Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 28, Number 5, October 2023
Page(s) 399 - 410
DOI https://doi.org/10.1051/wujns/2023285399
Published online 10 November 2023

© Wuhan University 2023

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

Stochastic differential equations (SDEs) have been utilized to model various phenomena, such as asset price, SIS epidemic and population dynamics. Analytical solutions can rarely be found for nonlinear SDEs, whereas numerical solutions may be helpful. For SDEs with super-linearly growing coefficients, implicit Euler-Maruyama (EM) methods[1-3] have been proposed. In general, the implicit schemes need to solve a nonlinear system at each iteration, and hence requires more computational efforts.

On the contrary, the explicit methods own simple algebraic structure, cheap computational costs and acceptable convergence rate. The explicit EM approximate solution to nonlinear SDEs may diverge to infinity in finite time[4]. Therefore some modified EM methods have been proposed to numerically solve nonlinear SDEs, such as the stopped EM method[5], the tamed EM method[6] and the tamed Milstein method[7]. Especially, Mao[8,9] invented the truncated Euler-Maruyama scheme (TEM for short) with strong convergence theory, which stimulates many researchers' interest. There are extensive literatures with the TEM[10-14]. These research results are important contributions to numerical approximation theory of SDEs. However, we find that the results normally require the drift and diffusion coefficients satisfy the one-sided linear growth condition:

x , f ( x ) + p - 1 2 | g ( x ) | 2 K ( 1 + | x | 2 ) , x R n ¯ Mathematical equation(1)

the one-sided Lipschitz condition:

( x - y ) ( f ( x ) - f ( y ) ) L 1 ( x - y ) 2 Mathematical equation(2)

and the polynomial growth condition:

| f ( x ) - f ( y ) | 2 H ( 1 + | x | γ + | y | γ ) | x - y | 2 Mathematical equation(3)

The one-sided Lipschitz condition (2) and polynomial growth condition (3) are frequently assumed in order to establish the strong convergence rates of the implicit EM schemes for highly nonlinear SDEs[15,16]. In this paper, we shall remove conditions (2) and (3). We only need that the drift coefficient fMathematical equation satisfies the one-sided polynomial growth condition to guarantee the strong convergence rates of the underlying numerical solutions, which is much less restrictive than (2) and (3).

The main purpose of this paper is to establish new criteria on the strong convergence rates of the truncated approximation when the drift coefficient is one-sided polynomially growing whereas the diffusion coefficient is linearly growing, polynomial growing or Hölder continuous. For SDEs with one-sided polynomial growing drift and diffusion coefficients, the strong convergence rate is one half.

The next section introduces basic notations and the truncated Euler-Maruyama method. After that the strong convergence rate for SDEs with superlinearly growing drift and diffusion coefficients at time TMathematical equation was established. Section 2 proves the path-dependent strong convergence rate for SDEs with super-linearly growing drift and linearly growing diffusion coefficients over a finite time interval [0,T]Mathematical equation.

1 SDEs with Polynomial Growing Coefficients

Throughout this paper, unless otherwise specified, let |x|Mathematical equation be the Euclidean norm in xRn¯Mathematical equation. If AMathematical equation is a vector or matrix, its transpose is denoted by ATMathematical equation. If AMathematical equation is a matrix, its trace norm is denoted by |A|=trace (ATA)Mathematical equation, while its operator norm is denoted by A=sup{|Ax|:|x|=1}Mathematical equation. Let (Ω,,{t}t0,P)Mathematical equation be a complete probability space with a filtration {t}t0Mathematical equation, satisfying the usual conditions (i.e., it is increasing and right continuous and 0Mathematical equation contains all PMathematical equation-null sets). Let R+=[0,+),Mathematical equationab=max{a,b}Mathematical equation and ab=min{a,b}Mathematical equation. Let NMathematical equation be the set of all natural integers.

Consider an n¯Mathematical equation-dimensional stochastic differential system

d x ( t ) = f ( x ( t ) ) d t + g ( x ( t ) ) d w ( t ) Mathematical equation(4)

on t0Mathematical equation with initial data x0Rn¯Mathematical equation, and f :Rn¯Rn¯,g :Rn¯Rn¯×m¯Mathematical equation are Borel-measurable.

Assumption 1 (local Lipschitz condition) For each real number R1Mathematical equation, there is a positive constant kRMathematical equation such that

| f ( x 1 ) - f ( x 2 ) | | g ( x 1 ) - g ( x 2 ) | k R | x 1 - x 2 | Mathematical equation(5)

for xiRn¯Mathematical equation with |xi|R, i=1,2Mathematical equation.

Assumption 2 (one-sided polynomial growth condition) There exist nN, p2Mathematical equation, and positive constants a0,a,α,ai,αi,i=1,2,,nMathematical equation such that

x , f ( x ) + p - 1 2 | g ( x ) | 2 a 0 | x | 2 + i = 1 n a i | x | α i + 1 - a | x | α + 2 Mathematical equation(6)

for xRn¯Mathematical equation.

In this paper, we only require that the drift coefficient fMathematical equation satisfies Assumptions 1 and 2. We remove the one-sided Lipschitz condition (2) in Refs. [8,9] and the polynomial growth condition (3) in Ref. [17]. The latter is a vital assumption in establishing the strong convergence rate of the implicit EM scheme for highly nonlinear SDEs.

It is easy to prove that there is a unique global solution to Eq. (4) under Assumptions 1 and 2 with α2αiMathematical equation and a>i=1naiMathematical equation (see Ref. [17]). Let R>0Mathematical equation be an arbitrary number and x(t)Mathematical equation be the solution of Eq. (4), define

σ R = i n f { t 0 : | x ( t ) | R } Mathematical equation(7)

It is easy to show that there exists a positive constant cpMathematical equation such that

E | x ( t ) | p c p ,   P { σ R T } c p R p , Mathematical equation

where cpMathematical equation represents a generic positive constant, whose value varies with each appearance throughout the paper.

