H)L2(0,T;V)Lβ+2(0,T;Lβ+2(Ω))Mathematical equation is a weak solution of problem (1) on [0,T]Mathematical equation, if

{ d d t ( u , v ) + γ ( ( u , v ) ) + a ( u , v ) + ( b | u | u , v ) + ( c | u | β u , v ) = ( f , v ) , v V , t > 0 u ( 0 ) = u 0                                                                                                                    Mathematical equation(2)

The weak form (2) is equivalent to the following functional equation:

{ d u d t + γ A u + a u + B ( u ) = f , t > 0 u ( 0 ) = u 0                                            Mathematical equation(3)

Here A=-PHΔMathematical equation is the Stokes operator subject to the no-slip homogeneous Dirichlet boundary condition with the domain (H2(Ω))3VMathematical equation defined as Au,v=((u,v))Mathematical equation. PHMathematical equation is the orthogonal projection from L2(Ω)Mathematical equation onto HMathematical equation. F(u)=b|u|u+c|u|βu,Mathematical equationB(u)=PHF(u),fH.Mathematical equation Obviously, the operator AMathematical equation is a non-negative self-adjoint operator in HMathematical equation with V=D(A1/2)Mathematical equation and Au,u=uV,Mathematical equation for all uVMathematical equation.

For a bounded domain ΩMathematical equation, the operator AMathematical equation is invertible, and its inverse operator A-1Mathematical equation is bounded, self-adjoint and compact in HMathematical equation. Thus, the spectrum of AMathematical equation consists of an infinite sequence 0<λ1λ2λk,Mathematical equation with λkMathematical equation as its eigenvalue kMathematical equation (Theorem 2.2, Corollary 2.2, Ref.[22]). For all k1Mathematical equation and nN,Mathematical equation we have λkC˜k2/n,Mathematical equation where C˜=n2+n((2π)nωn(n-1)|Ω|)2/n, ωn=πn/2Γ(1+n2),Mathematical equation and |Ω|Mathematical equation is the n-dimensional Lebesgue measure of ΩMathematical equation. For n=3,Mathematical equation we find

C ˜ = 3 1 / 3 2 8 / 3 π 2 / 3 5 | Ω | 2 / 3 Mathematical equation(4)

Next we formulate some well-known inequalities and a Gronwall type lemma that we will use in what follows.

Poincaré's inequality [23]:

u 2 1 λ 1 u 2 , u V Mathematical equation(5)

where λ1Mathematical equation is the first eigenvalue of operator A=-PHΔMathematical equation under the homogeneous Dirichlet boundary condition.

Agmon's inequality [23]:

u C 1 u 1 / 2 Δ u 1 / 2 , u D ( A ) Mathematical equation(6)

C q Mathematical equation-inequality [24]:

| x q - y q | C q ( | x | q - 1 + | y | q - 1 ) | x - y | , f o r   t h e   i n t e g e r [    q 2 ] Mathematical equation(7)

Series inequlity[25]:

k = m n k p < 1 p + 1 ( n p + 1 - ( m - 1 ) p + 1 ) , f o r   [ - 1 < p < 0 , n > m ] Mathematical equation(8)

Lemma 1   (Gagliardo-Nirenberg's inequality) [24] Assuming that Ω=RnMathematical equation or ΩRnMathematical equation be a bounded domain, which has a sufficiently smooth boundary ΩMathematical equation, uLq(Ω),DmuLr(Ω),Mathematical equation1q,rMathematical equation. Then there is a constant C>0Mathematical equation such that DjupCDmurauq1-a,Mathematical equationwhere 1p=jn+a(1r-mn)+(1-a)1q,1p,0jm,jma1,Mathematical equationCMathematical equation depends on n,m,j,a,q,r.

Lemma 2   ( Gronwall's inequality) [23] Let u(t), k(t)Mathematical equation be non-negative integrable functions on [0,T]Mathematical equation. If there is K>0Mathematical equation, such that u(t)K+0tk(s)u(s)ds,t[0,T],Mathematical equationthen u(t)Kexp(0tk(s)ds),t[0,T].Mathematical equation

Now we recall the existence and uniqueness theorem of the strong solutions of equation (1).

