Open Access
Issue
Wuhan Univ. J. Nat. Sci.
Volume 31, Number 3, June 2026
Page(s) 263 - 268
DOI https://doi.org/10.1051/wujns/2026313263
Published online 24 June 2026

© Wuhan University 2026

Licence Creative CommonsThis is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

0 Introduction

Let U(n,r)Mathematical equation be the q-Schur algebras over Q(v)Mathematical equation introduced by Dipper and James[1-2], who have showed that q-Schur algebras play an important role in the investigation of presentation theory of the finite general linear groups. The presentation of the q-Schur algebras could be referred to Refs. [3-4]. Gao and Liu[5] gave a set of primitives for the center of q-Schur algebras U(2,r)Mathematical equation. Du et al[6] studied the representation of little q-Schur algebra and gave a classification of finite representations of little q-Schur algebras under odd unit roots. And they pointed out that there is no nice and simple presentation for uk(n,r)Mathematical equation. Then, Bian and Liu[7] gave the presentation of little q-Schur algebras uk(2,r)Mathematical equation.

Little q-Schur superalgebras have been an important approach to studying q-Schur superalgebras. Turkey and Kujawa[8] gave a presentation of the Schur superalgebra and its quantum analogue. Chen[9] generalized algebra and quantum supergroup to the infinitesimal case, and finally obtained the infinitesimal theory of q-Schur superalgebras and the Beilinson-Lusztig-MacPherson (BLM) realization of integral quantum supergroups. Then, on one hand, we want to get deep understanding of the structure of the little q-Schur superalgebra uk(2|1,r)Mathematical equation by investigating the representation of uk(2|1,3)Mathematical equation in this paper; on the other hand, since little q-Schur superalgebras are closely related to q-Schur superalgebras, the research results on uk(2|1,3)Mathematical equation may be generalized to the study of more general little q-Schur superalgebras and even q-Schur superalgebras.

This paper studies the generators and relations for little q-Schur superalgebra uk(2|1,3)Mathematical equation.We briefly recall the definitions of q-Schur superalgebras Sv(m|n,r)Mathematical equation in Section 1. In Section 2, we prove that the set WkMathematical equation is the basis of uk(2|1,3)Mathematical equation and present the generators and relations of uk(2|1,3)Mathematical equation.

1 Preliminary

In the case of superalgebras, define a parity function, a mapping ^:{1,2,,m+n}2Mathematical equation, on the set {1,2,,m+n}Mathematical equation, for any a{1,2,,m+n}Mathematical equation, there is

a ^ = { 0 ¯ , 1 a m ; 1 ¯ , m + 1 a m + n . Mathematical equation

Note U(m|n)=Uv(glm|n)Mathematical equation is the quantum enveloping superalgebra of the Lie superalgebra glm|nMathematical equation[10]. Let g=glm|nMathematical equation. As a vector space, gMathematical equation is the set of m+nMathematical equation by m+nMathematical equation matrices. For 1i, jm+nMathematical equation, we set Ei,jMathematical equation to be the matrix unit with a 1 in iMathematical equation-th row and jMathematical equation-th column. Then the set of matrix units forms a homogeneous basis for gMathematical equation. The degree of Ei,jMathematical equation is i¯+j¯Mathematical equation. For any X,YU(m|n)Mathematical equation , X^Mathematical equation is the parity of XMathematical equation, and the square bracket [-,-]Mathematical equation is the super-Lie bracket, it means [X,Y]=XY-(-1)X^Y^YXMathematical equation. From now on, we mark νa=ν(-1)a^Mathematical equation for convenience.

Definition 1[8] The quantum supergroup U(m|n)=Uv(glm|n)Mathematical equation is generated by the elements

K a ± 1 ,   E h , h + 1 , E h + 1 , h ( 1 a m + n , 1 h m + n ) Mathematical equation

subject to the following relations:

(Q1) KaKb=KbKa,KaKa-1=1Mathematical equation;

(Q2) KaEh,h+1=vaδa,h-δa,h+1Eh,h+1Ka, KaEh+1,h=vaδa,h+1-δa,hEh+1,hKa;Mathematical equation

(Q3) [Ea,a+1,Eb,b+1]=δa,bKaKa+1-1-Ka-1Ka+1νa-νa-1Mathematical equation;

(Q4) [Ea,a+1,Eb,b+1]=0,[Ea+1,a,Eb+1,b]=0, for |a-b|>1;Mathematical equation

(Q5) if hmMathematical equation,

E h , h + 1 2 E h + 1 , h + 2 - ( v h + v h - 1 ) E h , h + 1 E h + 1 , h + 2 E h , h + 1 + E h - 1 , h E h , h + 1 2 = 0 ; Mathematical equation

E h , h + 1 2 E h - 1 , h - ( v h + v h - 1 ) E h , h + 1 E h - 1 , h E h , h + 1 + E h - 1 , h E h , h + 1 2 = 0 ; Mathematical equation

E h , h + 1 2 E h + 2 , h + 1 - ( v h + v h - 1 ) E h + 1 , h E h + 2 , h + 1 E h + 1 , h + E h + 2 , h + 1 E h + 1 , h 2 = 0 ; Mathematical equation

E h + 1 , h 2 E h , h - 1 - ( v h + v h - 1 ) E h + 1 , h E h , h - 1 E h + 1 , h + E h , h - 1 E h + 1 , h 2 = 0 ; Mathematical equation