The following result plays a key role in subsequent sections (For proof, please refer to page 425 of Ref. [3]).

Lemma 1[3]Define a polynomial function φ(x)Mathematical equation of a nonnegative real argument xMathematical equation by φ(x)=axp+bxγ+p-l=1nclxγl+p,Mathematical equation where a,b,p,γ,cl,γl(1ln)Mathematical equation are nonnegative real numbers satisfying 0<γ1γ2γnγMathematical equation and bc=l=1nclMathematical equation. If a>p0cMathematical equation, then φ(x)(a-p0c)xp,Mathematical equation where the nonnegative constant p0Mathematical equation is

p 0 = { 0 , γ 1 = γ ( γ - γ 1 ) ( γ 1 γ 1 γ γ ) 1 γ - γ l , γ 1 γ Mathematical equation(8)

We shall now introduce the discrete truncated EM scheme. Choose a strictly increasing continuous function μ:R+R+Mathematical equation such that μ(u)Mathematical equation as uMathematical equation and

s u p | x | u | f ( x ) | | g ( x ) | μ ( u ) , u 1 Mathematical equation(9)

Denote by μ-1Mathematical equation the inverse function of μMathematical equation, and μ-1:[μ(0),+)R+Mathematical equation. Choose a number Δ*(0,1)Mathematical equation, a strictly decreasing function h:(0,Δ*)(0,+)Mathematical equation such that

h ( Δ * ) > μ ( 1 ) , l i m Δ 0 h ( Δ ) = , Δ 1 4 h ( Δ ) 1 , Δ ( 0 , Δ * ) Mathematical equation(10)

Let the step size Δ(0,Δ*)Mathematical equation be a fraction of TMathematical equation, namely Δ=T/MMathematical equation for some integer MMathematical equation. Define a mapping π:Rn¯{xRn¯:|x|μ-1(h(Δ))}Mathematical equation by π(x)=(|x|μ-1(h(Δ)))x|x|Mathematical equation, where x/|x|=0Mathematical equation when x=0Mathematical equation. Define the truncated functions

f Δ ( x ) = f ( π ( x ) ) , g Δ ( x ) = g ( π ( x ) ) Mathematical equation

It is easy to see that |fΔ(x)||gΔ(x)|μ(μ-1(h(Δ)))=h(Δ),xRn¯Mathematical equation.

Obviously, the truncated functions fΔMathematical equation and gΔMathematical equation are bounded, although fMathematical equation and gMathematical equation may not be.

Denote tk=kΔMathematical equation. The discrete-time truncated EM numerical solution XΔ(tk)(x(tk))Mathematical equation is defined by

X Δ ( t k + 1 ) = X Δ ( t k ) + f Δ ( X Δ ( t k ) ) Δ + g Δ ( X Δ ( t k ) ) Δ w t k , k = 0,1 , 2 , Mathematical equation(11)

where Δwtk=w(tk+1)-w(tk)Mathematical equation. The increments ΔwtkMathematical equation are independent N(0,Δ)Mathematical equation-distributed Gaussian random variables tkMathematical equation-measurable at the mesh points tkMathematical equation. Define two continuous-time truncated EM solutions as

x ¯ Δ ( t ) = i = 1 X Δ ( t k ) I [ t k , t k + 1 ) ( t ) , t 0 Mathematical equation(12)

x Δ ( t ) = x 0 + 0 t f Δ ( x ¯ Δ ( s ) ) d s + 0 t g Δ ( x ¯ Δ ( s ) ) d w ( s ) , t 0 Mathematical equation(13)

where I[tk,tk+1)(t)={1,t[tk,tk+1)0, otherwise Mathematical equation is the indicator function. Clearly, XΔ(tk)=x¯Δ(tk)=Mathematical equationxΔ(tk)Mathematical equation for all k0Mathematical equation.

The truncated functions preserve the Khasminskii-type condition nicely[18]. They cannot preserve Assumption 2 exactly but piecewisely, as described in the following lemma.

Lemma 2   Let Assumption 2 hold. Denotea˜=(i=1ai+a0)/2Mathematical equation, then for everyΔ(0,Δ*)Mathematical equationand anyxRn¯Mathematical equation, wehave

x T f Δ ( x ) + p - 1 2 | g Δ ( x ) | 2 { a 0 | x | 2 + i = 1 n a i | x | α i + 1 - a | x | α + 2 , | x | μ - 1 ( h ( Δ ) ) 1 2 a 0 | π ( x ) | 4 + a ˜ | x | 2 + i = 1 n a i 2 | π ( x ) | 2 α i + 2 - a | π ( x ) | α + 2 , | x | > μ - 1 ( h ( Δ ) ) Mathematical equation(14)

Proof   Since μ()Mathematical equation is increasing, h()Mathematical equation is decreasing and h(Δ*)>μ(1)Mathematical equation, we have μ-1(h(Δ*))>1Mathematical equation and μ-1(h(Δ))>1Mathematical equation for Δ(0,Δ*)Mathematical equation. For any xRn¯Mathematical equation with |x|μ-1(h(Δ))Mathematical equation, it is clear that π(x)=xMathematical equation and hence

x T f Δ ( x ) + p - 1 2 | g Δ ( x ) | 2 = x T f ( x ) + p - 1 2 | g ( x ) | 2 a 0 | x | 2 + i = 1 n a i | x | α i + 1 - a | x | α + 2 Mathematical equation(15)

For any xRn¯Mathematical equation with |x|>μ-1(h(Δ))Mathematical equation, we have x=|x|π(x)μ-1(h(Δ)),|π(x)|<|x|Mathematical equation and hence

x T f Δ ( x ) + p - 1 2 | g Δ ( x ) | 2 = x T f ( π ( x ) ) + p - 1 2 | g ( π ( x ) ) | 2 = π ( x ) T f ( π ( x ) ) + p - 1 2 | g ( π ( x ) ) | 2 + ( | x | μ - 1 ( h ( Δ ) ) - 1 ) π ( x ) T f ( π ( x ) ) . Mathematical equation

