Issue |
Wuhan Univ. J. Nat. Sci.
Volume 30, Number 1, February 2025
|
|
---|---|---|
Page(s) | 60 - 68 | |
DOI | https://doi.org/10.1051/wujns/2025301060 | |
Published online | 12 March 2025 |
Mathematics
CLC number: O177
Property
and Property
for Operator and Its Functions
算子及算子函数的
性质与
性质
1 School of Mathematics and Statistics, Weinan Normal University, Weinan 714099, Shaanxi, China
2 School of Mathematics and Statistics, Shaanxi Normal University, Xi'an 710062, Shaanxi, China
Received:
18
April
2024
By using the topological uniform descent, the necessary and sufficient conditions for which property and property
hold for bounded linear operators are given. As a consequence of the main result, the stability of property
and property
is studied, and a new judgement for operator functions that satisfy property
and property
is discussed.
摘要
本文运用拓扑一致降标性质,给出了有界线性算子同时满足性质与
性质的充要条件。之后利用主要结论,研究了
性质与
性质的稳定性,并得到了算子函数同时有
性质与
性质的新判定方法。
Key words: property (WE) / property (R) / spectrum
关键字 : (WE)性质 / (R)性质 / 谱
Cite this article: SUN Chenhui, CAO Xiaohong. Property (WE) and Property (R) for Operator and Its Functions[J]. Wuhan Univ J of Nat Sci, 2025, 30(1): 60-68.
Biography: SUN Chenhui, female, Ph. D., Associate professor, research direction: operator theory. E-mail: sunchenhui1986@163. com
Foundation item: Supported by the 2021 General Special Scientific Research Project of the Education Department of Shaanxi Provincial Government (21JK0637), the Science and Technology Planning Project of Weinan Science and Technology Bureau (2022ZDYFJH-11) and the 2021 Talent Project of Weinan Normal University (2021RC16)
© Wuhan University 2025
This is an Open Access article distributed under the terms of the Creative Commons Attribution License (https://creativecommons.org/licenses/by/4.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
0 Introduction
The Weyl type theorem of bounded linear operator can well reflect the structure characteristics and distribution of operator's spectral[1-5]. Therefore, the Weyl type theorem is an important topic in spectral theory. In recent years, the research scope of Weyl type theorems has been extended from general operators to operator functions, operator matrices, etc. Numerous significant results have been obtained[6-9]. Property and property
are the latest variations of Weyl type theorems, which have attracted the attention and research of operator theorists[10-12]. In this paper, by decomposing and constructing the operator spectrum and using the topological uniform scaling property, we give a new method for bounded linear operators and operator functions to satisfy the property
and property
. Furthermore, the perturbation of property
and property
is characterized, and the necessary and sufficient conditions for the operator function to have both the property
and property
are studied.
Throughout this paper, denotes a complex separable infinite dimensional Hilbert space. Let
be the algebra of all bounded linear operators on
. For an operator
we shall denote by
the dimension of the kernel
, and by
the codimension of the range
. We call
is an upper semi-Fredholm operator if
and
is closed. If
is an upper semi-Fredholm operator and
, we call
a bounded below operator. If
,
is a lower semi-Fredholm operator. An operator
is said to be Fredholm if
is closed and both
and
are finite. If
is an upper (or a lower) semi-Fredholm operator, the index of
,
, is defined to be
. The ascent of
,
, is the least non-negative integer
such that
and the descent,
, is the least non-negative integer
such that
. We call
a Drazin invertible operator if
. The operator
is Weyl if it is Fredholm of index zero, and
is said to be Browder if it is Fredholm "of finite ascent and descent". Let
be the spectrum of
and
be the approximate point spectrum of
. We write
,
,
,
,
and
for the Weyl spectrum of
, the Browder spectrum of
, the essential spectrum of
, the semi-Fredholm spectrum of
, the essential approximate point spectrum of
and the Browder essential approximate point spectrum of
. Let
,
,
,
,
,
(
denotes the set of complex numbers).
is called an isoloid operator if
where
. For a set
, we write
,
and
for the set of isolated points, accumulation points and boundary points set of
. We denote by
the set of all normal eigenvalues of
, thus
.
satisfies property
if
, where
[10].
satisfies property
if
, where
[10].