(Q6) [Em,m+1,Em-1,m+2]=[Em+1,m,Em+2,m-1]=0.Mathematical equation

Let v be an indeterminate and A=Z[v,v-1]Mathematical equation , and Gauss symmetric polynomials will be introduced here . For any integers ab0Mathematical equation, let [a]=va-v-av-v-1Mathematical equation, [a]!=[1][2][a]Mathematical equation

and [ab]=s=1bva-s+1-v-a+s-1vs-v-s=[a]![b]![a-b]!Mathematical equation. For any integers 1a,bm+nMathematical equation and t,cZMathematical equation,t0Mathematical equation, we write Ka,b=KaKb-1, [Ka; ct]=s=1tKavac-s+1-Ka-1va-c+s-1vs-v-s, [Ka,b; ct]=s=1tKa,bvac-s+1-Ka,b-1va-c+s-1vas-va-s, E(m)=Em[m]!, F(m)=Fm[m]!,Mathematical equationand define the root vectors in U(m|n)Mathematical equation as follows. If j-i=1Mathematical equation, then set Ei,j=EiMathematical equation, Fj,i=FiMathematical equation. For j-i>1Mathematical equation, inductively set Ei,j=EiEi+1,j-v-1Ei+1,jEiMathematical equation, Fi,j=Fj,i+1Fi-vFiFj,i+1Mathematical equation. Besides for short, let [Kat]=[Ka;0t]Mathematical equation. Specializing vMathematical equation to εMathematical equation,kMathematical equation will be viewed as an AMathematical equation-module. When vMathematical equation is specialized to εMathematical equation, [c]Mathematical equation, [t]!Mathematical equation and [ct]Mathematical equation specialize to [c]εMathematical equation, [t]!εMathematical equation and [ct]εMathematical equation. And we define σi(A)=ai,i+1j<i(ai,j+aj,i)Mathematical equation.

Theorem 1[8] The q-Schur superalgebras Sv(m|n,r)Mathematical equation are generated by the elements

K a ± 1 ,   E h , h + 1 , E h + 1 , h ( 1 a m + n , 1 h m + n ) Mathematical equation

subject to the following relations:

(Q1)-(Q6) in Definition 1.

(Q7) K1K2KmKm+1-1Km+n-1=vr;Mathematical equation

(Q8) i=0r(Ka-vai)=0Mathematical equation, 1am+nMathematical equation.

By Theorem 1, we can obtain the algebraic full homomorphism ζr': U(m|n)Sv(m|n,r)Mathematical equation , such that there is ζr'(Ka±1)=Ka±1Mathematical equation, ζr'(Kh,h+1)=Kh,h+1Mathematical equation,ζr'(Kh+1,h)=Kh+1,hMathematical equation for 1am+nMathematical equation and 1hm+nMathematical equation.

Theorem 2[11] There is an algebra homomorphism ζr': U(m|n)Sv(m|n,r)Mathematical equation satisfying

ζ r ' ( K h , h + 1 ) = K h , h + 1 ( 0 , r ) ,   ζ r ' ( K h + 1 , h ) = K h + 1 , h ( 0 , r )   ,   ζ r ' ( K a ) = O ( e a , r ) , Mathematical equation

where ea=(0,,0,1,0,,0)m+nMathematical equation(1 in position a).

Lemma 1[9] 1) The set {kλ|λΛ(m|n,r)}Mathematical equation is the orthogonal idempotent set of Sv(m|n,r)Mathematical equation;

2) For any λΛ(m|n,r)Mathematical equation and 1am+nMathematical equation, kakλ=νaλakλMathematical equation.

Theorem 3[12] For all iMathematical equation, the set

W   : = { e c ( A + ) P λ ¯ f c ( A - ) | λ Λ ( m | n , r ) ,   λ i σ i ( A )   ,   A Γ ( m | n ) ± } Mathematical equationforms a QMathematical equation(q)-basis for q-Schur superalgebras Sv(m|n,r)Mathematical equation.

Let AΓ(m|n,r)±, λ¯Λ(m|n,r)¯Mathematical equation and jZm+nMathematical equation, define

P λ ¯ = { μ Λ ( m | n , r ) , μ ¯ = λ ¯ k μ , i f   λ ¯ Λ ( m | n , r ) ¯ ; 0 , o t h e r w i s e . Mathematical equation

Let ΓMathematical equation be the set of all A=(ai,j)Ξ˜(21)Mathematical equation such that ai,j<lMathematical equation for all ijMathematical equation and Γ±Mathematical equation be the set of all AΓMathematical equation whose diagonal entries are zero. According to Theorem 1, the following results can be obtained.

Lemma 2[8] For 1am+n,tZ , cZ , λMathematical equation

Λ ( m | n , r ) Mathematical equation and μΛ(m|n,r)Mathematical equation, we have

1) Ka±1Pλ=νa±λaPλ,[Ka;ct]Pλ=[λa+ct]PλMathematical equation;

2) KμPλ=λμPλMathematical equation, where λμ=a[λaμa]Mathematical equation;

3) Kμ=λΛ(m|n,r)λμPλMathematical equation.