By Assumption 2 and the inequality aba2+b22Mathematical equation, we may compute

x T f Δ ( x ) + p - 1 2 | g Δ ( x ) | 2 a 0 | π ( x ) | 2 + i = 1 n a i | π ( x ) | α i + 1 - a | π ( x ) | α + 2 + ( | x | μ - 1 ( h ( Δ ) ) - 1 ) ( i = 1 n a i | π ( x ) | α i + 1 + a 0 | π ( x ) | 2 ) = - a | π ( x ) | α + 2 + | x | μ - 1 ( h ( Δ ) ) ( i = 1 n a i | π ( x ) | α i + 1 + a 0 | π ( x ) | 2 ) - a | π ( x ) | α + 2 + i = 1 n a i 2 ( | π ( x ) | 2 α i + 2 + | x | 2 ) + a 0 2 ( | π ( x ) | 4 + | x | 2 ) . Mathematical equation

This completes the proof.

Lemma 3   FixT>0Mathematical equation. Let Assumptions 1 and 2 hold. Then for anyΔ(0,Δ*)Mathematical equationandp>0Mathematical equation, there exists cpMathematical equation, a genericpositive constant dependent onT,p,kRMathematical equationbut independent ofΔMathematical equation, such that

E | x Δ ( t ) - x ¯ Δ ( t ) | p c p Δ p 2 ( h ( Δ ) ) p , 0 t T . Mathematical equation

Proof   For t[0,T]Mathematical equation, there exists a unique nonnegative integer kMathematical equation such that t[tk,tk+1)Mathematical equation. Since |fΔ(x¯Δ(s))|Mathematical equation|gΔ(x¯Δ(s))|h(Δ)Mathematical equation, we have

E | x Δ ( t ) - x ¯ Δ ( t ) | p E | t k t f Δ ( x ¯ Δ ( s ) ) d s + t k t g Δ ( x ¯ Δ ( s ) ) d w ( s ) | p c p ( Δ p - 1 E t k t | f Δ ( x ¯ Δ ( s ) ) | p d s + Δ p / 2 - 1 t k t | g Δ ( x ¯ Δ ( s ) ) | p d s ) c p Δ p 2 ( h ( Δ ) ) p Mathematical equation

by Eqs. (12) and (13) and the Hölder inequality. For 0<p¯<2Mathematical equation, the Lyapunov inequality gives

E | x ( t ) - x ¯ Δ ( t ) | p ¯ ( E | x ( t ) - x ¯ Δ ( t ) | p ) p ¯ p ( c p Δ p 2 ( h ( Δ ) ) p ) p ¯ p = c p Δ p ¯ 2 ( h ( Δ ) ) p ¯ . Mathematical equation

This proof is completed.

Let R>0Mathematical equation be an arbitrary number and xΔ(t)Mathematical equation be the continuous-time truncated EM solution defined by Eq. (13), define

ρ R = i n f { t 0 : | x Δ ( t ) | R } Mathematical equation(16)

Lemma 4   Let Assumption 2 hold, α2αi2 (i=1,,n)Mathematical equationanda>i=1nai+a0/2Mathematical equation. Then forΔ(0,Δ*)Mathematical equationandp>0Mathematical equation, there exists a positive constantcpMathematical equationsuch that

s u p 0 < Δ < Δ * s u p 0 t T E | x Δ ( t ) | p c p , T > 0 . Mathematical equation

Moreover,

P { ρ R T } c p R p . Mathematical equation

Proof   We prove the results are true for p2Mathematical equation first. For any s>0Mathematical equation, there exists a unique nonnegative integer kMathematical equation such that s[tk,tk+1)Mathematical equation. For sρRMathematical equation, we see that |xΔ(s)|RMathematical equation by definition of ρRMathematical equation; for sρRMathematical equation, we deduce that |x¯Δ(s)|RMathematical equation as well due to x¯Δ(s)x¯Δ(tk)=xΔ(tk)Mathematical equation for s[tk,tk+1)Mathematical equation. The Itô formula then gives

E | x Δ ( t ρ R ) | p E | x 0 | p + E 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) T f Δ ( x ¯ Δ ( s ) ) + p - 1 2 | g Δ ( x ¯ Δ ( s ) ) | 2 ) d s   E | x 0 | 2 + 0 t ρ R p | x Δ ( s ) | p - 2 ( x ¯ Δ ( s ) T f Δ ( x ¯ Δ ( s ) ) + p - 1 2 | g Δ ( x ¯ Δ ( s ) ) | 2 ) d s + 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) - x ¯ Δ ( s ) ) T f Δ ( x ¯ Δ ( s ) ) d s . Mathematical equation

Depending on whether |x¯Δ(s)|μ-1(h(Δ))Mathematical equation, the rest of the proof falls into two cases:

Case 1: For any x¯Δ(s)Rn¯Mathematical equation with |x¯Δ(s)|μ-1(h(Δ))Mathematical equation, by Lemma 2, we have

E | x Δ ( t ρ R ) | p E | x 0 | p + E 0 t ρ R p | x Δ ( s ) | p - 2 ( a 0 | x ¯ Δ ( s ) | 2 + i = 1 n a i | x ¯ Δ ( s ) | α i + 1 - a | x ¯ Δ ( s ) | α + 2 ) d s + E 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) - x ¯ Δ ( s ) ) T f Δ ( x ¯ Δ ( s ) ) d s E | x 0 | p + 2 p a 0 E 0 t ρ R | x Δ ( s ) | p - 2 | x ¯ Δ ( s ) | 2 d s + E 0 t ρ R p | x Δ ( s ) | p - 2 ( - a 0 | x ¯ Δ ( s ) | 2 + i = 1 n a i | x ¯ Δ ( s ) | α i + 1 - a | x ¯ Δ ( s ) | α + 2 ) d s + E 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) - x ¯ Δ ( s ) ) T f Δ ( x ¯ Δ ( s ) ) d s . Mathematical equation