In this paper, we mainly study property and property
for bounded linear operators and its functions. Some meaningful conclusions are obtained.
1 Judgement of Property
and Property
for Bounded Linear Operators
Although both property and property
are variations of Weyl's theorem based on their definitions, there is no necessary connection between them.
Remark 1 (i) satisfies property
satisfies property
.
Let be defined by
,
. Suppose that
. Then
,
,
,
.
satisfies property
, but property
does not hold for
.
(ii) satisfies property
satisfies property
.
Let be defined by
,
,
. We have that
,
.
. So
satisfies property
and
does not have property
.
(iii) has property
and property
and
.
Topological uniform descent is an important property of operators, which is widely used in spectral theory. If , then for each nonnegative integer
,
induces a linear transformation from the vector space
to
. We denote
the dimension of the null space of the induced map and let
. The following definition was introduced by Grabiner[13]. Let
, if there is a nonnegative integer
for which
for
and
is closed in the operator range topology of
for
, then we say that
has topological uniform descent.
It can be shown that if is upper semi-Fredholm, then
has topological uniform descent. Let
has topological uniform descent},
. Grabiner discovered many properties of topological uniform descent. We will use the following property (Ref. [13], Corollary 4.9): Suppose that
,
, if
has topological uniform descent, then
is a pole of
. Next, we will discuss property
and property
by using the topological uniform descent.
Lemma 1 Let , the following statements are equivalent:
(1) satisfies property
;
(2) ;
(3)
Proof (1)(2). Suppose that
satisfies property
. If
, then there exists a deleted neighborhood
centered on
such that for any
,
is a Weyl operator. Since
has property
, we know that
is a Browder operator. Then we get that
. We assume that
. If
, we get that
is Drazin invertible. According to
, we have
. Since
satisfies property
, we can get that
is a Browder operator. If
, we can also get that
and
is Browder operators. The inclusion "
" is obviously true.
(2)(1). Since
and
, we know that
. Similarly,
. Hence
satisfies property
.
The fact that implies that (2)
(3).
The closeness of operator range is very important in spectral theory. According to the closeness of operator range, the following spectral set is defined: is not closed}.
Lemma 2 Let , the following statements are equivalent:
(1) satisfies property
;
(2)
;
(3)
Proof (1)(2). Suppose
. Without loss of generality, we assume that
. Then we have
. There exists a deleted neighborhood
centered on
such that for any
,
. If
, then
. Since
satisfies property
, we have that
is a Browder operator. Suppose that
, if
, then
is an upper semi-Fredholm operator. By
,
and
, we know that
. Because
has property
, we can get that
. If
, then exists a deleted neighborhood
centered on
such that for any
,
. Therefore
. Since
and
, we can also get that
.
(2)(1). Suppose that
. It follows that
. So
is a Browder operator. Then we have
. Similarly, we can get the inclusion "
". Hence
satisfies property
.
If (2) holds, then has property
. This implies that
, where
. It follows that
. Hence
. Then we have that
The inclusion "" is obviously true. This implies that (3) holds. For the converse, if (3) holds, by
we know that (2) holds. Therefore (2)
(3).
Based on Lemma 1 and Lemma 2, the following results demonstrate that the two properties can be valid at the same time:
Theorem 1
satisfies property
and property
if and only if
Proof "". Suppose
has property
. Using Lemma 2, we have that
Since
has property
, we know that
Thus
"". By the condition, we get that
The inclusion "
" is obviously true. From Lemma 2, we know that
satisfies property
.
If , then
is a Browder operator,
. The converse is similar. Therefore
satisfies property
.
Remark 2 (i) In Theorem 1, suppose satisfies property
and property
, then each part of the decomposition of
cannot be deleted.