Proposition 1[9] For AΓ±(m|n,r)Mathematical equation,

1) If there exist μΛ(m|n,r), μiσi(A+)Mathematical equation for all iMathematical equation and μ¯=λ¯Mathematical equation, then ec(A+)Pλ¯=Pλ¯'ec(A+)Mathematical equation, where λ'¯=λ-co(A+)+ro(A+)¯Mathematical equation; otherwise, ec(A+)Pλ¯=0Mathematical equation;

2) If there exist μΛ(m|n,r), μiσi(A-)Mathematical equation for all iMathematical equation and μ¯=λ¯Mathematical equation, then Pλ¯fc(A-)=fc(A-)Pλ¯'Mathematical equation, where λ'¯=λ+co(A+)-ro(A+)¯Mathematical equation; otherwise, Pλ¯fc(A-)=0Mathematical equation, where co(A+)Mathematical equation and ro(A+)Mathematical equation denote the column sum and row sum of the matrix A+Mathematical equation, respectively.

2 The Little q-Schur Superalgebra uk(2|1,3)Mathematical equation

Let uk̃Mathematical equation be the subalgebra of UkMathematical equation which is generated by all Kb±1Mathematical equation, Ea,a+1,Ea+1,a(1am+n,1bm+n)Mathematical equation.

According to (Q2), Kal-1Mathematical equation(1am+nMathematical equation) is the central element of UkMathematical equation (and therefore also uk̃Mathematical equation). Let Kal-1|1am+nMathematical equation be the ideal generated by Kal-1Mathematical equation(1am+nMathematical equation) in uk̃Mathematical equation and uk=uk̃/Kal-1|1am+nMathematical equation.

Thus quotient (super) algebra ukMathematical equation is called glm|nMathematical equation infinitesimal quantum supergroup. The image of uk̃Mathematical equation under ζr,kMathematical equation is denoted as uk(m|n,r)Mathematical equation. uk(m|n,r)Mathematical equation is called little q-Schur superalgebra related to mMathematical equation, nMathematical equation, rMathematical equation and lMathematical equation.

Theorem 4   The set

W k : = { e c ( A + ) P λ ¯ f c ( A - ) | λ Λ ( 2 | 1,3 ) ,   λ i σ i ( A ) , f o r   i = 1,2 , Mathematical equation

3, AΓ±(2|1)}Mathematical equation forms a basis for uk(2|1,3)Mathematical equation.

Proof   Fix AΓ(2|1)±Mathematical equation satisfying λiσi(A)Mathematical equation for all iMathematical equation. By the definition of Pλ¯Mathematical equation, we have

e c ( A + ) P λ ¯ f c ( A - ) = λ ¯ = μ ¯ , i , μ i σ i ( A ) e c ( A + ) k μ f c ( A - ) + λ ¯ = μ ' ¯ , i , μ i ' < σ i ( A ) e c ( A + ) k μ ' f c ( A - ) . Mathematical equation

In the q-Schur superalgebra Sv(2|1,3)Mathematical equation, for any ec(A+)kμ'fc(A-)Mathematical equation, if μi'<σi(A)Mathematical equation for some iMathematical equation, then it lies in the span of WMathematical equation in Theorem 3. Then we have

λ ¯ = μ ' ¯ , i , μ i ' < σ i ( A ) e c ( A + ) k μ ' f c ( A - ) = B Γ ± ( 2 | 1 ) σ i ( B ) < σ i ( A ) , μ i ' σ i ( B ) f B , A e c ( B + ) k μ ' f c ( B - ) ( f B , A k ) . Mathematical equation

By Theorem 3, the elements above are linearly independent, thus the set WkMathematical equation is linearly independent.

Inspired by Ref. [8], we have the following commutation formulas in the uk(2|1,3)Mathematical equation.

Proposition 2   For 1i2,MZ+,M1Mathematical equation,ei,i+1=eiMathematical equation, fi+1,i=fiMathematical equation, we define:

{ e 1,3 = e 1,2 e 2,3 - ε - 1 e 2,3 e 1,2 ; f 3,1 = f 3,2 f 2,1 - ε f 2,1 f 3,2 . Mathematical equation

(2.1a) e1,3e2,3=-ε-1e2,3e1,3Mathematical equation;

(2.1b) e1,3f3,1=-f3,1e1,3+λΛ(2|1,3)[λ1+λ3]Pλ¯Mathematical equation;

(2.1c) e1,2(M)f3,2=f3,2e1,2(M)Mathematical equation;

(2.1d) e1,3f3,2=-f3,2e1,3+λΛ(2|1,3)ελ2+λ3Pλ¯e1,2Mathematical equation;

(2.1e) e1,2(M)f3,1=f3,1e1,2(M)-f3,2λΛ(2|1,3)ελ1-λ2+2-MPλ¯e1,2(M-1)Mathematical equation;

(2.1f) e1,2(M)e1,3=εMe1,3e1,2(M)Mathematical equation ;

(2.1g) e1,2(M)e2,3=ε-Me2,3e1,2(M)+e1,3e1,2(M-1)Mathematical equation.

Proof   For (2.1a), by e1,3e2,3=e1,2e2,32-ε-1e2,3e1,2e2,3=-ε-1e2,3e1,2e2,3=-ε-1e2,3e1,3Mathematical equation.The equation holds.