According to Lemma 1,α2αiMathematical equation and a>i=1naiMathematical equation, there is a constant c0Mathematical equation such that

a 0 | x ¯ Δ ( s ) | 2 - i = 1 n a i | x ¯ Δ ( s ) | α i + 1 + a | x ¯ Δ ( s ) | α + 2 c 0 | x ¯ Δ ( s ) | 2 . Mathematical equation

This, together with the Young's inequality ap-2bp-2pap+2pbp/2Mathematical equation for a,b0Mathematical equation, implies

E | x Δ ( t ρ R ) | p E | x 0 | p + 2 a 0 E 0 t ρ R [ ( p - 2 ) | x Δ ( s ) | p + 2 | x ¯ Δ ( s ) | p ] d s + ( p - 2 ) E 0 t ρ R | x Δ ( s ) | p d s + 2 E 0 t ρ R | x Δ ( s ) - x ¯ Δ ( s ) | p / 2 | f Δ ( x ¯ Δ ( s ) ) | p / 2 d s E | x 0 | 2 + ( a 0 + 1 ) ( p - 2 ) E 0 t ρ R | x Δ ( s ) | p d s + 4 a 0 E 0 t ρ R | x ¯ Δ ( s ) | p d s   + 2 h ( Δ ) p / 2 E 0 t ρ R | x Δ ( s ) - x ¯ Δ ( s ) | p / 2 d s . Mathematical equation

By the Lyapunov inequality and Lemma 3, the above estimate becomes

E 0 t ρ R | x Δ ( s ) - x ¯ Δ ( s ) | p / 2 d s 0 t ( E | x Δ ( s ρ R ) - x ¯ Δ ( s ρ R ) | p ) 1 / 2 d s c p h ( Δ ) p / 2 Δ p / 4 . Mathematical equation

Noticing that sup0tTE|x¯Δ(s)|psup0tTE|xΔ(s)|pMathematical equation,

s u p 0 t T E | x Δ ( t ρ R ) | p E | x 0 | 2 + [ 2 ( a 0 + 1 ) p - 2 ] 0 T s u p 0 v s E | x Δ ( v ρ R ) | p d s + c p h ( Δ ) p Δ p / 4 . Mathematical equation

Using the Gronwall inequality , let RMathematical equation, the Fatou lemma gives

l i m 0 Δ Δ * s u p 0 t T E | x Δ ( t ) | p ( E | x 0 | 2 + c p h ( Δ ) p Δ p / 4 ) e ( 2 ( a 0 + 1 ) p - 2 ) T c p . Mathematical equation

Case 2: For any x¯Δ(s)Rn¯Mathematical equation with |x¯Δ(s)|>μ-1(h(Δ))Mathematical equation, we obtain by Lemma 2 :

E | x Δ ( t ρ R ) | p E | x 0 | p + p a ˜ E 0 t ρ R | x Δ ( s ) | p - 2 | x ¯ Δ ( s ) | 2 d s + E 0 t ρ R p | x Δ ( s ) | p - 2 [ a 0 2 | π ( x ¯ Δ ( s ) ) | 4 - a | π ( x ¯ Δ ( s ) ) | α + 2 + i = 1 n a i 2 | π ( x ¯ Δ ( s ) ) | 2 α i + 2 ] d s + E 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) - x ¯ Δ ( s ) ) T f Δ ( x ¯ Δ ( s ) ) d s . Mathematical equation

Note that |π(x¯Δ(s))|2|x¯Δ(s)|Mathematical equation, then

E | x Δ ( t ρ R ) | p E | x 0 | p + E 0 t ρ R p | x Δ ( s ) | p - 2 ( x Δ ( s ) - x ¯ Δ ( s ) ) T f Δ ( x ¯ Δ ( s ) ) d s - a 0 2 | π ( x ¯ Δ ( s ) ) | 4   - E 0 t ρ R p | x Δ ( s ) | p - 2 [ a 0 | π ( x ¯ Δ ( s ) ) | 2 + a | π ( x ¯ Δ ( s ) ) | α + 2 - i = 1 n a i 2 | π ( x ¯ Δ ( s ) ) | 2 α i + 2 ] d s + p a 0 E 0 t ρ R | x Δ ( s ) | p - 2 | π ( x ¯ Δ ( s ) ) | 2 d s + p a ˜ E 0 t ρ R | x Δ ( s ) | p - 2 | x ¯ Δ ( s ) | 2 d s . Mathematical equation

Recalling that α2αi2Mathematical equation and a>i=1nai+a0/2Mathematical equation, by Lemma 1, there is a constant c0Mathematical equation such that

a 0 | π ( x ¯ Δ ( s ) ) | 2 + a | π ( x ¯ Δ ( s ) ) | α + 2 - a 0 2 | π ( x ¯ Δ ( s ) ) | 4 - i = 1 n a i 2 | π ( x ¯ Δ ( s ) ) | 2 α i + 2 c 0 | π ( x ¯ Δ ( s ) ) | 2 . Mathematical equation

Therefore,

E | x Δ ( t ρ R ) | p = E | x 0 | p + 2 ( a 0 + a ˜ ) E 0 t ρ R ( | x ¯ Δ ( s ) | p + p - 2 2 | x Δ ( s ) | p ) d s + ( p - 2 ) E 0 t ρ R | x Δ ( s ) | p d s + c p h ( Δ ) p Δ p / 4 . Mathematical equation

Noticing that sup0tTE|x¯Δ(s)|psup0tTE|xΔ(s)|pMathematical equation, we obtain

s u p 0 t T E | x Δ ( t ρ R ) | p E | x 0 | p + c p 0 T [ s u p 0 u s E | x Δ ( u ρ R ) | p ] d s + c p h ( Δ ) p Δ p / 4 Mathematical equation

The Gronwall inequality and Fatou lemma imply

l i m 0 Δ Δ * s u p 0 t T E | x Δ ( t ) | 2 ( E | x 0 | 2 + c p h ( Δ ) p Δ p / 4 ) e c p T c p Mathematical equation

For 0<p¯<2Mathematical equation, the Lyapunov inequality gives the desired result. The second part of this lemma easily follows.