() Let
be defined by
. Hence
has property
and property
. But
Thus
cannot be deleted.
() Let
be defined by
. Then
has property
and property
. But
. Thus
cannot be deleted.
() Let
be defined by
. We know that
has property
and property
. But
. Hence
cannot be deleted.
() Let
be defined by
,
. And suppose
. Then
satisfies property
and property
. But
. Therefore
cannot be deleted.
() Let
be defined by
,
. And suppose
. Thus
satisfies property
and property
. But
. It follows that
cannot be deleted.
(ii) The conditions in Theorem 1 can be transformed as follows: can be replaced by
,
can be replaced by
.
From Lemma 1 and Lemma 2, we can get the following Corollary.
Corollary 1 Let . Then:
(1) satisfies property
;
(2) satisfies property
By Theorem 1 and Corollary 1, we can get the following Corollary.
Corollary 2 Let . Then
satisfies property
and property
Proof Using Theorem 1, satisfies property
and property
"".
is obvious. If
and
, by Theorem 1 we know that
.
"". Suppose
and
. If
, we have
by the condition. Suppose
, if
, we can get that
, then
is a Browder operator. If
, using
we have
. It also follows that
. From Theorem 1, we can get that
satisfies property
and property
.
2 The Perturbation of Property
and Property
Suppose satisfies property
or property
and
is a compact operator or even a finite rank operator, but we cannot deduce that
satisfies property
or property
. For example, let
be defined by
,
. It is obviously that
satisfies property
and property
and
is a finite rank operator. However, calculations indicate that
does not satisfy either property
or property
.
The operator is called a power finite rank operator, if there is a positive integer
such that
. A power finite rank operator is a Riesz operator, therefore, when
is a power finite rank operator, operator
is commutative with
, then it has the following properties:
, where
and
[14].
Due to the complexity of general compact perturbations, this section focuses on the power finite rank perturbation of property and property
.
Lemma 3 Let and
is a power finite rank operator with
. The following statements are equivalent:
(1) satisfies property
and is an isoloid operator;
(2) ;
(3) .
Proof (1)(2). Since
satisfies property
and
,
, we have that
. If
, when
, by the proof of Lemma 1, we know that
is Drazin invertible. Thus
. If
, then
. Since
has property
, we get that
is a Browder operator. It is a contradiction. Therefore
, hence
. By
is Drazin invertible we have that
. Suppose that
. Without loss of generality, we assume that
. Then
. The fact that
is isoloid implies that
. Because
has the property
,
is a Browder operator. We also have that
.
(2)(1). Suppose that
. Then we have that
is a Weyl operator. So
. By condition (2), we can get that
is a Browder operator. Thus
is a Browder operator. Then
. Contrarily, if
, then
. Therefore
. Hence
and
are Browder operators.
If there exists such that
, then
. By condition (2), we have that
is a Browder operator. It follows that
is a Browder operator. The fact that
implies that
is invertible, which is a contradiction. Therefore
is an isoloid operator.
(1)(3). Suppose
. If
, from the proof of (1)
(2) we can get that
. If
, we assume that
without loss of generality. Since
, we have that
. Hence
. Since
is isoloid and satisfies property
, we have that
is a Browder operator. Thus
.
(3)(1). The proof for (3)
(1) is the same as the proof for (2)
(1).
Lemma 4 Let and
is a power finite rank operator with
. The following statements are equivalent:
(1) is an isoloid operator and satisfies property
,
;
(2) ;
(3)
Proof (1)(2). Suppose
. We assume that
. If
, when
, we can get that
. Then
is a Browder operator. When
, we have that
is a Weyl operator. Hence
. The fact that
satisfies property
implies that
is a Browder operator. Hence
. If
, then
. We can assume that
. Since
is an isoloid operator, we have that
. Since
satisfies property
, we can get that
is a Browder operator. Therefore
.