For (2.1b), we can obtain e1,3f3,1=-f3,1e1,3+λΛ(2|1,3)[λ1+λ3]Pλ¯Mathematical equation by

e 1,3 f 3,1 = e 1,2 e 2,3 f 3,1 - ε - 1 e 2,3 e 1,2 f 3,1 = - f 3,1 e 1,3 + ( f 3,2 e 2,3 + e 2,3 f 3,2 ) λ Λ ( 2 | 1,3 ) ε λ 1 - λ 2 P λ ¯    + ( e 1,2 f 2,1 - f 2,1 e 1,2 ) λ Λ ( 2 | 1,3 ) ε - λ 2 - λ 3 P λ ¯ = - f 3,1 e 1,3 + λ Λ ( 2 | 1,3 ) ε λ 1 - λ 2 [ λ 2 + λ 3 ] P λ ¯    + λ Λ ( 2 | 1,3 ) ε - λ 2 - λ 3 [ λ 1 - λ 2 ] P λ ¯ = - f 3,1 e 1,3 + λ Λ ( 2 | 1,3 ) [ λ 1 + λ 3 ] P λ ¯ . Mathematical equation

For (2.1c), in order to prove e1,2(M)f3,2=f3,2e1,2(M)Mathematical equation, we need following steps:

Step 1   When M=1Mathematical equation,we can easily prove e1,2f3,2=f3,2e1,2Mathematical equation.

Step 2   When M1Mathematical equation, we assume e1,2(M)f3,2=f3,2e1,2(M)Mathematical equation holds, then we will discuss the following situation:e1,2(M+1)f3,2=[M+1]-1e1,2e1,2(M)f3,2=[M+1]-1e1,2f3,2e1,2(M)=[M+1]-1f3,2e1,2e1,2(M)=f3,2e1,2(M+1).Mathematical equation

For (2.1d), we can obtain e1,3f3,2=-f3,2e1,3+λΛ(2|1,3)ελ2+λ3Pλ¯e1,2Mathematical equation by (2.1c)

e 1,3 f 3,2 = e 1,2 e 2,3 f 3,2 - ε - 1 e 2,3 e 1,2 f 3,2 = - e 1,2 f 3,2 e 2,3 + e 1,2 λ Λ ( 2 | 1,3 ) [ λ 2 + λ 3 ] P λ ¯ + ε - 1 f 3,2 e 2,3 e 1,2 - ε - 1 λ Λ ( 2 | 1,3 ) [ λ 2 + λ 3 ] P λ ¯ e 1,2 = - f 3,2 e 1,3 + λ Λ ( 2 | 1,3 ) ε λ 2 + λ 3 P λ ¯ e 1,2 . Mathematical equation

For (2.1e), in order to prove e1,2(M)f3,1=f3,1e1,2(M)-f3,2λΛ(2|1,3)ελ1-λ2+2-MPλ¯e1,2(M-1)Mathematical equation, we need the following steps:

Step 3   When M=1Mathematical equation,we can prove e1,2f3,1=f3,1e1,2-f3,2λΛ(2|1,3)ελ1-λ2+1Pλ¯ by (2.1c),Mathematical equation

e 1,2 f 3,1 = e 1,2 f 3,2 f 2,1 - ε e 1,2 f 2,1 f 3,2 = f 3,1 e 1,2 + f 3,2 λ Λ ( 2 | 1,3 ) [ λ 1 - λ 2 ] P λ ¯ - ε λ Λ ( 2 | 1,3 ) [ λ 1 - λ 2 ] P λ ¯ f 3,2 = f 3,1 e 1,2 - f 3,2 λ Λ ( 2 | 1,3 ) ε λ 1 - λ 2 + 1 P λ ¯ . Mathematical equation

Step 4   When M1Mathematical equation, we assume e1,2(M)f3,1=f3,1e1,2(M)-f3,2λΛ(2|1,3)ελ1-λ2+2-MPλ¯e1,2(M-1)Mathematical equation holds, then we will discuss the following situation:

e 1,2 ( M + 1 ) f 3,1 = [ M + 1 ] - 1 e 1,2 ( f 3,1 e 1,2 ( M ) - f 3,2 λ Λ ( 2 | 1,3 ) ε λ 1 - λ 2 + 2 - M P λ ¯ e 1,2 ( M - 1 ) ) = f 3,1 e 1,2 ( M + 1 ) - [ M + 1 ] - 1 f 3,2 λ Λ ( 2 | 1,3 ) ( ε λ 1 - λ 2 + 1    + ε λ 1 - λ 2 - M [ M ] ) P λ ¯ e 1,2 ( M ) = f 3,1 e 1,2 ( M + 1 ) - f 3,2 λ Λ ( 2 | 1,3 ) ε λ 1 - λ 2 + 1 - M P λ ¯ e 1,2 ( M ) . Mathematical equation

For (2.1f, 2.1g), the proof is similar to the above.