Lemma 5   Let Assumptions 1 and 2 hold,p>0,α2αi(i=1,,n)Mathematical equationanda>i=1naiMathematical equation. Then for any real numberR<μ-1(h(Δ))Mathematical equationandΔ(0,Δ*)Mathematical equation, there exists a positive constantcpMathematical equationsuch that

E | x Δ ( t θ R ) - x ( t θ R ) | p c p Δ p 2 h ( Δ ) p , 0 t T , Mathematical equation

where θR=ρRσRMathematical equation.

Proof   Denote e(t)=x(t)-xΔ(t)Mathematical equation. Assume p2Mathematical equation first. For given Δ(0,Δ*)Mathematical equation and any real number R<μ-1(h(Δ)),0stθRMathematical equation implies that |x¯Δ(s)||x(s)||xΔ(s)|R<μ-1(h(Δ)))Mathematical equation and

f Δ ( x ¯ Δ ( s ) ) = f ( x ¯ Δ ( s ) ) , g Δ ( x ¯ Δ ( s ) ) = g ( x ¯ Δ ( s ) ) . Mathematical equation

The Itô formula and Assumption 1 give

E | e ( t θ R ) | p E 0 t θ R p | e ( s ) | p - 2 [ e ( s ) T ( f ( x ( s ) ) - f ( x ¯ Δ ( s ) ) + p - 1 2 | g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) | 2 ] d s k R E 0 t θ R ( p | e ( s ) | p - 1 | x ( s ) - x ¯ Δ ( s ) | + p ( p - 1 ) 2 | e ( s ) | p - 2 | x ( s ) - x ¯ Δ ( s ) | 2 ) d s . Mathematical equation

The Young inequality implies

E | e ( t θ R ) | p c p E 0 t θ R ( | e ( s ) | p + | x Δ ( s ) - x ¯ Δ ( s ) | p ) d s   c p E 0 t θ R ( | e ( s ) | p + 2 p | x ( s ) - x Δ ( s ) | p + 2 p | x Δ ( s ) - x ¯ Δ ( s ) | p ) d s c p E 0 t | e ( s θ R ) | p d s + c p Δ p 2 h ( Δ ) p . Mathematical equation

Applying the Gronwall inequality to the above inequality, we achieve the desired result.

For 0<p¯<2Mathematical equation, picking a p>2Mathematical equation , we have

E | e ( t θ R ) | p ¯ [ E | e ( t θ R ) | p ] p ¯ p [ c p Δ p 2 h ( Δ ) p ] p ¯ p c p Δ p ¯ 2 h ( Δ ) p ¯ Mathematical equation

by the Lyapunov inequality.

Theorem 1   Let Assumptions 1 and 2 hold withα2αi2 (i=1,,n)Mathematical equationanda>i=1nai+a0/2Mathematical equation, Δ(0,Δ*)Mathematical equationwithh(Δ)μ((Δq2h(Δ)q)-1p-q),p>2Mathematical equation, andq[2,p)Mathematical equation. Then there exists a positive constant cpMathematical equationsuch that

E | x ( T ) - x Δ ( T ) | q c p Δ q / 2 h ( Δ ) q Mathematical equation

Proof   For p2Mathematical equation, by the Young's inequality xqyδqpxp+p-qpδqp-qyqp-q,x,y,δ>0Mathematical equation, we have

E | e ( T ) | q = E [ | e ( T ) | q I { θ R > T } ] + E [ | e ( T ) | q I { θ R T } ]   E [ | e ( T ) | q I { θ R > T } ] + q δ p E [ | e ( T ) | p ] + p - q p δ q p - q P ( θ R T ) Mathematical equation(17)

The Hölder inequality and Lemma 5 imply that

E [ | e Δ ( T ) | q I { θ R > T } ] = E [ | e Δ ( T θ R ) | q ] c p Δ q / 2 h ( Δ ) q Mathematical equation(18)

By Lemma 4, we have

E | e ( T ) | p E | x ( T ) | p + E | x Δ ( T ) | p c p , P { θ R T } P { σ R ρ R T } = P { σ R T } + P { ρ R T } c p R p . Mathematical equation

This, together with Lemma 5, yields E|eΔ(T)|pcpΔq/2h(Δ)q+cpqδp+cp(p-q)pRpδqp-q.Mathematical equation

Choose δ=Δq2h(Δ)q,R=(Δq2h(Δ)q)-1p-qMathematical equation, then E|x(T)-xΔ(T)|qcpΔq/2h(Δ)q.Mathematical equation

Example 1Consider a scalar SDEMathematical equation

d x ( t ) = ( - x ( t ) + x 2 ( t ) - 3 x 5 ( t ) ) d t + | x ( t ) | 3 / 2 d w ( t ) Mathematical equation(19)

Denote f(x)=-x+x2-3x5,g(x)=|x|3/2Mathematical equation. Then

x T f ( x ) + p - 1 2 | g ( x ) | 2 = - x 2 + x 3 - 3 x 6 + p - 1 2 | x | 3 . Mathematical equation

Now, we design functions μ(x),h(x)Mathematical equation and choose Δ*Mathematical equation so that condition (10) holds. First, it is easy to see that

s u p | x | u | f ( x ) | | g ( x ) | 5 u 5 , u 1 . Mathematical equation

Pick μ(u)=5u5,u1Mathematical equation, then μ-1(u)=(u5)15,u0Mathematical equation. Let h(Δ)=Δ-ϵ,ϵ[0,14],Δ>0Mathematical equation. Choose Δ*Mathematical equation satisfying Δ*5-ϵ-1Mathematical equation, then h(Δ*)μ(1),h(Δ)Δ14=Δ-ϵ+14<1Mathematical equation. It is easy to see that Assumption 2 holds, by Theorem 1, for any Δ(0,Δ*),E|x(T)-xΔ(T)|pcpΔp2h(Δ)pMathematical equation.