Theorem 1[18]Suppose β>0, u0VLβ+2(Ω)Mathematical equation and fHMathematical equation. Then there exists a strong solution of equation (1) satisfying

u L ( 0 , T ; V ) L ( 0 , T ; L β + 2 ( Ω ) ) L 2 ( 0 , T ; ( H 2 ( Ω ) ) 3 ) , u | u | β / 2 L 2 ( 0 , T ; H ) , u t L 2 ( 0 , T ; H ) . Mathematical equation

Moreover when 5/2β4,Mathematical equation the strong solution is unique.

Now we will review the uniform estimates of strong solution to the problem (1) when tMathematical equation.

Lemma 3[18] Suppose 5/2β4, u0V, fH.Mathematical equation Then there exists a time t0Mathematical equation, constants ρ1,I1,Mathematical equation such that when t>t0,Mathematical equation we have u(t)ρ1,Mathematical equationtt+1u(s)V2ds+tt+1u(s)2ds+tt+1u(s)33ds+tt+1u(s)β+2β+2dsI1,Mathematical equationfor t>t0Mathematical equation.

Lemma 4[18]Suppose 5/2β4, u0V,fH.Mathematical equation Then there exists a time t1Mathematical equation,a constant ρ2,Mathematical equation such that u(t)V+u(t)+u(t)3+u(t)β+2ρ2,t>t1.Mathematical equation

Lemma 5[18] Suppose 5/2β4, u0V,fH.Mathematical equation Then there exists a time t2Mathematical equation,a constant ρ3,Mathematical equation such that ut(s)ρ3,st2.Mathematical equation

Lemma 6[18]Suppose 5/2β4,u0V, fH.Mathematical equation Then there exists a constant ρ4,Mathematical equation such that Au(t)ρ4,tt2.Mathematical equation

Finally, we give the result of existence of global attractor in VMathematical equation for the 3D Brinkman-Forchheimer equation.

Theorem 2[18]Suppose 5/2β4, u0V, fH.Mathematical equation Then the problem (1) has a global attractor AVMathematical equation in VMathematical equation, which is invariant and compact in VMathematical equation and attracts every bounded subset of VMathematical equation with the norm in VMathematical equation.

2 Estimates of Dimensions of the Global Attractor

In this section, we will establish the differentiability of the semigroup with respect to the initial data. We show that the global attractor of the 3D Brinkman-Forchheimer system has finite Hausdorff and fractal dimensions. We will use the similar techniques as in Refs.[19-21], etc to obtain the desired results.

Let u()Mathematical equation be the unique strong solution of the autonomous system (1) belonging to the global attractor AVMathematical equation.

Let us take inner product with -ΔuMathematical equation in HMathematical equation to the first equation in (1) to obtain

   d d t u V 2 + 2 γ Δ u + 2 2 a u V 2 + 2 b Ω | u | | u | 2 d x + 8 b 9 Ω | | u | 3 / 2 | 2 d x + 2 c Ω | u | β | u | 2 d x + 8 c β ( β + 2 ) 2 Ω | | u | β + 2 2 | 2 d x Mathematical equation

= - 2 ( f , Δ u ) 2 f Δ u γ Δ u 2 + 1 γ f 2 Mathematical equation(9)

So we have

d d t u V 2 + 2 a u V 2 1 γ f 2 Mathematical equation(10)

Applying Gronwall's inequality, we find

u V 2 u 0 V 2 e - 2 a t + f 2 2 a γ , t > 0 Mathematical equation(11)

So there is a time t'Mathematical equation which we can take as t'=max{-12alnf22aγu0V2,0}Mathematical equation, such that for all tt'Mathematical equation, we have

u V 2 f 2 a γ = M 1 2 , M 1 = f a γ Mathematical equation(12)

Integrating the inequality (10) from 0 to TMathematical equation, we obtain

u ( T ) V 2 + 2 a 0 T u ( s ) V 2 d s u 0 V 2 + T γ f 2 Mathematical equation(13)

so we get

l i m T s u p 1 T 0 T u ( t ) V 2 d t K 1 = f 2 2 a γ Mathematical equation(14)

Theorem 3   Let u0Mathematical equation and v0Mathematical equation be two members of AVMathematical equation. Then there exists a constant K=K(u0V,v0V)Mathematical equation such that