Theorem 5   The algebra TMathematical equation is generated by the elements ei, fi,Mathematical equation Pλ¯(λΛ(2|1,3),(1i2))Mathematical equation, subject to the following relations:

( L R 1 ) e i l = 0 ,   f i l = 0 Mathematical equation when i2Mathematical equation;

( L R 2 ) λ Λ ( 2 | 1,3 ) P λ ¯ = 1 ,   P λ ¯ P μ ¯ = δ λ μ P λ ¯ Mathematical equation;

( L R 3 )   [ e i , f j ] = δ i j λ Λ ( 2 | 1,3 ) [ λ i - ( - 1 ) e i ^ f j ^ λ i + 1 ] ε P λ ¯ Mathematical equation;

( L R 4 ) e i 2 e j - ( ε + ε - 1 ) e i e j e i + e j e i 2 = 0 Mathematical equation when |i-j|=1Mathematical equation;

( L R 5 ) f i 2 f j - ( ε + ε - 1 ) f i f j f i + f j f i 2 = 0 Mathematical equation when |i-j|=1Mathematical equation;

( L R 6 ) [ e a , e b ] = 0 , [ f a , f b ] = 0 Mathematical equation when |a-b|>1Mathematical equation;

( L R 7 ) e i P λ ¯ = { P μ + α i ¯ e i , i f      μ ¯ = λ ¯ , μ i + 1 1 0 , o t h e r w i s e , Mathematical equation

P λ ¯ e i = { e i P μ - α i ¯ , i f      μ ¯ = λ ¯ , μ i 1 0 , o t h e r w i s e Mathematical equation;

( L R 8 ) f i P λ ¯ = { P μ - α i ¯ f i , i f      μ ¯ = λ ¯ , μ i 1 0 , o t h e r w i s e , Mathematical equation

P λ ¯ f i = { f i P μ + α i ¯ , i f      μ ¯ = λ ¯ , μ i + 1 1 0 , o t h e r w i s e Mathematical equation;

( L R 9 ) Mathematical equation e c ( A j + ) P λ ¯ = 0 Mathematical equation (resp.Pλ¯fc(Aj-)=0Mathematical equation) for Aj+Γj+(2|1,3)Mathematical equation (resp. Aj-Γj-(2|1,3)Mathematical equation) and λΛ(2|1,3)Mathematical equation satisfying that if μΛ(2|1,3) with μ¯=λ¯ then μj<σj(A);Mathematical equation

( L R 10 )    e 1 P ( 2 ¯ , 1 ¯ , 0 ) ¯ f 1 = 0 , e 2 P ( 0 ¯ , 2 ¯ , 1 ¯ ) f 2 = 0 . Mathematical equation

The key to prove Theorem 5 is that in uk(2|1,3)Mathematical equation, the relation (LR10)Mathematical equation holds.

Proposition 3   In little q-Schur superalgebra uk(2|1,3)Mathematical equation, we have eiPλ¯fi=0Mathematical equation.

If λj<3,1ji+13,λj=2Mathematical equation and λi+1=1Mathematical equation.

Proof   e 1,2 P ( 2,1 , 0 ) f 2,1 = e 1,2 k ( 2,1 , 0 ) f 2,1 = k ( 3,0 , 0 ) e 1,2 f 2,1 = k ( 3,0 , 0 ) f 2,1 e 1,2 = 0 ; e 2,3 P ( 0,2 , 1 ) f 3,2 = e 2,3 k ( 0,2 , 1 ) f 3,2 = k ( 0,3 , 0 ) e 2,3 f 3,2 = - k ( 0,3 , 0 ) f 3,2 e 2,3 = 0 . Mathematical equation

From the above conclusions, it can be seen that little q-Schur superalgebra uk(2|1,3)Mathematical equation satisfies the relation (LR10)Mathematical equation of Theorem 5.

We define an algebra TMathematical equation which satisfies the generators and relations given in Theorem 5. Set T+Mathematical equation(resp. T-Mathematical equation,T0Mathematical equation) be the subalgebra generated by eiMathematical equation(resp. fiMathematical equation, Pλ¯Mathematical equation). For TMathematical equation, we give the root vectors in the same way, which satisfy the commutation formulas (2.1a)-(2.1g). According to the relations (LR3)-(LR7) in Theorem 5, we know that T=T+T0T-Mathematical equation can be spanned by all the elements WA,λ¯:=ec(A+)Pλ¯fc(A-)Mathematical equation, AΓ±(2|1,3)Mathematical equation.

Proposition 4   The set

W k = { e c ( A + ) P λ ¯ f c ( A - ) | λ Λ ( 2 | 1,3 ) ,   λ i σ i ( A ) , i = 1,2 , 3 , A Mathematical equation

Γ ± ( 2 | 1 ) } Mathematical equation is a spanning set for TMathematical equation.

Proof   Fixing BΓ±(2|1)Mathematical equation, to prove this proposition, it suffices to show that if λ'Λ(2|1,3)Mathematical equation with λ'¯=λ¯Mathematical equation, satisfying λj'<σj(B)Mathematical equation for some jMathematical equation, then WB,λ¯'=ec(B+)Pλ¯'fc(B-)Mathematical equation lies in the span of WkMathematical equation. Here Wka(aN+)Mathematical equation is a linear combination of the elements in WkMathematical equation and ga(aN+)Mathematical equation is a constant.

Case 1 If λ2'<σ2(B)Mathematical equation and λ3'σ3(B)Mathematical equation, assuming λ2'=σ2(B)-1Mathematical equation. For ec(B+)Pλ'¯fc(B-)Mathematical equation, we only need to consider e1,2(b1,2)Pλ¯'f2,1(b2,1)Mathematical equation.

By Theorem 5 (LR9)Mathematical equation, when b1,2=0Mathematical equation (or b2,1=0Mathematical equation), Pλ¯'f2,1(b2,1)Mathematical equation (or e1,2(b1,2)Pλ¯'Mathematical equation) is a linear combination of the elements in WkMathematical equation.Then we consider e1,2(b1,2)Pλ¯'f2,1(b2,1)Mathematical equation, where 1b1,2,b2,12Mathematical equation.