In Fig. 1, we plot the truncated EM approximation (11) of Eq. (19) with T=2Mathematical equation for initial value x(0)=1Mathematical equation. The figure illustrates that the numerical solution has convergence property.

Thumbnail: Fig. 1 Refer to the following caption and surrounding text. Fig. 1

Numerical simulation of the path x(t)Mathematical equation with T=2Mathematical equation for Eq. (19)

2 Strong Convergence Rate over a Finite Time Interval

Section 1 has established the strong convergence rate of the truncated EM solution at a fixed time T>0Mathematical equation. In this section, we consider the path-dependent strong convergence rate over a finite time interval [0,T]Mathematical equation, which requires a stronger assumption on the diffusion coefficient.

Assumption 3 (linear growth condition) For xRn¯Mathematical equation, there is a positive constant kgMathematical equation such that

| g ( x ) | 2 k g ( 1 + | x | 2 ) Mathematical equation(20)

Since gMathematical equation is linearly growing, it is not necessary to truncate it in this section. Consequently, gΔ()Mathematical equation shall be replaced by g()Mathematical equation in Equations (11) to (13), i.e., in the definition of the discrete-time and continuous-time truncated EM solutions.

Lemma 6   Let Assumptions 2 and 3 hold withα2αi(i=1,2,,n)Mathematical equationanda>i=1naiMathematical equation. Then for anyp2Mathematical equationandgivenT>0Mathematical equation, there exists a positive constantcpMathematical equationsuch that E[sup0sT|x(s)|p]cpMathematical equation.

Proof   The Itô formula gives

| x ( t ) | p   | x ( 0 ) | p + 0 t p ( a 0 | x ( s ) | p + i = 1 n a i | x ( s ) | α i + p - 1 - a | x ( s ) | α + p ) d s + 0 t p | x ( s ) | p - 2 x ( s ) T g ( x ( s ) ) d w ( s ) Mathematical equation(21)

By Lemma 1 , for any xRn¯Mathematical equation and α2αi(i=1,2,,n)Mathematical equation and a>i=1naiMathematical equation, there exists a constant c0Mathematical equation such that

a 0 | x ( s ) | p - i = 1 n a i | x ( s ) | α i + p - 1 + a | x ( s ) | α + p c 0 | x ( s ) | p . Mathematical equation

Inequality (21) then becomes

| x ( t ) | p | x 0 | p + 2 p a 0 0 t | x ( s ) | p d s + 0 t p | x ( s ) | p - 2 x ( s ) T g ( x ( s ) ) d w ( s ) . Mathematical equation

It follows that

E [ s u p 0 s T | x ( s σ R ) | p ] E | x 0 | p + 2 p a 0 0 T E [ s u p 0 u s | x ( u σ R ) | p ] d s   + E [ s u p 0 s T 0 t σ R p | x ( s ) | p - 2 x ( s ) T g ( x ( s ) ) d w ( s ) ] . Mathematical equation

By the Burkhölder-Davis-Gundy inequality, we obtain

E [ s u p 0 s t 0 t σ R p | x ( s ) | p - 2 x ( s ) T g ( x ( s ) ) d w ( s ) ] 4 2 p E [ 0 t σ R | x ( s ) | 2 p - 2 | g ( x ( s ) ) | 2 d s ] 1 / 2 1 2 E [ s u p 0 s T | x ( s σ R ) | p ] + 16 p 2 E [ 0 t σ R | x ( s ) | p - 2 | g ( x ( s ) ) | 2 d s ] . Mathematical equation

The above estimate, together with Assumption 3, yields

E [ s u p 0 s T | x ( s σ R ) | p ] c p + c p 0 T E [ s u p 0 u s | x ( u σ R ) | p ] d s Mathematical equation(22)

Finally, the desired result is obtained by the Gronwall inequality and the Fatou Lemma.

From the procedure of the proof in Lemma 6, we can see that Assumption 3 plays an important role in establishing the estimate (22), which makes the Gronwall inequality applicable to establish the moment boundedness.

Lemma 7   Let Assumption 3 hold. Then for p>0Mathematical equation and any Δ(0,Δ*)Mathematical equation with h(Δ)1Mathematical equation, there exists a positive constant cpMathematical equation such that E|xΔ(t)-x¯Δ(t)|pcpΔp2(h(Δ))p.Mathematical equation

Proof   We assume p2Mathematical equation first. For any t0Mathematical equation, there exists a unique nonnegative integer kMathematical equation such that t[tk,tk+1)Mathematical equation.

E | x ( t ρ R ) - x ¯ Δ ( t ρ R ) | p E | t k t ρ R f Δ ( x ¯ Δ ( s ) ) d s + t k t ρ R g ( x ¯ Δ ( s ) ) d w ( s ) | p 2 p - 1 ( Δ p - 1 E t k t ρ R | f Δ ( x ¯ Δ ( s ) ) | p d s + Δ p / 2 - 1 t k t ρ R | g ( x ¯ Δ ( s ) ) | p d s ) 2 p - 1 Δ p ( h ( Δ ) ) p + 2 p - 1 Δ p / 2 - 1 c p E t k t ρ R ( 1 + | x ¯ Δ ( s ) | p ) d s . Mathematical equation

By the linear growth condition (3) and the Doob martingale inequality, it is easy to see that

s u p 0 s t E | x ¯ Δ ( s ) | p s u p 0 s t E | x Δ ( s ) | p c p ( 1 + h ( Δ ) p ) . Mathematical equation

This, together with the Fatou Lemma, implies that

E | x ( t ) - x ¯ Δ ( t ) | p c p Δ p ( h ( Δ ) ) p + c p Δ p / 2 ( 1 + h ( Δ ) p ) c p Δ p 2 ( h ( Δ ) ) p . Mathematical equation

For 0<p¯<2Mathematical equation, the Lyapunov inequality gives

E | x ( t ) - x ¯ Δ ( t ) | p ¯ ( E | x ( t ) - x ¯ Δ ( t ) | p ) p ¯ p ( c p Δ p 2 ( h ( Δ ) ) p ) p ¯ p c p Δ p ¯ 2 ( h ( Δ ) ) p ¯ . Mathematical equation

The proof of the above lemma is different from that of Lemma 3 in that: |gΔ|(h(Δ))Mathematical equation is bounded in Lemma 3, but gMathematical equation here may be unbounded because we do not truncate gMathematical equation. Thus, the stopping time is necessary to apply the Doob martingale inequality.