S ( t ) u 0 - S ( t ) v 0 - Λ ( t ) ( u 0 - v 0 ) V K u 0 - v 0 V Mathematical equation(15)

where the linear operator Λ(t):VV,Mathematical equation for t>0Mathematical equation is the solution operator of the problem:

{ d ξ d t + γ A ξ + a ξ + 2 b P H ( | u ( t ) | ξ ( t ) ) + c ( β + 1 ) P H ( | u ( t ) | β ξ ( t ) ) = 0 , t ( 0 , T ) ξ ( 0 ) = ξ 0 V                                                                                                             Mathematical equation(16)

ξ 0 = u 0 - v 0 Mathematical equation and u(t)=S(t)u0Mathematical equation, v(t)=S(t)v0Mathematical equation. In other words, for every t>0Mathematical equation, the solution S(t)u0Mathematical equation as a map S(t):VVMathematical equation is Fréchet differentiable for the initial data, and its Fréchet derivative Du0(S(t)u0)w0=Λ(t)w0Mathematical equation.

Proof   Let S(t)u0=u(t), S(t)v0=v(t),Mathematical equation for any t0.Mathematical equation Then we have

{ d u d t + γ A u + a u + P H ( b | u | u + c | u | β u ) = f u ( 0 ) = u 0                                                            Mathematical equation(17)

and

{ d v d t + γ A v + a v + P H ( b | v | v + c | v | β v ) = f v ( 0 ) = v 0                                                           Mathematical equation(18)

Let w(t)=u(t)-v(t)Mathematical equation. Combining (17) with (18), we obtain

{ d w d t + γ A w + a w + P H ( b | u | u - b | v | v + c | u | β u - c | v | β v ) = 0 w ( 0 ) = u 0 - v 0                                                                                     Mathematical equation(19)

Let us define η(t)=u(t)-v(t)-ξ(t)=S(t)(u0-v0)-ξ(t)Mathematical equation. Then η(t)Mathematical equation satisfies:

{ d η ( t ) d t + γ A η ( t ) + a η ( t ) + P H ( b | u ( t ) | u ( t ) - b | v ( t ) | v ( t ) + c | u ( t ) | β u ( t ) - c | v ( t ) | β v ( t ) )    - 2 b P H ( | u ( t ) | ξ ( t ) ) - c ( β + 1 ) P H ( | u ( t ) | β ξ ( t ) ) = 0   η ( 0 ) = 0                                                                                                                                  Mathematical equation(20)

Let us take inner product with Aη(t)Mathematical equation in HMathematical equation to the first equation in (20) to obtain

1 2 d d t η ( t ) 2 + γ A η ( t ) 2 + a η ( t ) 2 = 2 b ( P H ( | u ( t ) | w ( t ) ) , A η ( t ) ) - 2 b ( P H ( | u ( t ) | η ( t ) ) , A η ( t ) ) + c ( β + 1 ) ( P H ( | u ( t ) | β w ( t ) ) , A η ( t ) ) - c ( β + 1 ) ( P H ( | u ( t ) | β η ( t ) ) , A η ( t ) ) - ( P H ( b | u ( t ) | u ( t ) - b | v ( t ) | v ( t ) + c | u ( t ) | β u ( t ) - c | v ( t ) | β v ( t ) ) , A η ( t ) ) Mathematical equation(21)

Let us consider the first term on the right-hand side of (21). We have

2 b ( P H ( | u ( t ) | w ( t ) ) , A η ( t ) ) γ 5 A η ( t ) 2 + 5 b 2 γ Ω | u ( t ) | 2 | w ( t ) | 2 d x γ 5 A η ( t ) 2 + 5 b 2 γ u ( t ) w ( t ) 2 w ( t ) 2 γ 5 A η ( t ) 2 + 5 b 2 C 1 2 γ u ( t ) Δ u ( t ) w ( t ) 2 γ 5 A η ( t ) 2 + C w ( t ) 2 Mathematical equation(22)

In (22), Agmon's inequality is used. And in the last inequality of (22), because u0,v0Mathematical equation are members of AVMathematical equation, so we used the uniform estimates of solutions in Lemma 4 and Lemma 6 to obtain the desired result.