Case 1-1 If λ2'=1Mathematical equation and σ2(B)=2Mathematical equation, for e1,2P(λ1'¯,1¯,λ3'¯)f2,1Mathematical equation,

1) When 0λ1'1Mathematical equation, by Theorem 5 (LR3)Mathematical equation,

e 1,2 P ( λ 1 ' ¯ , 1 ¯ , λ 3 ' ¯ ) f 2,1 = P ( λ 1 ' + 1 ¯ , 0 ¯ , λ 3 ' ¯ ) e 1,2 f 2,1 = P ( λ 1 ' + 1 ¯ , 0 ¯ , λ 3 ' ¯ ) f 2,1 e 1,2 + W k 1 Mathematical equation

where Wk1Mathematical equationis a linear combination of the elements in WkMathematical equation.

2) When λ1'=2Mathematical equation, by Theorem 5 (LR10)Mathematical equation, we can obtain e1,2P(2¯,1¯,0¯)f2,1=0Mathematical equation.

Case 1-2 If λ2'=2Mathematical equation and σ2(B)=3Mathematical equation, for e1,2(b1,2)P(λ1'¯,2¯,λ3'¯)f2,1(b2,1)Mathematical equation, where b1,2=1,b2,1=2Mathematical equation, by Theorem 5 (LR3)Mathematical equation,

e 1,2 P ( λ 1 ' ¯ , 2 ¯ , λ 3 ' ¯ ) f 2,1 ( 2 ) = [ 2 ] ε - 1 e 1,2 f 2,1 P ( λ 1 ' + 1 ¯ , 1 ¯ , λ 3 ' ¯ ) f 2,1 = [ 2 ] ε - 1 f 2,1 e 1,2 P ( λ 1 ' + 1 ¯ , 1 ¯ , λ 3 ' ¯ ) f 2,1 + W k 2 . Mathematical equation

Then,

1) When λ1'=0Mathematical equation,

e 1,2 P ( 0 ¯ , 2 ¯ , 1 ¯ ) f 2,1 ( 2 ) = [ 2 ] ε - 1 f 2,1 e 1,2 P ( 1 ¯ , 1 ¯ , 1 ¯ ) f 2,1 + W k 2 = [ 2 ] ε - 1 f 2,1 2 e 1,2 P ( 2 ¯ , 0 ¯ , 1 ¯ ) + [ 2 ] ε - 1 [ 2 ] ε P ( 1 ¯ , 1 ¯ , 1 ¯ ) f 2,1 + W k 2 = W k 2 + W k 3 . Mathematical equation

2) When λ1'=1Mathematical equation, by Theorem 5 (LR10)Mathematical equation, we can obtain

e 1,2 P ( λ 1 ' ¯ , 2 ¯ , λ 3 ' ¯ ) f 2,1 ( 2 ) = [ 2 ] ε - 1 f 2,1 e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 2,1 + W k 2 Mathematical equation

where Wk2Mathematical equationand Wk3Mathematical equation are linear combinations of the elements in WkMathematical equation.

For e1,2(b1,2)P(λ1'¯,2¯,λ3'¯)f2,1(b2,1)Mathematical equation, when b1,2=2,b2,1=1Mathematical equation, the proof is similar to the above.

Case 1-3 If λ2'=3Mathematical equation and σ2(B)=4Mathematical equation, for e1,2(b1,2)P(0¯,3¯,0¯)f2,1(b2,1)Mathematical equation ,

When b1,2=1Mathematical equation (or b2,1=1Mathematical equation), by Theorem 5 (LR1)Mathematical equation, we can obtain e1,2(b1,2)P(0¯,3¯,0¯)f2,1(b2,1)=0Mathematical equation.

When b1,2=b2,1=2Mathematical equation, by Theorem 5 (LR3,LR10)Mathematical equation,

e 1,2 ( 2 ) P ( 0 ¯ , 3 ¯ , 0 ¯ ) f 2,1 ( 2 ) = [ 2 ] ε - 2 e 1,2 P ( 1 ¯ , 2 ¯ , 0 ¯ ) e 1,2 f 2,1 2 = [ 2 ] ε - 2 e 1,2 f 2,1 P ( 2 ¯ , 1 ¯ , 0 ¯ ) e 1,2 f 2,1 - [ 2 ] ε - 2 e 1,2 P ( 1 ¯ , 2 ¯ , 0 ¯ ) f 2,1 = [ 2 ] ε - 2 f 2,1 e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 2,1 e 1,2 + [ 2 ] ε - 2 e 1,2 P ( 1 ¯ , 2 ¯ , 0 ¯ ) f 2,1    - [ 2 ] ε - 2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) = [ 2 ] ε - 2 f 2,1 e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 2,1 e 1,2 + W k 4 , Mathematical equation

where Wk4Mathematical equationis a linear combination of the elements in WkMathematical equation.