Lemma 8   Let Assumptions 2 and 3 hold with α2αi(i=1,2,,n)Mathematical equationanda>i=1naiMathematical equation. Then for anyp>0Mathematical equation, there exists a positive constantcpMathematical equationsuch that E[sup0st|xΔ(s)|p]cp.Mathematical equation

Proof   Let us first assume p2Mathematical equation. Repeating the same process as in the proof of Lemma 4, we obtain |xΔ(t)|pcp+cp0t(|xΔ(s)|p+x¯Δ(s)|p)ds+2h(Δ)pΔp/4+0tp|xΔ(s)|p-1xΔ(s)Tg(x¯Δ(s))dw(s)Mathematical equation. Therefore,

E [ s u p 0 s t | x Δ ( s ρ R ) | p ] c p + c p E [ s u p 0 s t 0 s ρ R | x Δ ( v ) | p d v ] + 2 h ( Δ ) p Δ p / 4 + E [ s u p 0 s t 0 s ρ R p | x Δ ( v ) | p - 2 x Δ ( v ) T g ( x ¯ Δ ( v ) ) d w ( v ) ] . Mathematical equation

By the Burkhölder-Davis-Gundy inequality, the Hölder inequality and Lemma 7, we may compute

E [ s u p 0 s t | 0 s ρ R p | x Δ ( v ) | p - 2 x Δ ( v ) T g ( x ¯ Δ ( v ) ) d w ( v ) | ] c p E [ 0 t ρ R | x Δ ( v ) | 2 p - 2 | g ( x ¯ Δ ( v ) ) | 2 d s ] 1 / 2 1 2 E [ s u p 0 s t | x Δ ( s ρ R ) | p ] + c p E [ 0 t ρ R | x Δ ( s ) | p - 2 | g ( x ¯ Δ ( s ) ) | 2 d s ] 1 2 E [ s u p 0 s t | x Δ ( s ρ R ) | p ] + c p E 0 t ρ R ( 1 + | x Δ ( s ) | p + | x ¯ Δ ( s ) | p ) d s . Mathematical equation

Observing that E[sup0vs|x¯Δ(v)|p]E[sup0vs|xΔ(v)|p]Mathematical equation, we arrive at

E [ s u p 0 s t | x Δ ( s ρ R ) | p ] c p + c p h ( Δ ) p Δ p / 4 + c p 0 t E [ s u p 0 v s | x Δ ( v ρ R ) | p ] d s . Mathematical equation

The Gronwall inequality yields E[sup0st|xΔ(sρR)|p](cp+cph(Δ)pΔp/4)ecpTcpMathematical equation.

Let RMathematical equation, the Fatou lemma gives the desired result.

For 0<p¯<2Mathematical equation, the Lyapunov inequality shall ensure the result.

Lemma 9   Fix T>0Mathematical equation and p2Mathematical equation. Let Assumptions 1 to 3 hold with α2αi(i=1,2,,n)Mathematical equation and a>i=1naiMathematical equation. Then for |x0|<RMathematical equation and Δ(0,Δ*)Mathematical equation sufficiently small such that μ-1(h(Δ))>RMathematical equation, there exists a positive constant cpMathematical equation such that

E [ s u p 0 s T | x ( s θ R ) - x Δ ( s θ R ) | p ] c p Δ p 2 h ( Δ ) p . Mathematical equation

Proof   Denote e(s)=x(s)-xΔ(s)Mathematical equation. For stθRMathematical equation, we have |xΔ(s)||x¯Δ(s)||x(s)|RMathematical equationμ-1(h(Δ)),fΔ(x¯Δ(s))=f(x¯Δ(s))Mathematical equation, and gΔ(x¯Δ(s))=g(x¯Δ(s))Mathematical equation. The Itô formula gives

| e ( t θ R ) | 2 0 t θ R [ 2 e ( s ) T ( f ( x ( s ) ) - f ( x ¯ Δ ( s ) ) ) + | g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) | 2 ] d s + 0 t θ R 2 e ( s ) T ( g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) ) d w ( s ) J 1 + J 2 + J 3 . Mathematical equation

Here J1,J2Mathematical equation and J3Mathematical equation are the three integrals inside the expression. For J1Mathematical equation, we apply the Hölder's inequality to get

E [ s u p 0 s t | J 1 | p 2 ]   ( T p - 1 E 0 t θ R 2 p | e ( s ) | p | f ( x ( s ) ) - f ( x ¯ Δ ( s ) ) | p d s ) 1 / 2   2 - 2 3 - p 2 + 1 E [ s u p 0 s t | e ( s θ R ) | p ] + 3 p 2 - 1 T p - 1 2 p E 0 t θ R | f ( x ( s ) ) - f ( x ¯ Δ ( s ) ) | p d s . Mathematical equation

This, together with Assumption 1, implies

E [ s u p 0 s t | J 1 | p 2 ] 2 - 2 3 - p 2 + 1 E [ s u p 0 s t | e ( t θ R ) | p ] + 3 p 2 - 1 T p - 1 2 p k R p E 0 t θ R | x ( s ) - x ¯ Δ ( s ) | p d s . Mathematical equation

For J2Mathematical equation, we have

E [ s u p 0 s t | J 2 | p 2 ] k R p T p 2 - 1 E 0 t θ R | x ( s ) - x ¯ Δ ( s ) | p d s Mathematical equation