Similar with (22), for the second term on the right-hand side of (21), we have

- 2 b ( P H ( | u ( t ) | η ( t ) ) , A η ( t ) ) γ 5 A η ( t ) 2 + 5 b 2 C 1 2 γ u ( t ) Δ u ( t ) η ( t ) 2 γ 5 A η ( t ) 2 + C η ( t ) 2 Mathematical equation(23)

For the third term on the right-hand side of (21), we get

c ( β + 1 ) ( P H ( | u ( t ) | β w ( t ) ) , A η ( t ) ) γ 5 A η ( t ) 2 + 5 c 2 ( β + 1 ) 2 4 γ Ω | u ( t ) | 2 β | w ( t ) | 2 d x γ 5 A η ( t ) 2 + 5 c 2 ( β + 1 ) 2 4 γ u ( t ) 2 β w ( t ) 2 γ 5 A η ( t ) 2 + 5 c 2 ( β + 1 ) 2 C 1 2 β 4 γ u ( t ) β Δ u ( t ) β w ( t ) 2 γ 5 A η ( t ) 2 + C w ( t ) 2 Mathematical equation(24)

Similar with (24), for the fourth term on the right-hand side of (21), we have

- c ( β + 1 ) ( P H ( | u ( t ) | β η ( t ) ) , A η ( t ) ) γ 5 A η ( t ) 2 + 5 c 2 ( β + 1 ) 2 C 1 2 β 4 γ u ( t ) β Δ u ( t ) β η ( t ) 2 γ 5 A η ( t ) 2 + C η ( t ) 2 Mathematical equation(25)

For the fifth term on the right-hand side of (21), we have

- ( P H ( b | u ( t ) | u ( t ) - b | v ( t ) | v ( t ) + c | u ( t ) | β u ( t ) - c | v ( t ) | β v ( t ) ) , A η ( t ) ) γ 5 A η ( t ) 2 + 5 2 γ Ω | b | u ( t ) | u ( t ) - b | v ( t ) | v ( t ) | 2 d x + 5 2 γ Ω | c | u ( t ) | β u ( t ) - c | v ( t ) | β v ( t ) | 2 d x Mathematical equation

γ 5 A η ( t ) 2 + C Ω ( | u ( t ) | | w ( t ) | + | | u | - | v | | | v | ) 2 d x + C Ω ( | u ( t ) | β | w ( t ) | + | | u ( t ) | β - | v ( t ) | β | | v ( t ) | ) 2 d x γ 5 A η ( t ) 2 + C Ω | u ( t ) | 2 | w ( t ) | 2 d x + C Ω | v ( t ) | 2 | w ( t ) | 2 d x + C Ω | u ( t ) | 2 β | w ( t ) | 2 d x + C Ω | | u ( t ) | β - 1 + | v ( t ) | β - 1 | 2 | v ( t ) | 2 | w ( t ) | 2 d x Mathematical equation

γ 5 A η ( t ) 2 + C u ( t ) 4 2 w ( t ) 4 2 + C v ( t ) 4 2 w ( t ) 4 2 + C u ( t ) 3 β 2 β w ( t ) 6 2 + C ( u ( t ) 6 ( β - 1 ) 2 ( β - 1 ) + v ( t ) 6 ( β - 1 ) 2 ( β - 1 ) ) v ( t ) 6 2 w ( t ) 6 2 γ 5 A η ( t ) 2 + C u ( t ) 2 w ( t ) 2 + C v ( t ) 2 w ( t ) 2 + C u ( t ) β + 2 2 ( β + 2 ) 2 β + 8 Δ u ( t ) 8 ( β - 1 ) β + 8 w ( t ) 2      + C ( u ( t ) β + 2 2 ( β 2 + 2 β ) β + 8 Δ u ( t ) 10 β - 16 β + 8 + v ( t ) β + 2 2 ( β 2 + 2 β ) β + 8 Δ v ( t ) 10 β - 16 β + 8 ) v ( t ) 2 w ( t ) 2 γ 5 A η ( t ) 2 + C w ( t ) 2 Mathematical equation(26)