Case 2 If λ3'<σ3(B)Mathematical equation and λ2'σ2(B)Mathematical equation, assuming λ3'=σ3(B)-1Mathematical equation, for ec(B+)Pλ'¯fc(B-)Mathematical equation, by the commutation formulas (2.1a), (2.1f) , we have

e c ( B + ) P λ ' ¯ f c ( B - ) = e 1,3 ( b 1,3 ) e 2,3 ( b 2,3 ) e 1,2 ( b 1,2 ) P λ ' ¯ f 2,1 ( b 2,1 ) f 3,2 ( b 3,2 ) f 3,1 ( b 3,1 ) = ε g 3 e 1,2 ( b 1,2 ) ( e 1,3 ( b 1,3 ) e 2,3 ( b 2,3 ) P λ ' ¯ f 3,2 ( b 3,2 ) f 3,1 ( b 3,1 ) ) f 2,1 ( b 2,1 ) + W k 5 , Mathematical equation

where Wk5Mathematical equationis a linear combination of the elements in WkMathematical equation.Therefore, we only need to consider ec(B3+)Pλ¯'fc(B3-)Mathematical equation.

By Theorem 5 (LR9)Mathematical equation, when b1,3+b2,3=0Mathematical equation (or b3,2+b3,1=0Mathematical equation), Pλ¯'f3,2(b3,2)f3,1(b3,1)Mathematical equation (or e1,3(b1,3)e2,3(b2,3)Pλ¯'Mathematical equation) is a linear combination of the elements in WkMathematical equation. We consider ec(B3+)Pλ¯'fc(B3-)Mathematical equation, where b1,3+b2,30Mathematical equation and b3,2+b3,10Mathematical equation.

Case 2-1 If λ3'=1Mathematical equation and σ3(B)=2Mathematical equation, we need to consider e1,3(b1,3)e2,3(b2,3)P(λ1'¯,λ2'¯,1¯)f3,2(b3,2)f3,1(b3,1)Mathematical equation ,

When b2,3=b3,2=1Mathematical equation, for e2,3P(λ1'¯,λ2'¯,1¯)f3,2Mathematical equation,

1) When 0λ2'1Mathematical equation, by Theorem 5 (LR3)Mathematical equation,

e 2,3 P ( λ 1 ' ¯ , λ 2 ' ¯ , 1 ¯ ) f 3,2 = P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) e 2,3 f 3,2 = - P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) f 3,2 e 2,3 + W k 6 Mathematical equation

where Wk6Mathematical equationis a linear combination of the elements in WkMathematical equation.

2) When λ2'=2Mathematical equation, by Theorem 5 (LR10)Mathematical equation, we can obtain e2,3P(λ1'¯,λ2'¯,1¯)f3,2=e2,3P(0¯,2¯,1¯)f3,2=0Mathematical equation.

When b2,3=b3,1=1Mathematical equation, for e2,3P(λ1'¯,λ2'¯,1¯)f3,1Mathematical equation,

1) When 0λ1'1Mathematical equation, by Theorem 5 (LR3, LR9) and the commutation formulas (2.1c),

e 2,3 P ( λ 1 ' ¯ , λ 2 ' ¯ , 1 ¯ ) f 3,1 = P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) e 2,3 f 3,2 f 2,1 - ε P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) e 2,3 f 2,1 f 3,2 = - P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) f 3,2 e 2,3 f 2,1 + [ λ 2 ' + 1 ] ε P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) f 2,1      - ε f 2,1 P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 0 ¯ ) e 2,3 f 3,2 = ε f 2,1 P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 0 ¯ ) f 3,2 e 2,3 + ( [ λ 2 ' + 1 ] ε - ε [ λ 2 ' ] ε ) P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) f 2,1 = ε f 2,1 P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 0 ¯ ) f 3,2 e 2,3 + W k 7 , Mathematical equation

where Wk7Mathematical equationis a linear combination of the elements in WkMathematical equation.

2) When λ1'=2Mathematical equation, by Theorem 5 (LR3,LR9,LR10)Mathematical equation,

e 2,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,1 = e 2,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,2 f 2,1 - ε e 2,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 2,1 f 3,2 = e 2,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,2 f 2,1 = - P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 3,2 e 2,3 f 2,1 + P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 2,1 = - P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 3,2 e 2,3 f 2,1 + W k 8 , Mathematical equation

where Wk8Mathematical equationis a linear combination of the elements in WkMathematical equation.

When b1,3=b3,1=1Mathematical equation, for e1,3P(λ1'¯,λ2'¯,1¯)f3,1Mathematical equation,

1) When 0λ1'1Mathematical equation, by the commutation formulas (2.1b), we have e1,3P(λ1'¯,λ2'¯,1¯)f3,1=P(λ1'+1¯,λ2'¯,0¯)e1,3f3,1=-P(λ1'+1¯,λ2'¯,0¯)f3,1e1,3+[λ1'+1]εP(λ1'+1¯,λ2'¯,0¯)=Wk9Mathematical equation,

where Wk9Mathematical equation is a linear combination of the elements in WkMathematical equation.

2) When λ1'=2Mathematical equation, by theorem 5 (LR10,LR9)Mathematical equation and the commutation formulas (2.1d), we have

e 1,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,1 = e 1,2 e 2,3 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,1 - ε - 1 e 2,3 e 1,2 P ( 2 ¯ , 0 ¯ , 1 ¯ ) f 3,1 = e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) e 2,3 f 3,1 = - e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 3,1 e 2,3 + e 1,2 P ( 2 ¯ , 1 ¯ , 0 ¯ ) f 2,1 = 0 . Mathematical equation

For e1,3(b1,3)e2,3(b2,3)P(λ1'¯,λ2'¯,1¯)f3,2(b3,2)f3,1(b3,1)Mathematical equation, when b1,3=b3,2=1Mathematical equation, the proof is similar to the above.