By the Burkhölder-Davis-Gundy and Hölder inequalities, we may compute

E [ s u p 0 s t | J 3 | p 2 ] E [ s u p 0 u t | 0 u θ R 2 e ( s ) T ( g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) ) d w ( s ) | p 2 ] c p E ( 0 t θ R 4 | e ( s ) | 2 | g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) | 2 d s ) p 4 c p E ( 0 t θ R T p / 2 - 1 2 p c p 2 | e ( s θ R ) | p | g ( x ( s ) ) - g ( x ¯ Δ ( s ) ) | p d s ) 1 2 2 - 2 3 - p 2 + 1 E [ s u p 0 s t | e ( s θ R ) | p ] + c p E 0 t θ R | x ( s ) - x ¯ Δ ( s ) | p d s . Mathematical equation

Summarizing up, we reach

E [ s u p 0 s t | e ( t θ R ) | p ]   1 2 E [ s u p 0 s t | e ( s θ R ) | p ] + c p E 0 t θ R | x ( s ) - x ¯ Δ ( s ) | p d s   c p E 0 t θ R | x ( s ) - x Δ ( s ) | p d s + c p E 0 t θ R | x Δ ( s ) - x ¯ Δ ( s ) | p d s Mathematical equation(23)

This, together with Lemma 7, implies

E [ s u p 0 s t | e ( s θ R ) | p ] c p 0 t E [ s u p 0 u s | e ( u θ R ) | p ] d s + c p Δ p / 2 h ( Δ ) p . Mathematical equation

The Gronwall inequality gives E[sup0st|e(sθR)|p]cpΔp/2h(Δ)p.Mathematical equation

The proof is completed.

Theorem 2   Let Assumptions 1 to 3 hold withα2αi2 (i=1,2,,n)Mathematical equationanda>i=1nai+a0/2Mathematical equation. Then forp>2Mathematical equationand given q[2,p)Mathematical equation, the truncated EM scheme described by Equation (13) has the property

E [ s u p 0 t T | x ( t ) - x Δ ( t ) | q ] c p Δ q / 2 h ( Δ ) q . Mathematical equation

Proof   Denote e(t)=x(t)-xΔ(t)Mathematical equation. For p>2Mathematical equation, the Young's inequality xqyδqpxp+p-qpδqp-qyqp-q,x,yMathematical equation, δ>0Mathematical equation, gives that

E [ s u p 0 t T | e ( t ) | q ] = E [ s u p 0 t T | e ( t ) | q I { θ R > T } ] + q δ p E [ s u p 0 t T | e ( t ) | p ] + p - q p δ q p - q P ( θ R T ) Mathematical equation(24)

The Hölder inequality and Lemma 9 imply that

E [ s u p 0 t T | e Δ ( t ) | q I { θ R > T } ] = E [ s u p 0 t T | e Δ ( t θ R ) | q ] c p Δ q / 2 h ( Δ ) q Mathematical equation(25)

By Lemmas 6 and 8, we obtain

E [ s u p 0 t T | e ( t ) | p ] E [ s u p 0 t T | x ( t ) | p ] + E [ s u p 0 t T | x Δ ( t ) | p ] c p . Mathematical equation

Applying Lemma 4, we get

P { θ R T } P { σ R ρ R T } = P { σ R T } + P { ρ R T } c p R p . Mathematical equation

Choosing δ=Δq2h(Δ)q,R=(Δq2h(Δ)q)-1p-qMathematical equation, we achieve E[sup0tT|x(t)-xΔ(t)|q]cpΔq/2h(Δ)q.Mathematical equation

The proof is completed.

Section 1 discusses the strong convergence rate at time TMathematical equation under a very general polynomial growth condition (6). Imposing the linear growth condition (20) on the diffusion coefficient, we obtain the strong convergence rate over [0,T]Mathematical equation after the pMathematical equation-th moment uniform boundedness is established.

Example 2 Consider a one-dimensional stochastic differential equation

d x ( t ) = ( x ( t ) + 2 x 2 ( t ) - 8 x 5 ( t ) ) d t + 0.5 x ( t ) d w ( t ) Mathematical equation(26)

It is easy to see that f(x)=x+2x2-8x5,g(x)=0.5xMathematical equation satisfy Assumptions 1, 2 and 3. Clearly, for u1,sup|x|u|f(x)||g(x)|11u5Mathematical equation. Define μ(u)=11u5Mathematical equation, then μ-1(u)=(u11)1/5Mathematical equation. Define h(λ)=λ-ε,ε[0,1/4]Mathematical equation, obviously, limΔ0h(Δ)=,Δ14h(Δ)<1Mathematical equation. Choose Δ*11-ε-1Mathematical equation, then h(Δ*)μ(1)Mathematical equation. By Theorem 2, for any Δ(0,Δ*),E|x(t)-xΔ(t)|pcpΔp2h(Δ)pMathematical equation.

In Fig. 2, we demonstrate that the numerical solution calculated by Eq. (26) converges strongly in the sense to the numerical exact solution with an order approximately equal to 0.5. We perform 2 000 sample paths and average over all the paths.

Thumbnail: Fig. 2 Refer to the following caption and surrounding text. Fig. 2

Convergence rate plot for Eq.(26)

3 Conclusion

In this paper, we discussed the strong convergence of the truncated EM methods for stochastic differential equations with super-linearly growing coefficients. The strong convergence rate at a single time TMathematical equation under a very general polynomial growth condition (6) is established in Theorem 1. Imposing the linearly growing condition (20) on the diffusion coefficient, the strong convergence rate over [0,T]Mathematical equation is established in Theorem 2. By using the Gronwall inequality, we proved the pMathematical equation-th moment uniform boundedness of both the exact and the approximate truncated EM solutions, which is the crucial result in examining the convergence rates.

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All Figures

Thumbnail: Fig. 1 Refer to the following caption and surrounding text. Fig. 1

Numerical simulation of the path x(t)Mathematical equation with T=2Mathematical equation for Eq. (19)

In the text
Thumbnail: Fig. 2 Refer to the following caption and surrounding text. Fig. 2

Convergence rate plot for Eq.(26)

In the text

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