In inequality (26), we used CqMathematical equation-inequality and the following Gagliardo-Nirenberg's inequality:

u ( t ) 3 β 2 β C u ( t ) β + 2 2 ( β + 2 ) 2 β + 8 Δ u ( t ) 8 ( β - 1 ) β + 8 ,   u ( t ) 6 ( β - 1 ) 2 ( β - 1 ) C u ( t ) β + 2 2 ( β 2 + 2 β ) β + 8 Δ u ( t ) 10 β - 16 β + 8   Mathematical equation

Combining (21)-(26), we find

d d t η ( t ) 2 + 2 a η ( t ) 2 C w ( t ) 2 + C η ( t ) 2 + C w ( t ) 2 Mathematical equation(27)

Taking inner product with AwMathematical equation in HMathematical equation to the first equation of (19), we have

1 2 d d t w ( t ) 2 + γ A w ( t ) 2 + a w ( t ) 2 + b ( P H ( | u ( t ) | u ( t ) - | v ( t ) | v ( t ) ) , A w ( t ) ) + c ( P H ( | u ( t ) | β u ( t ) - | v ( t ) | β v ( t ) ) , A w ( t ) ) = 0 Mathematical equation(28)

where

| b ( P H ( | u ( t ) | u ( t ) - | v ( t ) | v ( t ) ) , A w ( t ) ) | γ 2 A w ( t ) 2 + b 2 2 γ | u ( t ) | u ( t ) - | v ( t ) | v ( t ) 2 Mathematical equation(29)

and

| c ( P H ( | u ( t ) | β u ( t ) - | v ( t ) | β v ( t ) ) , A w ( t ) ) | γ 2 A w ( t ) 2 + c 2 2 γ | u ( t ) | β u ( t ) - | v ( t ) | β v ( t ) 2 Mathematical equation(30)

For the second term on the right-hand side of (29), from inequality (26), we have

b 2 2 γ Ω | | u ( t ) | u ( t ) - | v ( t ) | v ( t ) | 2 d x C u ( t ) 2 w ( t ) 2 + C v ( t ) 2 w ( t ) 2 C w ( t ) 2 Mathematical equation(31)

For the second term on the right-hand side of (30), we have

c 2 2 γ Ω | | u ( t ) | β u ( t ) - | v ( t ) | β v ( t ) | 2 d x C u ( t ) β + 2 2 ( β + 2 ) 2 β + 8 Δ u ( t ) 8 ( β - 1 ) β + 8 w ( t ) 2 + C ( u ( t ) β + 2 2 ( β 2 + 2 β ) β + 8 Δ u ( t ) 10 β - 16 β + 8 + v ( t ) β + 2 2 ( β 2 + 2 β ) β + 8 Δ v ( t ) 10 β - 16 β + 8 ) v ( t ) 2 w ( t ) 2   C w ( t ) 2 Mathematical equation(32)

Combining (29)-(32) with (28), we obtain

d d t w ( t ) 2 C w ( t ) 2 Mathematical equation(33)

Integrating (33 ) from 0 to tMathematical equation, we have

w ( t ) 2 w ( 0 ) 2 + C 0 t w ( s ) 2 d s Mathematical equation(34)

Applying Gronwall's inequality to (34), we get

w ( t ) 2 w ( 0 ) 2 e C t w ( 0 ) 4 + 1 2 e C t Mathematical equation(35)

Integrating (27) from 0 to tMathematical equation, due to (35), we infer that

η ( t ) V 2 C 0 t w ( s ) 2 d s + C 0 t η ( s ) 2 d s + C 0 t w ( s ) 2 d s C 0 t w ( s ) 2 d s + C 0 t η ( s ) V 2 d s C w ( 0 ) 4 e C t + C 0 t η ( s ) V 2 d s Mathematical equation(36)

An application of Gronwall's inequality in (36) yields

η ( t ) V 2 C w ( 0 ) 4 e 2 C t Mathematical equation(37)

Thus

u ( t ) - v ( t ) - ξ ( t ) V u 0 - v 0 V C u 0 - v 0 V e C t Mathematical equation(38)

which completes the proof.