(2)(1). Let's first prove that
is an isoloid operator. If there exists
such that
. We assume that
without loss of generality. Thus
,
. Therefore
. It follows that
is a Browder operator. Then
is a Browder operator. Hence
is invertible, which is a contradiction. Thus
is an isoloid operator.
Next we will prove . If
, then
. It implies that both
and
are Browder operators. Hence
.
If , then
. Hence
and
are Browder operators. Thus
. Conversely, suppose that
, then
. Then we also have that
. Thus
and
are Browder operators. Hence
satisfies property
.
The proof for (1)(3) is the same as the proof for (1)
(2).
Then we obtain the finite rank perturbation with two properties held at the same time.
Theorem 2 Let and
is a power finite rank operator with
. The following statements are equivalent:
(1) is an isoloid operator and satisfies property
and property
,
;
(2)
Proof (1)(2). Suppose
. If
, by Lemma 4 we have that
. If
, by Lemma 3 we also get that
.
(2)(1). The statement (2) implies that
. Suppose
, then
. If
, then
. If
, we have that
. Thus
is Drazin invertible. Therefore
. Hence
. Then
is a Browder operator. Thus
. With Lemma 3 we get that
is isoloid and satisfies property
.
By condition (2) we have that . Then according to Lemma 4 we have that
satisfies property
and
. Therefore (1) holds.
3 Property
and Property
for Operator Functions
Let be the class of all complex-valued functions which are analytic on a neighborhood of
and are not constant on any component of
. For the function's properties, we discuss property
first.
Lemma 5 Let . For any
,
satisfies property
if and only if
,
,
and one of the following conditions holds:
(1) ;
(2) .
Proof "". Suppose (1) holds. Then
,
, thus for any
,
,
. Since
, we have that
. So
satisfies property
. If (2) holds, then
,
. Hence
. It follows that
. For the converse, let
, and let
, where
, and
is inverse. We assume that
, then
, thus
. It follows that
is a Browder operator.
"". If there exists
such that
,
, suppose that
, then
. By
satisfies property
, we have that
is a Browder operator. Hence both
and
are Browder operators. It is a contradiction. Thus
,
.
If , then the fact that
satisfies property
implies that
,
. According to Lemma 1, we can get (1) holds. When
, we can assert that
. If not, suppose that
,
. Let
, then
. Since
satisfies property
, then
is a Browder operator, so is
, which is a contradiction. Therefore
. By Lemma 1 and its proof, we get that (2) holds.
Similarly, we can obtain the following conclusion. Let , for any
,
satisfies property
if and only if
,
and one of the following conditions holds:
(1) ;
(2) .
Corollary 3 Let , for any
,
satisfies property
if and only if
,
and the following conditions holds:
(1) satisfies property
;
(2) If , then
.
For property of operator functions, we have the following conclusions.
Lemma 6 Let , for any
,
satisfies property
if and only if one of the following conditions holds:
(1) ;
(2) .
Proof "". If
, then
. By Lemma 2, we can get that (1) holds.
If , we can assert that
. If not, suppose that
,
, let
, then
. Since
satisfies property
, we can get that
is a Browder operator. Then
is a Browder operator, which is a contradiction. Therefore
. Similarly, we have
in this situation. Suppose that
. If
, by
satisfies property
and
we have that
. The fact that
implies that
is a Browder operator. If
, we can assume that
. Since
, we have
. By
has property
, we can get that
is a Browder operator. Therefore (2) holds.
"". If condition (1) holds, then
,
,
. Then for any
,
. Hence
. Since
, we have that
. Therefore
satisfies property
.
If conditions (2) holds, then ,
,
. Hence
. Suppose that
. Let
, where
,
is invertible. We can assume that
, then
. Since
has property
, we get
. So
is a Browder operator. Therefore
satisfies property
.
By the proof of Lemma 6, we can get that:
Corollary 4 Let . For any
,
satisfies property
if and only if the following conditions holds:
(1) satisfies property
;
(2) If , then
.