Case 2-2 If λ3'=2Mathematical equation and σ3(B)=3Mathematical equation, for e1,3(b1,3)e2,3(b2,3)P(λ1'¯,λ2'¯,2¯)Mathematical equation

f 3,2 ( b 3,2 ) f 3,1 ( b 3,1 ) Mathematical equation, when b1,3=0Mathematical equation, for e2,3P(λ1'¯,λ2'¯,2¯)f3,2f3,1Mathematical equation,by Theorem 5 (LR3)Mathematical equation and the commutation formulas (2.1d),

e 2,3 P ( λ 1 ' ¯ , λ 2 ' ¯ , 2 ¯ ) f 3,2 f 3,1 = - f 3,2 e 2,3 P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 3,1 + [ λ 2 ' + 2 ] ε P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 3,1 = ε [ λ 2 ' + 1 ] ε P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 3,1 - ε - λ 2 ' P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 2,1 f 3,2 = W k 10 , Mathematical equation

where Wk10Mathematical equationis a linear combination of the elements in WkMathematical equation.

When b2,3=0Mathematical equation, by the commutation formulas (2.1b , 2.1d ), we have

e 1,3 P ( λ 1 ' ¯ , λ 2 ' ¯ , 2 ¯ ) f 3,2 f 3,1 = P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 1 ¯ ) e 1,3 f 3,2 f 3,1 = - P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 1 ¯ ) f 3,2 e 1,3 f 3,1   + ε λ 2 ' + 1 P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 1 ¯ ) e 1,2 f 3,1 = - f 3,2 P ( λ 1 ' + 1 ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) e 1,3 f 3,1 + ε λ 2 ' + 1 e 1,2 P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 3,1 = f 3,2 P ( λ 1 ' + 1 ¯ , λ 2 ' + 1 ¯ , 0 ¯ ) f 3,1 e 1,3 - [ λ 1 ' + 1 ] ε P ( λ 1 ' + 1 ¯ , λ 2 ' ¯ , 1 ¯ ) f 3,2 Mathematical equation

+ ε λ 2 ' + 1 e 1,2 P ( λ 1 ' ¯ , λ 2 ' + 1 ¯ , 1 ¯ ) f 3,1 = W k 11 , Mathematical equation

where Wk11Mathematical equationis a linear combination of the elements in WkMathematical equation.

For e1,3(b1,3)e2,3(b2,3)P(λ1'¯,λ2'¯,2¯)f3,2(b3,2)f3,1(b3,1)Mathematical equation, when b3,1=0Mathematical equation and b3,2=0Mathematical equation, the proof is similar to the above.

Case 2-3 If λ3'=3Mathematical equation and σ3(B)=4Mathematical equation,we need to consider e1,3e2,3P(0¯,0¯,3¯)f3,2f3,1Mathematical equation, by Theorem 5 (LR9Mathematical equation, LR10Mathematical equation) and the commutation formulas (2.1b , 2.1d ), we have

e 1,3 e 2,3 P ( 0 ¯ , 0 ¯ , 3 ¯ ) f 3,2 f 3,1 = - P ( 1 ¯ , 1 ¯ , 1 ¯ ) e 1,3 f 3,2 e 2,3 f 3,1 + [ 3 ] ε e 1,3 P ( 0 ¯ , 1 ¯ , 2 ¯ ) f 3,1 = P ( 1 ¯ , 1 ¯ , 1 ¯ ) f 3,2 f 3,1 e 1,3 e 2,3 - P ( 1 ¯ , 1 ¯ , 1 ¯ ) f 3,2 e 2,3    - ε - 2 P ( 1 ¯ , 1 ¯ , 1 ¯ ) e 1,3 f 3,2 f 2,1 + W k 12 = e 2,3 P ( 1 ¯ , 0 ¯ , 2 ¯ ) f 3,2 - [ 2 ] ε P ( 1 ¯ , 1 ¯ , 1 ¯ ) - ε - 2 e 1,3 P ( 0 ¯ , 1 ¯ , 2 ¯ ) f 3,1    - ε - 1 e 1,3 P ( 0 ¯ , 1 ¯ , 2 ¯ ) f 2,1 f 3,2 + W k 12 = W k 13 , Mathematical equation

where Wk12Mathematical equationand Wk13Mathematical equation are the linear combination of the elements in WkMathematical equation. We complete the proof of Proposition 4.

Proof of Theorem 5   By the definition of TMathematical equation and Theorem 1, it is clear that TMathematical equation satisfies the relations (Q1-Q6) in Definition 1. Hence, there is a surjective algebra homomorphism from TMathematical equation to uk(2|1,3)Mathematical equation. On the basis of Theorem 3, Propositions 1 and 4, we have the uk(2|1,3)Mathematical equation that satisfies the relations in Theorem 5. According to the definition of uk(2|1,3)Mathematical equation, there is a surjective algebra homomorphism ψMathematical equation from TMathematical equation to uk(2|1,3)Mathematical equation satisfying ψ(ei)=eiMathematical equation, ψ(fi)=fiMathematical equation, ψ(Pλ¯)=Pλ¯Mathematical equation. On the other hand, by Proposition 1, we see that the map ψMathematical equation sends the spanning set of TMathematical equation to the basis of uk(2|1,3)Mathematical equation. Hence ψMathematical equation is an isomorphism.

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