Now we rewrite the system (3) as

{ d u ( t ) d t + γ A u ( t ) + a u ( t ) + b P H ( | u ( t ) | u ( t ) ) + c P H ( | u ( t ) | β u ( t ) ) = f u ( 0 ) = u 0 V                                                                                        Mathematical equation(39)

Let us now set u˜=A1/2u,v˜=A1/2v,Mathematical equation and using it in (39) to obtain

{ d u ˜ ( t ) d t = - γ A u ˜ ( t ) - a u ˜ ( t ) - b A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 u ˜ ( t ) ) - c A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 u ˜ ( t ) ) + A 1 / 2 f   u ˜ ( 0 ) = A 1 / 2 u 0                                                                                                                                                  Mathematical equation(40)

where A1/2u0HMathematical equation. Note that the systems (40) and (39) are equivalent. Remember that the systems (39) is well posed in VMathematical equation, while the system (40) is well posed in HMathematical equation. Therefore, there exists a unique weak solution u˜()Mathematical equation of (40) in C([0,T];H)Mathematical equation. Moreover, the system (40) generates one family of strongly continuous semigroup S˜(t)Mathematical equation of solution operators

S ˜ ( t ) : H H , u ˜ 0 u ˜ ( t ) = S ˜ ( t ) u ˜ 0 . Mathematical equation

Since u˜(t)=A1/2u(t)Mathematical equation and u˜0=A1/2u0Mathematical equation, the semigroup S˜(t)Mathematical equation is connected to the original semigroup S(t)Mathematical equation through the relation

S ˜ ( t ) = A 1 / 2 S ( t ) A - 1 / 2 Mathematical equation(41)

Thus, the semigroup S˜(t)Mathematical equation has the global attractor ÃHMathematical equation, where

A ̃ H = A 1 / 2 A V Mathematical equation(42)

and AVMathematical equation is the global attractor for S(t)Mathematical equation.

Now we will show a bound for the fractal dimension of ÃHMathematical equation in HMathematical equation. Besides, using the following argument, the fractal dimension AVMathematical equation in VMathematical equation can easily yield the same bound. From Proposition 3.1, Chapter VI of Ref.[23], we know that under the Lipschitz maps, the fractal dimension estimates can be obtained. Furthermore, we infer that

d i m F V ( A V ) = d i m F V ( A - 1 / 2 A ̃ H ) = d i m F H ( A ̃ H ) Mathematical equation(43)

Let us first consider the linear variations of the system (40). The linear variational equation corresponding to (40) has this form

d w ( t ) d t = L ( t , u ˜ ) w ( t ) Mathematical equation(44)

where

L ( t , u ˜ ) w ( t ) = - γ A w ( t ) - a w ( t ) - 2 b A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 w ( t ) ) - ( β + 1 ) c A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 w ( t ) ) Mathematical equation(45)

The adjoint L*(t,u˜)Mathematical equation of L(t,u˜)Mathematical equation is given by

L * ( t , u ˜ ) w ( t ) = - γ A w ( t ) - a w ( t ) - 2 b A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 w ( t ) ) - ( β + 1 ) c A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 w ( t ) ) Mathematical equation(46)

Hence, L˜(t,u˜)w(t)=L(t,u˜)w(t)+L*(t,u˜)w(t)Mathematical equation can be computed as

L ˜ ( t , u ˜ ) w ( t ) = - 2 γ A w ( t ) - 2 a w ( t ) - 4 b A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 w ( t ) ) - 2 ( β + 1 ) c A 1 / 2 P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 w ( t ) ) Mathematical equation(47)

Then, we derive the following results.

Proposition 1   Let wHMathematical equation. Then, we have

( L ˜ ( t , u ˜ ) w ( t ) , w ( t ) ) - 2 a w ( t ) 2 + ( 4 b 2 C 1 2 γ λ 1 Δ u 2 + 4 ( β + 1 ) 2 c 2 C 1 2 β γ λ 1 β / 2 Δ u 2 β ) A - 1 / 2 w ( t ) 2 Mathematical equation(48)

where γ>0,b>0,c>0,C1>0Mathematical equation is given in (6) which only depends on ΩMathematical equation.