Then we obtain the condition that the operator function satisfies both two properties.
Theorem 3 Let . For any
,
satisfies property
and property
if and only if
,
and:
(1) satisfies property
and property
;
(2) If , then
.
Proof "". According to Corollary 3 and Corollary 4, we know that we only need to prove (2). Suppose that
. If
, by Corollary 3 we know that
is a Browder operator. Suppose
. When
, by Corollary 4 we can get that
. When
, the fact that
implies
. Thus
. We also get that
is a Browder operator. The converse is obviously true. Hence (2) holds.
The sufficiency is easy to get from Corollary 3 and Corollary 4.
Corollary 5 Let . For any
,
satisfies property
and property
if and only if
,
and one of the following conditions holds:
(1) ;
(2) .
Proof "". If
, then
. Since
, by Theorem 1 and Remark 2 we can get that (1) holds. If
, the condition (2) hold.
"". According to Theorem 1 and Theorem 3, we know that for any
,
satisfies property
and property
.
Example 1 Let be defined by:
,
. Suppose that
. Then: (1)
satisfies property
and property
; (2) For any
,
; (3)
, and
.
Therefore by Theorem 3, we can get that for any ,
satisfies property
and property
.
References
- Djordjević D S. Operators obeying a-Weyl's theorem[J]. Publicationes Mathematicae Debrecen, 1999, 55(3/4): 283-298. [Google Scholar]
- Cao X H, Guo M Z, Meng B. Weyl spectra and Weyl's theorem[J]. Journal of Mathematical Analysis and Applications, 2003, 288(2): 758-767. [Google Scholar]
- Gupta A, Kumar A. Properties (BR) and (BgR) for bounded linear operators[J]. Rendiconti Del Circolo Matematico Di Palermo Series 2, 2020, 69(2): 601-611. [Google Scholar]
- Sun C H, Wang N, Cao X H. Topological uniform descent and judgement of a-Weyl's theorem [J]. Wuhan University Journal of Natural Sciences, 2023, 28(5): 392-398. [Google Scholar]
- Aiena P, Triolo S. Weyl-type theorems on Banach spaces under compact perturbations[J]. Mediterranean Journal of Mathematics, 2018, 15(3): 126. [Google Scholar]
- Wu X F, Huang J J, Chen A. Weylness of 2 × 2 operator matrices[J]. Mathematische Nachrichten, 2018, 291(1): 187-203. [Google Scholar]
- Dong J, Cao X H, Dai L. On weyl's theorem for functions of operators[J]. Acta Mathematica Sinica, English Series, 2019, 35(8): 1367-1376. [CrossRef] [MathSciNet] [Google Scholar]
- Dai L, Yi J L. Property (ω) and Hypercyclic Property for Operators[J]. Wuhan University Journal of Natural Sciences, 2024, 29(6): 499-507. [Google Scholar]
- Zhu S, Li C G, Zhou T T. Weyl type theorems for functions of operators [J]. Glasgow Mathematical Journal, 2012, 54(3): 493-505. [Google Scholar]
- Berkani M, Kachad M. New Browder and weyl type theorems[J]. Bulletin of the Korean Mathematical Society, 2015, 52(2): 439-452. [CrossRef] [MathSciNet] [Google Scholar]
- Yang L L, Cao X H. Property (R) for functions of operators and its perturbations[J]. Mediterranean Journal of Mathematics, 2022, 19(1): 25. [Google Scholar]
-
Ren Y X, Jiang L N, Kong Y Y. Property
and topological uniform descent [J]. Bulletin of the Belgian Mathematical Society - Simon Stevin, 2022, 29(1): 1-17. [MathSciNet] [Google Scholar]
- Grabiner S. Uniform ascent and descent of bounded operators[J]. Journal of the Mathematical Society of Japan, 1982, 34(2): 317-337. [Google Scholar]
- Rakočević V. Semi-Browder operators and perturbations[J]. Studia Mathematica, 1997, 122(2): 131-137. [Google Scholar]
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