Proof   Let us take the inner product with w(t)Mathematical equation in HMathematical equation to equation (47), we obtain

( L ˜ ( t ) w ( t ) , w ( t ) ) = - 2 γ A 1 / 2 w ( t ) 2 - 2 a w ( t ) 2 - 4 b ( P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 w ( t ) ) , A 1 / 2 w ( t ) ) - 2 ( β + 1 ) c ( P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 w ( t ) ) , A 1 / 2 w ( t ) ) Mathematical equation(49)

And because

| 4 b ( P H ( | A - 1 / 2 u ˜ ( t ) | A - 1 / 2 w ( t ) ) , A 1 / 2 w ( t ) ) | 4 b Ω | A - 1 / 2 u ˜ ( t ) | | A - 1 / 2 w ( t ) | | A 1 / 2 w ( t ) | d x 4 b A - 1 / 2 u ˜ ( t ) A - 1 / 2 w ( t ) A 1 / 2 w ( t ) γ A 1 / 2 w ( t ) 2 + 4 b 2 γ u 2 A - 1 / 2 w ( t ) 2 γ A 1 / 2 w ( t ) 2 + 4 b 2 C 1 2 γ u Δ u A - 1 / 2 w ( t ) 2 γ A 1 / 2 w ( t ) 2 + 4 b 2 C 1 2 γ λ 1 Δ u 2 A - 1 / 2 w ( t ) 2 Mathematical equation(50)

and

| 2 ( β + 1 ) c ( P H ( | A - 1 / 2 u ˜ ( t ) | β A - 1 / 2 w ( t ) ) , A 1 / 2 w ( t ) ) | 2 ( β + 1 ) c Ω | A - 1 / 2 u ˜ ( t ) | β | A - 1 / 2 w ( t ) | | A 1 / 2 w ( t ) | d x 2 ( β + 1 ) c A - 1 / 2 u ˜ ( t ) β A - 1 / 2 w ( t ) A 1 / 2 w ( t ) γ A 1 / 2 w ( t ) 2 + 4 ( β + 1 ) 2 c 2 γ u 2 β A - 1 / 2 w ( t ) 2 γ A 1 / 2 w ( t ) 2 + 4 ( β + 1 ) 2 c 2 C 1 2 β γ u β Δ u β A - 1 / 2 w ( t ) 2 γ A 1 / 2 w ( t ) 2 + 4 ( β + 1 ) 2 c 2 C 1 2 β γ λ 1 β / 2 Δ u 2 β A - 1 / 2 w ( t ) 2 Mathematical equation(51)

Combining (50) and (51) with (49), we deduce that

( L ̃ ( t ) w ( t ) , w ( t ) ) - 2 a w ( t ) 2 + ( 4 b 2 C 1 2 γ λ 1 Δ u 2 + 4 ( β + 1 ) 2 c 2 C 1 2 β γ λ 1 β / 2 Δ u 2 β ) A - 1 / 2 w ( t ) 2 Mathematical equation(52)

Proposition 2   Suppose 5/2β4,u0V,fH.Mathematical equation Then the global attractor ÃHMathematical equation has the finite fractal dimension in HMathematical equation, with

d i m H ( A ̃ H ) d i m F ( A ̃ H ) ( 6 b 2 C 1 2 ρ 4 2 a C ̃ γ λ 1 + 6 ( β + 1 ) 2 c 2 C 1 2 β ρ 4 2 β a C ̃ γ λ 1 β / 2 ) 3 2 Mathematical equation(53)

where C̃Mathematical equation is defined in (4), b>0,c>0,ρ4>0Mathematical equation is given in Lemma 6 and C1>0Mathematical equation is given in (6) which only dependents on ΩMathematical equation.

Proof   Let w1,0,,wn,0,Mathematical equation for some n1Mathematical equation, be an initial orthogonal set of infinitesimal displacements. The volume of the parallelopiped spanned by w1,0,,wn,0,Mathematical equation is given by Vn(0)=|w1,0wn,0|,Mathematical equation where Mathematical equation denotes the exterior product. The evolution of such displacements satisfies the following evolution equation:

{ d d t w i ( t ) = L ̃ ( t , u ˜ ) w i ( t ) w i ( 0 ) = w i , 0                    Mathematical equation(54)

for all i=1,,nMathematical equation. Using Lemma 3.5 in Ref.[26], we know that the volume elements Vn(t)=|w1(t)wn(t)|Mathematical equation satisfy

V n ( t ) = V n ( 0 ) e x p [ 0 t T r ( P n ( s ) L ̃ ( s , u ˜ ) ) d s ] Mathematical equation(55)

where Pn(s)Mathematical equation is the orthogonal projection onto the linear span of {w1(t),,wn(t)}Mathematical equation in HMathematical equation. And we also know that Tr(Pn(s)L̃(s,u˜))=k=1n(L̃(s,u˜)φk(s),φk(s)),Mathematical equation with n1Mathematical equation and {φ1(s),,φn(s)}Mathematical equation an orthonormal set spanning Pn(s)HMathematical equation. Then, we define

[ P n L ̃ ( u ˜ ) ] = l i m s u p T 1 T 0 T T r ( P n ( t ) L ̃ ( t , u ˜ ) ) d t Mathematical equation(56)

From (56), we have

V n ( t ) = V n ( 0 ) e x p { t s u p u ̃ A ˜ H s u p P n ( 0 ) [ P n L ̃ ( u ˜ ) ] } Mathematical equation(57)

for all t0Mathematical equation, where the supremum over Pn(0)Mathematical equation is a supremum over all choices of initial nMathematical equation orthogonal set of infinitesimal displacements that have taken around u˜Mathematical equation. Now let us prove that the volume element Vn(t)Mathematical equation decays exponentially with time, whenever nMathematical equationN, with N>Mathematical equation0 to be determined later.

Let us use Proposition 1 to estimate 1T0TTr(Pn(t)L̃(t,u˜))dt.Mathematical equation

1 T 0 T T r ( P n ( t ) L ̃ ( t , u ˜ ) ) d t = 1 T 0 T k = 1 n ( L ̃ ( t , u ˜ ) φ k ( t ) , φ k ( t ) ) d t 1 T 0 T k = 1 n - 2 a φ k ( t ) 2 d t + 1 T 0 T ( 4 b 2 C 1 2 ρ 4 2 γ λ 1 + 4 ( β + 1 ) 2 c 2 C 1 2 β ρ 4 2 β γ λ 1 β / 2 ) k = 1 n A - 1 / 2 φ k ( t ) 2 d t - 2 a n + h T 0 T k = 1 n φ k ( t ) 2 λ k d t   - 2 a n + h k = 1 n 1 C ˜ k 2 3         ( t h e   f a c t   λ k C ˜ k 2 3   i s   u s e d ) - 2 a n + 3 n 1 3 h C ˜           ( s e r i e s   i n e q u a l i t y   ( 8 )   i s   u s e d ) Mathematical equation(58)

where h=4b2C12ρ42γλ1+4(β+1)2c2C12βρ42βγλ1β/2Mathematical equation. So we obtain [PnL̃(u˜)]-2an+3n13hC˜.Mathematical equation

We need the right hand side of the above inequality must be negative, therefore we require n(3h2aC˜)32Mathematical equation , where h=4b2C12ρ42γλ1+4(β+1)2c2C12βρ42βγλ1β/2Mathematical equation and C˜Mathematical equation is defined in (4), which completes the proof.

Since A˜HMathematical equation has finite fractal dimension in HMathematical equation with the bound (53), we can easily prove the following Theorem by using (43).

Theorem 4   Suppose 5/2β4,u0V, fHMathematical equation. Then the global attractor AVMathematical equation obtained in Theorem 2 has finite Hausdorff and fractal dimensions, which can be estimated by

d i m H ( A V ) d i m F ( A V ) ( 6 b 2 C 1 2 ρ 4 2 a C ˜ γ λ 1 + 6 ( β + 1 ) 2 c 2 C 1 2 β ρ 4 2 β a C ˜ γ λ 1 β / 2 ) 3 2 , Mathematical equation

where C˜Mathematical equation is defined in (4), b>0,c>0,ρ4>0Mathematical equation are given in Lemma 6 and C1>0Mathematical equation is given in (6) which only depends on ΩMathematical equation.

3 Conclusion

In this paper, we investigate the dimension of global attractor in (H01(Ω))3Mathematical equation of strong solution for a 3D Brinkman-Forchheimer equation. By setting u˜=A1/2uMathematical equation, we rewrite system (3) as (40). And by proving (40) has a bound for the fractal dimension and Hausdorff dimension of A˜HMathematical equation in HMathematical equation, we obtain the system (3) has a bound for the fractal dimension and Hausdorff dimension of A˜VMathematical equation in VMathematical equation.

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